p=12342 x34566+23453

     12342 x(34566+1)+11111

p=12342 x34566+23453

    12342 x34566+12342 x1+11111

p=23453

   12342+11111

p=23453

    23453

p=1

12342+23453/11111

=> P= 23453/11111

P= 12342x34566+23453/12342x(34566+1)+1111

P=12342+34566+23453

12342x34566+12342+1111

P=12342+34566+23453/12342+34566+23453

P=1

12342 - 19785 = - 7443

9752 x 49889 = 486 517 528

12342 - 19785 = -7443

9752 x 49889 = 486517528

\(a,\frac{12345}{12342}=1+\frac{3}{12342}\)

    \(\frac{23457}{23455}=1+\frac{2}{23455}\)

Vì \(\frac{3}{12342}>\frac{2}{23455}\Rightarrow\frac{12345}{12342}>\frac{23457}{23455}\)

\(b,\frac{149}{150}=1-\frac{1}{150}\)

        \(\frac{4}{11}=1-\frac{7}{11}\)

Vì \(\frac{1}{150}< \frac{7}{11}\Rightarrow\frac{149}{150}>\frac{4}{11}\)

12345/12342 = 1 + 3/12342 = 1 + 1/ 4114 = 1 + 2/8228

23457/23455 = 1 + 2/23455

Có 1 + 2/8228 > 1 + 2/23455 => 12345/12342 > 23457/23455.

149/450 < 150/450 = 1/3

4/11 > 4/12 = 1/3

Vậy 149/450 < 4/11

```pascal
program TimSoNguyenTrongSoN;
uses crt;

procedure TimSoNguyenTrongSoN(n: integer);
var
n_str: string;
so_nguyen_xuat_hien: array of integer;
temp: string;
i, j, so: integer;
begin
n_str := IntToStr(n);
SetLength(so_nguyen_xuat_hien, 0);

for i := 1 to Length(n_str) do
begin
temp := '';
for j := i to Length(n_str) do
begin
temp := temp + n_str[j];
if TryStrToInt(temp, so) then
begin
SetLength(so_nguyen_xuat_hien, Length(so_nguyen_xuat_hien) + 1);
so_nguyen_xuat_hien[Length(so_nguyen_xuat_hien) - 1] := so;
end;
end;
end;

writeln('Cac so nguyen xuat hien trong so ', n, ' la:');
for i := 0 to Length(so_nguyen_xuat_hien) - 1 do
begin
writeln(so_nguyen_xuat_hien[i]);
end;
end;

var
n: integer;
begin
clrscr;
write('Nhap vao so n: ');
readln(n);
TimSoNguyenTrongSoN(n);
readln;
end.
```

sao mình ko chạy được v bạn

43534 + 23143 = 66677

423 + 112 = 535

4545 + 213 = 4758

356465 + 123 = 356588

12342 + 64 = 12406

hok tốt !!!

43534+23143=66686

423+112=535

4545+213=4758

356465+123=356579

12342+64=12406

kb voi mk nha

a: \(\dfrac{12345}{12342}=1+\dfrac{3}{12342}\)

\(\dfrac{23457}{23454}=1+\dfrac{3}{23454}\)

mà 3/12342>3/23454

nên \(\dfrac{12345}{12342}>\dfrac{23457}{23454}\)

b: \(\dfrac{149}{450}< \dfrac{1}{3}=\dfrac{4}{12}< \dfrac{4}{11}\)