\(\frac{12}{6}.\frac{4}{5}.4^5.4\)

\(=\left(\frac{12}{6}.\frac{4}{5}\right).4^5.4\)

\(=\frac{8}{5}.4^5.4\)

\(=\frac{8}{5}.1024.4\)

\(=1638,4.4\)

\(=6553.6\)

d: Ta có: \(\left(x+1\right)\left(x+2\right)\left(x+3\right)\left(x+4\right)=24\)

\(\Leftrightarrow\left(x^2+5x+4\right)\left(x^2+5x+6\right)-24=0\)

\(\Leftrightarrow x\left(x+5\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-5\end{matrix}\right.\)

\(\dfrac{4}{5}\times\dfrac{3}{7}\times\dfrac{4}{5}\times\dfrac{6}{7}\times\dfrac{4}{14}=\dfrac{4}{5}\times\dfrac{3}{7}+\dfrac{4}{5}\times\dfrac{6}{7}-\dfrac{4}{5}\times\dfrac{2}{7}=\dfrac{4}{5}\times\left(\dfrac{6}{7}+\dfrac{3}{7}-\dfrac{2}{7}\right)=\dfrac{4}{5}\)

(x+1)(x+2)(x+4)(x+5)=24

           x(1+2+4+5)  = 24

                      x12  = 24

                        x   = 24:12

                        x    = 2

Mik biết nhưng nhìn dài quá ngại làm

r lm bài nào bn

Ghi lại đề đi em, là \(14^2\) hay \(14x^2\)?

\(\dfrac{-1}{4}< \dfrac{x}{24}< \dfrac{-1}{6}\\ \dfrac{-6}{24}< \dfrac{x}{24}< \dfrac{-4}{24}\\ \Rightarrow x=-5\)

\(\dfrac{-1}{4}< \dfrac{x}{24}< \dfrac{-1}{6}\)
\(\Rightarrow\dfrac{-6}{24}< \dfrac{x}{24}< \dfrac{-4}{24}\)
\(\Rightarrow-6< x< -4\)
\(\Rightarrow x=-5\)