câu 5 : Tính bằng cách thuận tiện nhất
12 x 3 + 12 x 8 - 12
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\(\dfrac{3}{12}\)x\(\dfrac{15}{6}\)x\(\dfrac{8}{5}\)
=> \(\dfrac{5}{8}\)x\(\dfrac{8}{5}\)
=>1
=125 x 12 +12 x 874 +12 x 1
=12x( 125 + 874 +1)
=12 x 1000
=12000
A) 5/4 x X = 3/8 + 5/12
5/4 x X = 19/24
X = 19/24 : 5/4
X = 19/30
vậy x =...
B, 3 x 7/10 + 7/10 x 5 + 2 x 7/10
= 7/10 x ( 3 + 5 + 2)
= 7/10 x 10
= 7
a, \(\dfrac{5\times11\times15\times18}{6\times15\times22\times10}\)
= \(\dfrac{5\times11\times15\times6\times3}{6\times15\times11\times2\times2\times5}\)
= \(\dfrac{5\times11\times15\times6}{5\times11\times15\times6}\) \(\times\) \(\dfrac{3}{2\times2}\)
= 1 \(\times\) \(\dfrac{3}{4}\)
= \(\dfrac{3}{4}\)
b, \(\dfrac{7}{12}\) \(\times\) \(\dfrac{3}{5}\) + \(\dfrac{3}{5}\) \(\times\) \(\dfrac{5}{12}\)
= \(\dfrac{3}{5}\) \(\times\) ( \(\dfrac{7}{12}+\dfrac{5}{12}\))
= \(\dfrac{3}{5}\) \(\times\) \(\dfrac{12}{12}\)
= \(\dfrac{3}{5}\) \(\times\) 1
= \(\dfrac{3}{5}\)
3/5 x 5 + 12 x 3/5 + 3 : 5/3
=3/5 x 5 + 12 x 3/5 + 3 x 3/5
= 3/5 x ( 5 + 12 + 3 )
= 3/5 x 20
= 12
a; 60 \(\times\) (\(\dfrac{7}{12}\) + \(\dfrac{4}{15}\))
= 60 \(\times\) \(\dfrac{7}{12}\) + 60 \(\times\) \(\dfrac{4}{15}\)
= 35 + 16
= 51
12 x 3 + 12 x 8 - 12
=12 x 3 + 12 x 8 - 12x1
=12x(3+8-1)
= 12 x 10
= 120
= 12 x ( 3 + 8 - 1)
= 12 x 10
= 120