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8 tháng 7 2016

(2x+1)^2-(x-1)^2

= (4x^2 + 4x +1) - (x^2 - 2x +1)

= 2x^2 + 6x

= 2x(x+3)

9(x+5)^2-(x-7)^2

= 9 (x^2 + 10x + 25) - (x^2 - 14x +49)

= 9x^2 + 90x + 225 - x^2 + 14x - 49

= 8x^2 + 104x + 176

= 8x^2 + 8 * 13x + 8 * 22

= 8(x^2 + 13x +22)

x^2-y^2-x+y

= (x^2 - y^2) - (x-y)

= (x-y) (x+y) - (x-y)

= (x-y) (x+y+1)

\(\dfrac{1}{x-y}-\dfrac{1}{x+y}+\dfrac{2x}{\left(x-y\right)\left(x+y\right)}\\ \dfrac{x+y}{\left(x-y\right)\left(x+y\right)}-\dfrac{x-y}{\left(x-y\right)\left(x+y\right)}+\dfrac{2x}{\left(x-y\right)\left(x+y\right)}\\ \dfrac{x+y-x+y+2x}{\left(x-y\right)\left(x+y\right)}\\ \dfrac{2x+2y}{\left(x-y\right)\left(x+y\right)}\\ \dfrac{2}{x-y}\)

2 tháng 1 2022

\(\dfrac{1}{x-y}+\dfrac{1}{x+y}+\dfrac{2x}{x^2-y^2}=\dfrac{x+y}{\left(x-y\right)\left(x+y\right)}+\dfrac{x-y}{\left(x-y\right)\left(x+y\right)}+\dfrac{2x}{\left(x-y\right)\left(x+y\right)}=\dfrac{4x}{\left(x-y\right)\left(x+y\right)}\)

1: \(x\left(x-1\right)+\left(1+x\right)^2\)

\(=x^2-x+x^2+2x+1\)

\(=2x^2+x+1\)

Đa thức này ko phân tích được nha bạn

2: \(\left(x+1\right)^2-3\left(x+1\right)\)

\(=\left(x+1\right)\cdot\left(x+1\right)-\left(x+1\right)\cdot3\)

\(=\left(x+1\right)\left(x+1-3\right)\)

\(=\left(x+1\right)\left(x-2\right)\)

3: \(2x\cdot\left(x-2\right)-\left(x-2\right)^2\)

\(=2x\left(x-2\right)-\left(x-2\right)\cdot\left(x-2\right)\)

\(=\left(x-2\right)\left(2x-x+2\right)\)

\(=\left(x-2\right)\left(x+2\right)\)

4: \(3x\left(x-1\right)^2-\left(1-x\right)^3\)

\(=3x\left(x-1\right)^2+\left(x-1\right)^3\)

\(=3x\left(x-1\right)^2+\left(x-1\right)^2\cdot\left(x-1\right)\)

\(=\left(x-1\right)^2\cdot\left(3x+x-1\right)\)

\(=\left(x-1\right)^2\cdot\left(4x-1\right)\)

5: \(3x\left(x+2\right)-5\left(x+2\right)^2\)

\(=\left(x+2\right)\cdot3x-\left(x+2\right)\cdot\left(5x+10\right)\)

\(=\left(x+2\right)\left(3x-5x-10\right)\)

\(=\left(-2x-10\right)\left(x+2\right)\)

\(=-2\left(x+5\right)\left(x+2\right)\)

6: \(4x\left(x-y\right)+3\left(y-x\right)^2\)

\(=4x\left(x-y\right)+3\left(x-y\right)^2\)

\(=\left(x-y\right)\cdot4x+\left(x-y\right)\left(3x-3y\right)\)

\(=\left(x-y\right)\cdot\left(4x+3x-3y\right)\)

\(=\left(x-y\right)\left(7x-3y\right)\)

4 tháng 12 2023

Cảm ơn nhiều

14 tháng 10 2020

đầu cắt moi :)))))

14 tháng 10 2020

11) \(3x\left(x-1\right)+5\left(1-x\right)=\left(3x-5\right)\left(x-1\right)\)

12) \(2\left(2x-1\right)+3\left(1-2x\right)=1-2x\)

13) \(10x\left(x-y\right)-8y\left(y-x\right)=2\left(x-y\right)\left(5x+4y\right)\)

14) \(3x\left(y+2\right)-3\left(y+2\right)=3\left(x-1\right)\left(y+2\right)\)

15) \(x^2-y^2-2x+2y\)

\(=\left(x-y\right)\left(x+y\right)-2\left(x-y\right)=\left(x-y\right)\left(x+y-2\right)\)

31 tháng 8 2021

( x + 3 )( x + 4 )( x + 5 )( x + 6 ) + 1 

= [ ( x + 3 )( x + 6 ) ][ ( x + 4 )( x + 5 ) ] + 1

= ( x2 + 9x + 18 )( x2 + 9x + 20 ) + 1

= ( x2 + 9x + 19 - 1 )( x2 + 9x + 19 + 1 ) 1 

= ( x2 + 9x + 19 )2 - 12 + 1 = ( x2 + 9x + 19 )2

31 tháng 8 2021

x2 - 2x( y + 2 ) + y2 + 4y + 4

= x2 - 2x( y + 2 ) + ( y + 2 )2

= ( x - y - 2 )2

18 tháng 10 2021

1.A

2.C

3.B

4.C

15 tháng 12 2021

a

c

b

c

17 tháng 7 2023

1) \(2\left(x-1\right)^3-\left(x-1\right)=\left(x-1\right)\left(2\left(x-1\right)^2-1\right)\)

2) \(y\left(x-2y\right)^2+xy^2\left(2y-x\right)=\left(2y-x\right)\left(2\left(2y-x\right)+1\right)=\left(2y-x\right)\left(4y-2x+1\right)\)

3) \(xy\left(x+y\right)-x-y=xy\left(x+y\right)-\left(x+y\right)=\left(x+y\right)\left(xy-1\right)\) (xem lại đề sửa -2x thành -x mới đúng)

4) \(xy\left(x-3y\right)-2x+6y=xy\left(x-3y\right)-2\left(x-3y\right)=\left(x-3y\right)\left(xy-2\right)\)

a) \(3x\left(x+1\right)^2-5x^2\left(x+1\right)+7\left(x+1\right)\)

\(=\left(x+1\right)\left[3x\left(x+1\right)-5x^2+7\right]\)

\(=\left(x+1\right)\left(3x^2+3x-5x^2+7\right)\)

\(=\left(x+1\right)\left(-2x^2+3x+7\right)\)

\(=-\left(x+1\right)\left(2x^2-3x-7\right)\)

b) \(\left(x+y\right)\left(2x-y\right)-\left(3x-y\right)\left(y-2x\right)\)

\(=\left(x+y\right)\left(2x-y\right)+\left(3x-y\right)\left(2x-y\right)\)

\(=\left(2x-y\right)\left(x+y+3x-y\right)\)

\(=4x\left(2x-y\right)\)

c) \(5u\left(u-v\right)^2+10u^2\left(v-u\right)^2\)

\(=5u\left(u-v\right)^2+10u^2\left(u-v\right)^2\)

\(=5u\left(u-v\right)^2\left(1+2u\right)\)

13 tháng 8 2021

Trả lời:

a, 3x ( x + 1 )2 - 5x2 ( x + 1 ) + 7 ( x + 1 )

= ( x + 1 )[ 3x ( x + 1 ) - 5x2 + 7 ]

= ( x + 1 )( 3x2 + 3x - 5x2 + 7 )

= ( x + 1 )( - 2x2 + 3x + 7 )

b, ( x + y )( 2x - y ) - ( 3x - y )( y - 2x )

= ( x + y )( 2x - y ) + ( 3x - y )( 2x - y )

= ( 2x - y )( x + y + 3x - y )

= 4x ( 2x - y )

c, 5u ( u - v )2 + 10u2 ( v - u )2 

= 5u ( u - v )2 + 10u2 ( u - v )2 

= 5u ( u - v )2( 1 + 2u )

3 tháng 10 2021

a) \(4x\left(a-b\right)+6xy\left(b-a\right)\)

\(=4x\left(a-b\right)-6xy\left(a-b\right)\)

\(=\left(4x-6xy\right)\left(a-b\right)\)

\(=2x\left(2-3y\right)\left(a-b\right)\)

3 tháng 10 2021

b) \(\left(6x+3\right)-\left(2x-5\right)\left(2x+1\right)\)

\(=3\left(2x+1\right)-\left(2x-5\right)\left(2x+1\right)\)

\(=\left(3-2x+5\right)\left(2x+1\right)\)

\(=\left(8-2x\right)\left(2x+1\right)\)

\(=2\left(4-x\right)\left(2x+1\right)\)