B

B

SĐL: 

 P : AaBb   (cao,tròn) x           AaBb(cao, tròn)

 G  AB, Ab,aB, ab                      AB, Ab, aB, ab

 F1: 1AABB : 2 AaBB: 2 AABb : 4 AaBb

     1 AAbb : 2 Aabb

     1 aaBB : 2 aaBb

     1 aabb

TLKG: 9A_B_ : 3A_bb: 3aaB_ : 1 aabb

TLKH : 9 cao, tròn  : 3 cao, bầu dục : 3 thấp, tròn : 1 thấp, bầu dục

- Tỉ lệ thân cao, bầu dục dị hợp trong tổng số thân cao, bầu dục là 2/3

- Tỉ lệ thấp, tròn dị hợp trong tổng số thấp, tròn là 2/3

1 ........will be rebuilt  next year

2 .......met each other for ten years

3 ..... of Liberty was presented to the United State by France in 1876

4 ........ too high for the children to reach

5 ...... on animals should be stopped

6 ..... her child not to cry

7 .......mind if I turn on the television?

8 ......... rather you didn't use the office phone

9.........asked the students not to throw things away

10 ........ suggest that we go to the movie now

11 ....goes to Ho Chi Minh City in order to visit his friend

12 smoked

13 ..... interesting to learn ENglish

14She shows me where to get the tickets

15 The boy who is talking to Lan is my classmate

16 The wall has been painted white

17 .......told to go away

18 ...... will be looked after carefully

19 She asked me if I was good at Maths

20 They said that they had attended course of cooking

---------------------------------------------------------------------------------

1 without

2 for

-Tham khảo c2 bV

3 at - on

4 of - from

-Tham khảo c4 bV

5 to - on

6 of

7 among

8 of

9 into

10 for

Bài 1:

\(A=3+3^2+...+3^{100}\)

=>\(3\cdot A=3^2+3^3+...+3^{101}\)

=>\(3A-A=3^2+3^3+...+3^{101}-3-3^2-...-3^{100}\)

=>\(2A=3^{101}-3\)

=>\(2A+3=3^{101}\)

mà \(2A+3=3^n\)

nên n=101

 Bài 2:

a: \(M=3+3^2+3^3+3^4+...+3^{100}\)

\(=\left(3+3^2\right)+\left(3^3+3^4\right)+...+\left(3^{99}+3^{100}\right)\)

\(=\left(3+3^2\right)+3^2\left(3+3^2\right)+...+3^{98}\left(3+3^2\right)\)

\(=12\left(1+3^2+...+3^{98}\right)⋮12\)

=>\(M=4\cdot3\cdot\left(1+3^2+...+3^{98}\right)⋮4\)

b: \(M=3+3^2+...+3^{100}\)

=>\(3M=3^2+3^3+...+3^{101}\)

=>\(3M-M=3^2+3^3+...+3^{101}-3-3^2-...-3^{100}\)

=>\(2M=3^{101}-3\)

=>\(2M+3=3^{101}\)

=>n=101

Bài 4:

a) 2x + 7 ⋮ x + 2

⇒ 2x + 4 + 3 ⋮ x + 2

⇒ 2(x + 2) + 3 ⋮ x + 2

⇒ 3 ⋮ x + 2

⇒ x + 2 ∈ Ư(3) = {1; -1; 3; -3}

⇒ x ∈ {-1; -3; 1; -5} 

b) 2x + 7 ⋮ x - 3

⇒ 2x - 6 + 13 ⋮ x - 3

⇒ 2(x - 3) + 13 ⋮ x - 3

⇒ 13 ⋮ x - 3

⇒ x - 3 ∈ Ư(13) = {1; -1; 13; -13}

⇒ x ∈ {4; 2; 16; -10}

Bài 6:

a: \(3x-13⋮x+3\)

=>\(3x+9-22⋮x+3\)

=>\(-22⋮x+3\)

=>\(x+3\in\left\{1;-1;2;-2;11;-11;22;-22\right\}\)

=>\(x\in\left\{-2;-4;-1;-5;8;-14;19;-25\right\}\)

b: \(2x+24⋮x-4\)

=>\(2x-8+32⋮x-4\)

=>\(32⋮x-4\)

=>\(x-4\in\left\{1;-1;2;-2;4;-4;8;-8;16;-16;32;-32\right\}\)

=>\(x\in\left\{5;3;6;2;8;0;12;-4;20;-12;36;-28\right\}\)

Bài 5:

a: \(4x+3⋮x-2\)

=>\(4x-8+11⋮x-2\)

=>\(11⋮x-2\)

=>\(x-2\in\left\{1;-1;11;-11\right\}\)

=>\(x\in\left\{3;1;13;-9\right\}\)

b: \(2x+7⋮x-3\)

=>\(2x-6+13⋮x-3\)

=>\(13⋮x-3\)

=>\(x-3\in\left\{1;-1;13;-13\right\}\)

=>\(x\in\left\{4;2;16;-10\right\}\)

Bài 4:

a: \(2x+7⋮x+2\)

=>\(2x+4+3⋮x+2\)

=>\(3⋮x+2\)

=>\(x+2\in\left\{1;-1;3;-3\right\}\)

=>\(x\in\left\{-1;-3;1;-5\right\}\)

b: \(2x+7⋮x-3\)

=>\(2x-6+13⋮x-3\)

=>\(13⋮x-3\)

=>\(x-3\in\left\{1;-1;13;-13\right\}\)

=>\(x\in\left\{4;2;16;-10\right\}\)

1 relaxed

2 disastrous

3 inquiry

4 applications

5 shaped

6 examined

7 Careful

8 impressed

25. relaxed

26. disastrous

27. inquiry

28. applications

29. shaped

30. examined

31. Careful

32. impressed