Cho A = 1/2+3/2+(3/2)^2+................+(3/2)^2012; B=(3/2)^2013:2
Tính A - B
K
Khách
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T
1
NT
0
VM
6
6 tháng 4 2015
\(\frac{3}{2}.A=\frac{3}{4}+\left(\frac{3}{2}\right)^2+\left(\frac{3}{2}\right)^3+...+\left(\frac{3}{2}\right)^{2013}\)
\(\Rightarrow\frac{3}{2}.A-A=\frac{3}{4}+\left(\frac{3}{2}\right)^2+\left(\frac{3}{2}\right)^3+...+\left(\frac{3}{2}\right)^{2013}-\left(\frac{1}{2}+\frac{3}{2}+\left(\frac{3}{2}\right)^2+...+\left(\frac{3}{2}\right)^{2012}\right)\)
\(\Rightarrow\frac{1}{2}.A=\frac{3}{4}+\left(\frac{3}{2}\right)^{2013}-\frac{1}{2}-\frac{3}{2}=\left(\frac{3}{2}\right)^{2013}-\frac{5}{4}\Rightarrow A=2.\left(\frac{3}{2}\right)^{2013}-\frac{5}{2}\)
\(B-A=\frac{1}{2}.\left(\frac{3}{2}\right)^{2013}-2.\left(\frac{3}{2}\right)^{2013}+\frac{5}{2}=-\left(\frac{3}{2}\right)^{2014}+\frac{5}{2}\)
ND
0
A
0
NC
0
7 tháng 4 2017
c) Cho B = (1.2.3....2012) . ( 1 + \(\dfrac{1}{2}\) + \(\dfrac{1}{3}\) + ... + \(\dfrac{1}{2012}\) ) Chứng minh B chia hết cho 2013
B = (1.2.3....2012) . (1 + \(\dfrac{1}{2}\) + \(\dfrac{1}{3}\) + ...+ \(\dfrac{1}{2012}\) )
=(1.2.3...671...2012) . (1 + \(\dfrac{1}{2}\) + \(\dfrac{1}{3}\) + ... + \(\dfrac{1}{2012}\))
=(1.2.(3.671)...2012) . (1 + \(\dfrac{1}{2}\) +\(\dfrac{1}{3}\) + ... + \(\dfrac{1}{2012}\))
=(1.2.2013...2012) . (1 + \(\dfrac{1}{2}\) + \(\dfrac{1}{3}\) + ... + \(\dfrac{1}{2012}\))
Vậy B chia hết cho 2013
Đúng đấy, bạn cứ chép vào đi
BM
1
AH
Akai Haruma
Giáo viên
14 tháng 9
Lời giải:
Ta có:
\(A-\frac{1}{2}=\frac{3}{2}+(\frac{3}{2})^2+...+(\frac{3}{2})^{2012}\)
\(\frac{3}{2}(A-\frac{1}{2})=(\frac{3}{2})^2+(\frac{3}{2})^3+....+(\frac{3}{2})^{2013}\\ \Rightarrow \frac{3}{2}(A-\frac{1}{2})-(A-\frac{1}{2})=(\frac{3}{2})^{2013}-\frac{3}{2}\)
$\Rightarrow \frac{1}{2}(A-\frac{1}{2})=(\frac{3}{2})^{2013}-\frac{3}{2}$
$A-\frac{1}{2}=2(\frac{3}{2})^{2013}-3$
$A=2(\frac{3}{2})^{2013}-2,5$
$\Rightarrow A-B=2(\frac{3}{2})^{2013}-2,5-(\frac{3}{2})^{2013}:2$
$=\frac{3}{2}(\frac{3}{2})^{2013}-2,5=(\frac{3}{2})^{2014}-2,5$
Lời giải:
$A-\frac{1}{2}=\frac{3}{2}+(\frac{3}{2})^2+....+(\frac{3}{2})^{2012}$
$\frac{3}{2}(A-\frac{1}{2})=(\frac{3}{2})^2+(\frac{3}{2})^3+....+(\frac{3}{2})^{2013}$
$\Rightarrow \frac{3}{2}(A-\frac{1}{2}) - (A-\frac{1}{2})=(\frac{3}{2})^{2013}-\frac{3}{2}$
$\Rightarrow \frac{1}{2}(A-\frac{1}{2})=(\frac{3}{2})^{2013}-\frac{3}{2}$
$\Rightarrow A=2(\frac{3}{2})^{2013}-\frac{5}{2}$
$\Rightarrow A-B=2(\frac{3}{2})^{2013}-\frac{5}{2}- \frac{1}{2}.(\frac{3}{2})^{2013}$
$\Rightarrow A-B=\frac{3}{2}(\frac{3}{2})^{2013}-\frac{5}{2}=(\frac{3}{2})^{2014}-\frac{5}{2}$