\(\dfrac{4^9\cdot36+64^4}{100\cdot16^4}=\dfrac{2^{20}\cdot3^2+2^{24}}{2^{18}\cdot5^2}=\dfrac{2^{20}\left(3^2+2^4\right)}{2^{18}\cdot5^2}=4\)

 ko bt

\(D=\dfrac{21^2.14^{126}}{126^{35}.5^6}=\dfrac{7^2.3^2.14^{126}}{14^{35}.9^{35}.5^6}=\dfrac{7^2.3^2.14^{91}}{3^{70}.5^6}\)

\(D=\dfrac{7^2.7^{91}.2^{91}}{3^{68}.5^6}=\dfrac{7^{93}.2^{91}}{3^{68}.5^6}\)

D = \(\dfrac{7^{93}.2^{91}}{3^{68}.5^6}\)

a) \(9^{21}.9^{33}=9^{21+33}=9^{54}\)

b) \(19^{11}.19.19=19^{11+1+1}=19^{13}\)

c) \(25^2.5^2.125=5^4.5^2.5^3=5^{4+2+3}=5^9\)

d) \(t^{2021}.t^2.\left(t^2\right)^2=t^{2021}.t^2.t^4=t^{2021+2+4}=t^{2027}\)

e) \(123^{14}:123^{13}=123^{14-13}=123\)

f) \(64^2:8^3=\left(8^2\right)^2:8^3=8^4:8^3=8^{4-3}=8=2^3\)

g) \(6^{10}:6^3:36=6^{10}:6^3:6^2=6^{10-3-2}=6^5\)

h) \(m^{20}:m^{10}.m^{10}=m^{20-10+10}=m^{20}\)

oke

Thế này à:

a, \(\frac{2^{13}+25}{2^{10}}\)

b, \(\frac{21^2.14.125}{35^5.6}\)

c,\(\frac{45^3.20^4.18^2}{180^5}\)

d, \(\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)

2 mũ 13 ta chia cho 2 mũ 10 ta có là 2 mũ 3 chuyển thành 8 rồi cộng cho 25 ta có là 33

\(27\cdot36+73\cdot99+27\cdot14-49\cdot7\)

\(=27\cdot\left(36+14\right)+73\cdot99-49\cdot7\)

\(=27\cdot50+6884=1350+6884=8234\)

\(\dfrac{5^6}{5^4}+2^3\cdot2^2-1^{2017}\)

\(=5^2+2^5-1\)

=25+32-1

=25+31

=56

a) (26-6)*(-4)+31*(-7-13)

=-80+-620

=-700

hacker 2k6

dài thế

dai the giai bao gio xong chac mua quyt nam sau moi giai xong

1. 2².3².5:2².3-3²=3.5-3²=15-9=6
2. 2.5²-2².3²:3²=2.(5²-2)=2.(25-2)=46

3. 3³.19-3³.12=3³.(19-12)=3³.7=189

4. 3.5²-16:2²=3.5²-2⁴:2²=3.25-4=75-4=71

2^(10 : 64 x 16) = 2^[(10 x 16) : 64] = 2^(160 : 64) = 2^25

2^(10 x 8) = 2^80     3^(5 : 27) = 3^(5/27)     5^(2 x 125) = 5^250     6^(6 : 36) = 6^(1/6)