a)  (a-b)-(c-b)-a=a-b-c+b-a=(a-a)+(b-b)-c=0+0-c=-c

1)

a) (a-b) - (c-b) - a= a - b - c + b - a = -c

b) -(300 - 400) + (300 - 400) + 100 = 100

2) a) 4x - 20 =  50 - ( 30 -3x)

        4x - 20 = 50 - 30 + 3x

        4x - 3x = 50 - 30 + 20= 40

        x          = 40

b) 100 - (-5x) = 40 - (-4x +10)

    100 + 5x    = 40 + 4x -10

    5x - 4x       = 40 - 10 -100

    x                = -70

c) (-50) + (-7x) = 100 - 8x

     -7x + 8x      = 100 + 50

      x                = 150

a, 12⋮\(x\) ; 21⋮\(x\) ⇒ \(x\) \(\in\)ƯC(12; 21)

     12 = 2².3;          21 = 3.7 ⇒   ƯCLN(12;21) = 3

   ⇒\(x\) \(\in\) Ư(3) = {1; 3} Vì  150 < \(x\) < 300 nên  \(x\) = \(\varnothing\)

b, 40 ⋮ \(x\);    45 \(⋮\) \(x\) và  700 ≤ \(x\) ≤ 800

   40\(⋮\) \(x\);    45\(⋮\) \(x\)  ⇒ \(x\) \(\in\) ƯC(40; 45) 

40 = 2³.5;          45 = 5.9 ⇒ ƯCLN(40; 45) = 5 

⇒  \(x\in\) Ư(5) = { 1; 5} vì  700 ≤  \(x\) ≤ 800 nên \(x=\varnothing\)

khó quá

a) 1,25 x 320 = 400

b) 456 x 800 = 364800

c) 0,4 x 75 = 30

Ta có : \(\frac{x}{4}=\frac{y}{7}\) 

\(\Rightarrow\frac{x^2}{16}=\frac{y^2}{49}=\frac{3x^2}{48}=\frac{4y^2}{196}=\frac{3x^2-4y^2}{48-196}=\frac{100}{-148}=-\frac{25}{37}\)

Thay vào là ra nhé !:D

Cái chỗ Nguyễn Quang Trung đúng ròi

\(\Rightarrow\hept{\begin{cases}\frac{x}{4}=-\frac{25}{37}\\\frac{y}{7}=-\frac{25}{37}\end{cases}}\Rightarrow\hept{\begin{cases}x=-\frac{100}{37}\\y=-\frac{175}{37}\end{cases}}\)

a) x/-3=y/-7=2x/-6=4y/-28=2x+4y/(-6)+(-28)= 68/-34=-2

Vậy x/-3 = -2 => x=(-2)x(-3)=6

       y/-7= -2 => y=(-2)x(-7)=14

      nhớ chọn nhé

a) \(\dfrac{x}{2}=\dfrac{y}{5}=\dfrac{z}{7};x+y+z=56\)

\(\dfrac{x}{2}=\dfrac{y}{5}=\dfrac{z}{7}=\dfrac{x+y+z}{2+5+7}=\dfrac{56}{14}=4\)

\(\Rightarrow\left\{{}\begin{matrix}x=4.2=8\\y=4.5=20\\z=4.7=28\end{matrix}\right.\)

b) \(\dfrac{x}{1,1}=\dfrac{y}{1,3}=\dfrac{z}{1,4}\left(1\right);2x-y=5,5\)

\(\left(1\right)\Rightarrow\dfrac{2x-y}{1,1.2-1,3}=\dfrac{5,5}{0,9}\)

\(\Rightarrow\left\{{}\begin{matrix}x=1,1.\dfrac{5,5}{0,9}=\dfrac{6,05}{0,9}\\y=1,3.\dfrac{5,5}{0,9}=\dfrac{7,15}{0,9}\\z=\dfrac{1,4}{1,1}.x=\dfrac{1,4}{1,1}.\dfrac{6,05}{0,9}=\dfrac{8,47}{0,99}\end{matrix}\right.\)

d) \(\dfrac{x}{2}=\dfrac{x}{3}=\dfrac{z}{5};xyz=-30\)

\(\dfrac{x}{2}=\dfrac{x}{3}=\dfrac{z}{5}=\dfrac{xyz}{2.3.5}=\dfrac{-30}{30}=-1\)

\(\Rightarrow\left\{{}\begin{matrix}x=2.\left(-1\right)=-2\\y=3.\left(-1\right)=-3\\z=5.\left(-1\right)=-5\end{matrix}\right.\)

a) $\genfrac{}{}{0ex}{}{x}{2}=\genfrac{}{}{0ex}{}{y}{5}=\genfrac{}{}{0ex}{}{z}{7};x+y+z=56$

$\genfrac{}{}{0ex}{}{x}{2}=\genfrac{}{}{0ex}{}{y}{5}=\genfrac{}{}{0ex}{}{z}{7}=\genfrac{}{}{0ex}{}{x+y+z}{2+5+7}=\genfrac{}{}{0ex}{}{56}{14}=4$

$\Rightarrow \{\begin{array}{c}x=4.2=8\\ y=4.5=20\\ z=4.7=28\end{array}$

b) $\genfrac{}{}{0ex}{}{x}{1,1}=\genfrac{}{}{0ex}{}{y}{1,3}=\genfrac{}{}{0ex}{}{z}{1,4}\left(1\right);2x-y=5,5$

$\left(1\right)\Rightarrow \genfrac{}{}{0ex}{}{2x-y}{1,1.2-1,3}=\genfrac{}{}{0ex}{}{5,5}{0,9}$

$\Rightarrow \{\begin{array}{c}x=1,1.\genfrac{}{}{0ex}{}{5,5}{0,9}=\genfrac{}{}{0ex}{}{6,05}{0,9}\\ y=1,3.\genfrac{}{}{0ex}{}{5,5}{0,9}=\genfrac{}{}{0ex}{}{7,15}{0,9}\\ z=\genfrac{}{}{0ex}{}{1,4}{1,1}.x=\genfrac{}{}{0ex}{}{1,4}{1,1}.\genfrac{}{}{0ex}{}{6,05}{0,9}=\genfrac{}{}{0ex}{}{8,47}{0,99}\end{array}$

d) $\genfrac{}{}{0ex}{}{x}{2}=\genfrac{}{}{0ex}{}{x}{3}=\genfrac{}{}{0ex}{}{z}{5};xyz=-30$

$\genfrac{}{}{0ex}{}{x}{2}=\genfrac{}{}{0ex}{}{x}{3}=\genfrac{}{}{0ex}{}{z}{5}=\genfrac{}{}{0ex}{}{xyz}{\mathrm{2.3.5}}=\genfrac{}{}{0ex}{}{-30}{30}=-1$

$\Rightarrow \{\begin{array}{c}x=2.\left(-1\right)=-2\\ y=3.\left(-1\right)=-3\\ z=5.\left(-1\right)=-5\end{array}$
 

a) \(x-285\div35=5\times54\)

\(x-\dfrac{57}{7}=270\)

\(x=\dfrac{1947}{7}\)

b) \(\left(x+120\right)\div20=8\)

\(x+120=160\)

\(x=40\)

c) \(\left(x+5\right)\times3=300\)

\(x+5=100\)

\(x=95\)

d) \(\left(x+100\right)\times4=800\)

\(x+100=200\)

\(x=100\)

a) \(x-285:35=5x54\)

\(x-\dfrac{57}{7}=270\)

\(x=270+\dfrac{57}{7}=\dfrac{1890}{7}+\dfrac{57}{7}=\dfrac{1947}{7}\)

b) \(\left(x+20\right):20=8\)

\(\left(x+20\right)=8x20\)

\(x+20=160\)

\(x=160-20=140\)

c) \(\left(x+5\right)x3=300\)

\(x+5=300:3\)

\(x+5=100\)

\(x=100-5=95\)

d) \(\left(x+100\right)x4=800\)

\(x+100=800:4\)

\(x+100=200\)

\(x=200-100=100\)

ây trung

b. Đặt x-1/2 = y+3/4 = z-5/6  = k

=> x = 2k+1

     y = 4k -3

      z = 6k+5

5z-3x-4y=50 => 5(6k+5)-3(2k+1)-4(4k-3) = 50

                   =>30k+25-6k-3-16k+12 = 50

                   =>(30k-6k-16k)+(25-3+12) = 50

                   =>8k+34 = 50

                   =>8k = 16 

                   =>k = 2

nên x = 2.2+1 = 5

       y = 4.2-3 = 5 

       z = 6.2+5 = 17