[ { 4 x X + 28 } x 3 + 55 ] : 5 = 35

[ { 4 x X + 28 } x 3 + 55 ] = 35 x 5

[ { 4 x X + 28 } x 3 + 55 ] = 175

{ 4 x X + 28 } x 3 = 175 - 55

{ 4 x X + 28 } x 3 = 120

4 x X + 28 = 120 : 3

4 x X + 28 = 40

4 x X = 40 - 28

4 x X = 12

X = 12 : 4

X = 3

(4*X+28)*3+55=35*5

=>(4*X+28)*3+55=175

=>(4*X+28)*3=120

=>4*X+28=40

=>4*X=12

=>X=3
 

(4*x+28)*(3+55) :5=35

         (4*x+28)*58 =35.5

             (4*x+28)*58= 175

                    4*x+28=\(\frac{175}{58}\)

                   4 * x = \(\frac{175}{58}-28\)

                  4 * x = \(\frac{-1449}{58}\)

                      x = \(\frac{-1449}{58}:4=\frac{-1449}{232}\)

{ ( 4 . x + 28 ) . 3 + 55 }      = 35 . 5

{ ( 4 . x + 28 ) . 3 + 55 }      = 175

{ ( 4 . x + 28 ) . 3 }              = 175 - 55

{ ( 4 . x + 28 ) . 3 }              = 120

{ ( 4 . x + 28 ) }                   = 120 : 3

     4 . x + 28                       = 40

     4 . x                               = 40 - 28

     4 . x                               = 12

          x                               = 12 : 4

          x                               = 3

dương bạn lớp mấy ở đâu học trường nào

a) \(128-3\left(x+4\right)=23\)

\(\Rightarrow3\left(x+4\right)=128-23\)

\(\Rightarrow3\left(x+4\right)=105\)

\(\Rightarrow x+4=35\)

\(\Rightarrow x=35-4\)

\(\Rightarrow x=31\)

b) \(\left[\left(4x+28\right)\cdot3+55\right]:5=35\)

\(\Rightarrow\left(4x+28\right)\cdot3+55=35\cdot5\)

\(\Rightarrow\left(4x+28\right)\cdot3+55=175\)

\(\Rightarrow\left(4x+28\right)\cdot3=120\)

\(\Rightarrow4x+28=40\)

\(\Rightarrow4x=12\)

\(\Rightarrow x=3\)

a, \(128-3\left(x+4\right)=23\)

\(=>3\left(x+4\right)=128-23\)

\(=>3\left(x+4\right)=105\)

\(=>x+4=105:3\)

\(=>x+4=35\)

\(=>x=35-4\)

\(=>x=31\)

b, \(\left[\left(4x+28\right).3+55\right]:5=35\)

\(=>\left(4x+28\right).3+55=35.5\)

\(=>\left(4x+28\right).3+55=175\)

\(=>\left(4x+28\right).3=175-55\)

\(=>\left(4x+28\right).3=120\)

\(=>4x+28=120:3\)

\(=>4x+28=40\)

\(=>4x=40-28\)

\(=>4x=12\)

\(=>x=12:4\)

\(=>x=3\)

\(#WendyDang\)

\(a,128-3.\left(x+4\right)=23\\ \Rightarrow3.\left(x+4\right)=105\\ \Rightarrow x+4=35\\ \Rightarrow x=31\\ b,\left[\left(4x+28\right).3+55\right]:5=35\\ \Rightarrow\left(4x+28\right).3+55=175\\ \Rightarrow4x+28.3=120\\ \Rightarrow4x+28=60\\ \Rightarrow4x=32\\ \Rightarrow x=8.\)

c) \(\left(12x-4^3\right).8^3=4.8^4\)

\(12x-64=4.8^4:8^3\)

\(12x-64=32\)

\(12x=32+64\)

\(12x=96\)

\(x=\dfrac{96}{12}\)

\(x=8\)

d) \(720:\left[41-\left(2x-5\right)\right]:5=35\)

\(720:\left(41-2x+5\right):5=35\)

\(720:\left(46-2x\right)=35.5\)

\(720:\left(46-2x\right)=175\)

\(46-2x=720:175\)

\(46-2x=\dfrac{144}{35}\)

\(2x=46-\dfrac{144}{35}\)

\(2x=\dfrac{1466}{35}\)

\(x=\dfrac{1466}{35}:2\)

\(x=\dfrac{733}{35}\)

a: =>3(x+4)=115

=>x+4=115/3

hay x=103/3

b: =>\(8^3\cdot\left(12x-64\right)=4\cdot8^4\)

\(\Leftrightarrow12x-64=32\)

=>12x=96

hay x=8

c: \(\Leftrightarrow\left(4x+28\right)\cdot23+55=175\)

=>(4x+28)x23=120

=>4x+28=120/23

=>4x=-524/23

hay x=-131/23

128 - 3(x + 4) = 23

=> 3(x + 4) = 128 - 23

=> 3(x + 4) = 105

=> x + 4 = 105 : 3

=> x + 4 = 35

=> x = 35 - 4

=> x = 31

Vậy x = 31

[(4x + 28) . 3 + 55] : 5 = 35

=> (4x + 28) . 3 + 55 = 35 . 5

=> (4x + 28) . 3 + 55 = 175

=> (4x + 28) . 3 = 175 - 55

=> (4x + 28) . 3 = 120

=> 4x + 28 = 120 : 3

=> 4x + 28 = 40

=> 4x = 40 - 28

=> 4x = 12

=> x = 12 : 4

=> x = 3

Vậy x = 3

1. 128 - 3.(x+4) = 23

             3.(x+4) = 5

                 x+4  = 5 : 3

                 x+4  = 5/3

                 x      = -7/3