a,(5x-1)⁶=3⁶

5x-1=3

x=4/5

b,(2x+1)³=0,1³

2x+1=0,1

x=-0,45

c,(2x-3)⁴=(2x-3)⁴(2x-3)²

(2x-3)²=0

2x-3=0

x=3/2

d,(2x+1)⁵=(2x+1)⁵(2x+1)²⁰⁰⁵

(2x+1)²⁰⁰⁵=0

2x+1=0

x=-1/2

a)\(\orbr{\begin{cases}5x-1=3\\5x-1=-3\end{cases}}\Leftrightarrow\orbr{\begin{cases}5x=4\\5x=-2\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{4}{5}\\x=\frac{-2}{5}\end{cases}}\)

b) 2x+1=-0,1 <=> 2x=-1,1=>x=-0,55

c) (2x-3)⁴ .[1-(2x-3)² ]=0

do (2x-3)⁴ lớn hơn 0 nên 1-(2x-3)²=0=>(2x-3)²=1=>2x-3=1=>2x=4=>x=2

d) tương tự câu c)

a) 5x-1=3 hoặc 5x-1=-3 sau đo tính ra

\(\left(2x+1\right)^3=729\)

\(\Leftrightarrow\)\(\left(2x+1\right)^3=9^3\)

\(\Leftrightarrow\)\(2x+1=9\)

\(\Leftrightarrow\)\(2x=8\)

\(\Leftrightarrow\)\(x=4\)

Vậy...

\(\left(2x+1\right)^3=729\)

\(\Rightarrow2x+1=9\)

\(\Rightarrow2x=8\)

\(\Rightarrow x=4\)

a: A=2^0+2^1+...+2^9

2A=2+2^2+...+2^10

=>A=2^10-1

b: B=1+3+3^2+...+3^6

=>3B=3+3^2+...+3^7

=>2B=3^7-1

=>\(B=\dfrac{3^7-1}{2}\)

a,  3 x + 1 : 3 4 = 81

3 x - 3 = 3 4

x – 3 = 4

x = 7

Vậy x = 7

b,  3 x + 3 . 3 x + 1 = 729

3 2 x + 4 = 3 6

2x + 4 = 6

x = 1

Vậy x = 1

c,  2 x + 3 . 2 x = 128

2 2 x + 3 = 2 7

2x + 3 = 7

x = 2

Vậy x = 2

d,  23 + 3 x = 5 6 : 5 3

23 + 3 x = 5 3

23 + 3x = 125

3x = 102

x = 34

Vậy x = 34

e,  2 x + 2 x + 4 = 272

2 x + 2 x . 2 4 = 272

2 x ( 1 + 2 4 ) = 272

2 x . 17 = 272

2 x = 16

2 x = 2 4

x = 4

Vậy x = 4

(2x+1)³=729
=>2x+1=\(\sqrt[3]{729}\)
=>2x+1=9
=>2x=8
=>x=4

tick đúng nha

\(3^{2x}=\left(3^2\right)^x\)\(\Rightarrow9^x=729\)\(\Rightarrow x=3\)

\(3^{2x}\) = 729

<=>\(9^x\) = 729

<=>9 . 9 .9 = 729

<=>  \(9^3\) = 729

<=>   x        =3

Vay :x=3

3^x+3*3^2x-1*3^x=729

\(\Rightarrow3^{x+3+2x-1+x}=3^6\)

\(\Rightarrow3^{4x+2}=3^6\)

\(\Rightarrow4x+2=6\)

\(\Rightarrow4x=4\)

\(\Rightarrow x=1\)