\(\frac{1}{3}-\frac{3}{5}+\frac{5}{7}-\frac{7}{9}+\frac{9}{11}-\frac{11}{13}+\frac{13}{15}+\frac{11}{13}-\frac{9}{11}+\frac{7}{9}-\frac{5}{7}+\frac{3}{5}\)

\(=\left(-\frac{3}{5}+\frac{3}{5}\right)+\left(\frac{5}{7}-\frac{5}{7}\right)+\left(-\frac{7}{9}+\frac{7}{9}\right)+\left(\frac{9}{11}-\frac{9}{11}\right)+\left(-\frac{11}{13}+\frac{11}{13}\right)+\left(\frac{1}{3}+\frac{13}{15}\right)\)

\(=\frac{1}{3}+\frac{13}{15}\)

\(=\frac{6}{5}\)

tính theo công thức bạn nhé

= 1/3 - 1/3 + 5/7 - 5/7 - 7/9 + 7/9 +9/11 - 9/11 -11/13 + 11/13 +13/15

= 0 + 0 - 0 + 0 -0 + 13/15

= 0 + 13/15

= 13/15

\(\frac{1}{3}-\frac{3}{5}+\frac{5}{7}-\frac{7}{9}+\frac{9}{11}-\frac{11}{13}+\frac{13}{15}+\frac{11}{13}-\frac{9}{11}+\frac{7}{9}-\frac{5}{7}+\frac{3}{5}-\frac{1}{3}\)

\(=\left(\frac{1}{3}-\frac{1}{3}\right)+\left(\frac{3}{5}-\frac{3}{5}\right)+\left(\frac{5}{7}-\frac{5}{7}\right)+\left(\frac{7}{9}-\frac{7}{9}\right)+\left(\frac{9}{11}-\frac{9}{11}\right)+\left(\frac{11}{13}-\frac{11}{13}\right)+\frac{13}{15}\)

\(=0+0+0+0+0+0+\frac{13}{15}\)

\(=\frac{13}{15}\)

1^3-3^5-(-3^5)+1^64-2^9-1^36+1^15

=1+(-3^5+3^5)+1-2^9-1+1

=2-2^9

=-510

= -59/105

k mình nha

k mình nha

\(A=\dfrac{1}{3}-\dfrac{3}{5}+\dfrac{5}{7}+\dfrac{7}{9}+\dfrac{9}{11}-\dfrac{11}{13}+\dfrac{13}{15}-\dfrac{9}{11}-\dfrac{7}{9}-\dfrac{5}{7}+\dfrac{3}{5}-\dfrac{1}{3}\left(+\dfrac{7}{9}\rightarrow-\dfrac{7}{9}\right)\)

\(\Rightarrow A=\dfrac{1}{3}-\dfrac{1}{3}-\dfrac{3}{5}+\dfrac{3}{5}+\dfrac{5}{7}-\dfrac{5}{7}+\dfrac{7}{9}-\dfrac{7}{9}+\dfrac{9}{11}-\dfrac{9}{11}-\dfrac{11}{13}+\dfrac{13}{15}\)

\(\Rightarrow A=-\dfrac{11}{13}+\dfrac{13}{15}\)

\(\Rightarrow A=\dfrac{-11.15+13.13}{13.15}\)

\(\Rightarrow A=\dfrac{-165+169}{195}=\dfrac{4}{195}\)

mik học lớp 5

Ta có : B=(1/5-1/5)-(3/7-3/7)+(5/9-5/9)-(2/11-2/11)+(7/13-7/13)-9/16

B=-9/16

\(\dfrac{1}{3}-\dfrac{3}{5}+\dfrac{5}{7}-\dfrac{7}{9}+\dfrac{9}{11}-\dfrac{11}{13}+\dfrac{13}{15}+\dfrac{11}{13}-\dfrac{9}{11}+\dfrac{7}{9}-\dfrac{5}{7}+\dfrac{3}{5}-\dfrac{1}{3}\)
\(=\left(\dfrac{1}{3}-\dfrac{1}{3}\right)-\left(\dfrac{3}{5}-\dfrac{3}{5}\right)+\left(\dfrac{5}{7}-\dfrac{5}{7}\right)-\left(\dfrac{7}{9}-\dfrac{7}{9}\right)+\left(\dfrac{9}{11}-\dfrac{9}{11}\right)-\left(\dfrac{11}{13}-\dfrac{11}{13}\right)+\dfrac{13}{15}\)
\(=\dfrac{13}{15}\)

$\genfrac{}{}{0ex}{}{1}{3}-\genfrac{}{}{0ex}{}{3}{5}+\genfrac{}{}{0ex}{}{5}{7}-\genfrac{}{}{0ex}{}{7}{9}+\genfrac{}{}{0ex}{}{9}{11}-\genfrac{}{}{0ex}{}{11}{13}+\genfrac{}{}{0ex}{}{13}{15}+\genfrac{}{}{0ex}{}{11}{13}-\genfrac{}{}{0ex}{}{9}{11}+\genfrac{}{}{0ex}{}{7}{9}-\genfrac{}{}{0ex}{}{5}{7}+\genfrac{}{}{0ex}{}{3}{5}-\genfrac{}{}{0ex}{}{1}{3}$
$=\left(\genfrac{}{}{0ex}{}{1}{3}-\genfrac{}{}{0ex}{}{1}{3}\right)-\left(\genfrac{}{}{0ex}{}{3}{5}-\genfrac{}{}{0ex}{}{3}{5}\right)+\left(\genfrac{}{}{0ex}{}{5}{7}-\genfrac{}{}{0ex}{}{5}{7}\right)-\left(\genfrac{}{}{0ex}{}{7}{9}-\genfrac{}{}{0ex}{}{7}{9}\right)+\left(\genfrac{}{}{0ex}{}{9}{11}-\genfrac{}{}{0ex}{}{9}{11}\right)-\left(\genfrac{}{}{0ex}{}{11}{13}-\genfrac{}{}{0ex}{}{11}{13}\right)+\genfrac{}{}{0ex}{}{13}{15}$
$=\genfrac{}{}{0ex}{}{13}{15}$