a)

Dễ thấy:

\(-\frac{1274}{2530}< 0< 1,2\)

\(\Rightarrow-\frac{1274}{2530}< 1,2\)

b)

Ta có :

\(25^{15}=\left(5^2\right)^{15}=5^{30}\)

\(8^{10}.3^{30}=\left(2^3\right)^{10}.3^{30}=2^{30}.3^{30}=6^{30}\)

Vì \(5^{30}< 6^{30}\)

=> \(25^{15}< 8^{10}.3^{30}\)

\(1)\) \(3^x+3^{x+1}+3^{x+2}=351\)

\(\Leftrightarrow\)\(3^x.1+3^x.3+3^x.3^2=351\)

\(\Leftrightarrow\)\(3^x\left(1+3+3^2\right)=351\)

\(\Leftrightarrow\)\(3^x.13=351\)

\(\Leftrightarrow\)\(3^x=\frac{351}{13}\)

\(\Leftrightarrow\)\(3^x=27\)

\(\Leftrightarrow\)\(3^x=3^3\)

\(\Leftrightarrow\)\(x=3\)

Vậy \(x=3\)

Chúc bạn học tốt ~ 

\(2)\) 

\(a)\) Ta có : 

\(25^{15}=\left(5^2\right)^{15}=5^{2.15}=5^{30}\)

\(8^{10}.3^{30}=\left(2^3\right)^{10}.3^{30}=2^{30}.3^{30}=\left(2.3\right)^{30}=6^{30}\)

Vì \(5^{30}< 6^{30}\) nên \(25^{15}< 8^{10}.3^{30}\)

Vậy \(25^{15}< 8^{10}.3^{30}\)

\(b)\) Ta có : 

\(\left(0,3\right)^{20}=\left[\left(0,3\right)^2\right]^{10}=\left(0,09\right)^{10}\)

Vì \(\left(0,1\right)^{10}>\left(0,09\right)^{10}\) nên \(\left(0,1\right)^{10}>\left(0,3\right)^{20}\)

Vậy \(\left(0,1\right)^{10}>\left(0,3\right)^{20}\)

Chúc bạn học tốt ~ 

Ta có: \(25^{15}=\left(5^2\right)^{15}=25^{30}\)

\(\left(-8\right)^{10}.3^{30}=8^{10}.3^{30}=\left(2^3\right)^{10}.3^{30}=2^{30}.3^{30}=\left(2.3\right)^{30}=6^{30}\)

Mà \(25^{30}>6^{30}\) nên \(25^{15}>\left(-8\right)^{10}.3^{30}\)

Vậy \(25^{15}>\left(-8\right)^{10}.3^{30}\)

ta có 25^15=(5^2)^15=5^30

(-8)^10 . 3^30=(2^3)^10 . 3^30=2^30 . 3^30=6^30

vì 5<6 nên 5^30<6^30

vậy 25^15 > (-8)^10 . 3^30

\(\frac{4^{15}}{7^{30}}=\frac{\left(2^2\right)^{15}}{7^{30}}=\frac{2^{30}}{7^{30}}=\left(\frac{2}{7}\right)^{30}\)

\(\frac{8^{10}.3^{30}}{7^{30}.4^{15}}=\frac{\left(2^3\right)^{10}.3^{30}}{7^{30}.\left(2^2\right)^{15}}=\frac{2^{30}.3^{30}}{7^{30}.2^{30}}=\frac{3^{30}}{7^{30}}=\left(\frac{3}{7}\right)^{30}\)

Vì \(\frac{2}{7}<\frac{3}{7}\Rightarrow\left(\frac{2}{7}\right)^{30}<\left(\frac{3}{7}\right)^{30}\)

Vậy \(\frac{4^{15}}{7^{30}}<\frac{8^{10}.3^{30}}{7^{30}.4^{15}}\).

\(\frac{15}{25}=\frac{3}{5}\)

vậy\(\frac{3}{5}< \frac{7}{5}\)

Ta có:\(\frac{15}{25}< 1\)\(;\)\(\frac{7}{5}>1\)

\(\Leftrightarrow\frac{15}{25}< \frac{7}{5}\)

Lightning Red

a)\(\frac{16}{20}=\frac{4}{5};\frac{9}{15}=\frac{3}{5}\)

Vì 4>3\(\Rightarrow\frac{4}{5}>\frac{3}{5}\) hay \(\frac{16}{20}>\frac{9}{15}\)

Vậy \(\frac{16}{20}>\frac{9}{15}\)

b) \(\frac{6}{8}=\frac{3}{4};\frac{3}{12}=\frac{1}{4}\)

Vì 3>1 \(\Rightarrow\frac{3}{4}>\frac{1}{4}\) hay \(\frac{6}{8}=\frac{3}{12}\)

Vậy \(\frac{6}{8}=\frac{3}{12}\)

c) \(\frac{15}{25}=\frac{3}{5};\frac{36}{45}=\frac{4}{5}\)

Vì 3<4 \(\Rightarrow\frac{3}{5}<\frac{4}{5}\) hay \(\frac{15}{25}<\frac{36}{45}\)

Vậy \(\frac{15}{25}<\frac{36}{45}\)

Neu ban nao dung thi minh tich cho nhe