\(A=-2x^2y\)

1A

2B

3C

4D

4A

Kết quả thu gọn là: \(A=3x^2y^4\)

`a, A= 4xy -xy-2xy`

`= (4-1-2)xy`

`= xy`

Thay `x=2;y=3`

Ta có : `xy=2*3=6`

`b, B= x^2 y -7x^2y-4x^2y`

`=(1-7-4)x^2y`

`= -10x^2y`

Thay `x=2;y=3`

Ta có : `-10x^2y=-10*2^2 *3= -10*4*3=-40*3=-120`

`c, C=10x^2y -x^2y-7x^2y`

`=(10-1-7)x^2y`

`= 2x^2y`

Thay `x=2;y=3`

Ta có : `2x^2y=2*2^2 *3= 2*4*3=8*3=24`

`d,D=5x^2y^2-12x^2y^2+8x^2y^2`

`= (5-12+8)x^2y^2`

`=x^2y^2`

Thay `x=2;y=3`

ta có : `x^2y^2=2^2 *3^2= 4* 9=36`

có chỗ nào bn đọc ko rõ thì ns mik nha, để mik gõ ra cho bn rõ hơn

a: \(M=\dfrac{2}{3}\cdot\dfrac{3}{4}\cdot x^3\cdot xy^2\cdot z^2=\dfrac{1}{2}x^4y^2z^2\)

Hệ số là 1/2

Biến là \(x^4;y^2;z^2\)

b: \(N=x^2y\left(4+5-3\right)=6x^2y=6\cdot2^2\cdot\left(-1\right)=-24\)

Cảm ơn đã giải cho mình 

a: Ta có: \(\left(8x^3-4x^2\right):4x-\left(4x^2-5x\right):2x+\left(2x\right)^2\)

\(=2x^2-x-2x+\dfrac{5}{2}+4x^2\)

\(=6x^2-3x+\dfrac{5}{2}\)

b: Ta có: \(\left(3x^3-x^2y\right):x^2-\left(xy^2+x^2y\right):xy+2x\left(x-1\right)\)

\(=3x-y-y-x+2x^2-2x\)

\(=2x^2-2y\)

a: Ta có: \(x^2-4x\left(3x-4\right)+7x-5\)

\(=x^2-12x^2+16x+7x-5\)

\(=-11x^2+23x-5\)

b: Ta có: \(7x\left(x^2-5\right)-3x^2y\left(xy-6y^2\right)\)

\(=7x^3-35x-3x^3y^2+18x^2y^3\)

c: Ta có: \(\left(5x+4\right)\left(2x-7\right)\)

\(=10x^2-35x+8x-28\)

\(=10x^2-27x-28\)

\(a.\) \(A=\left(15x+2y\right)-\left[\left(2x+3\right)-\left(5x+y\right)\right]\)

\(A=15x+2y-2x-3+5x+y\)

\(A=\left(15x-2x+5x\right)+\left(2y+y\right)-3\)

\(A=18x+3y-3\)

\(A=3\left(6x+y-1\right)\)

\(b.\) \(B=-\left(12x+3y\right)+\left(5x-2y\right)-\left[13x+\left(2y-5\right)\right]\)

\(B=-12x-3y+5x-2y-13x-2y+5\)

\(B=-\left(12x-5x+13x\right)-\left(3y+2y+2y\right)+5 \)

\(B=-20x-7y+5\)

\(x^2y+y^2x-2xz+2xy^2\)-\(5x^2y\)

=\(\left(x^2y-5x^2y\right)+\)\(y^2x\)-2xz+\(2xy^2\)

=-4\(x^2y\)+\(y^2x\)-2xz+\(2xy^2\)