\(\Leftrightarrow-3\left(x+3\right)=4\left(2x-1\right)\left(x\ne-3\right)\\ \Leftrightarrow-3x-9=8x-4\\ \Leftrightarrow11x=-5\Leftrightarrow x=-\dfrac{5}{11}\left(tm\right)\)

\(\Leftrightarrow8x-4+3x+9=0\)

=>11x=-5

hay x=-5/11

Ta có : \(A=\dfrac{x^2}{x+1}=\dfrac{x^2+2x+1-2x-1}{x+1}=\dfrac{\left(x+1\right)^2-2x-2+1}{x+1}\)

\(=\dfrac{\left(x+1\right)^2-2\left(x+1\right)+1}{x+1}=x+1-2+\dfrac{1}{x+1}=x-1+\dfrac{1}{x+1}\)

- Để A là số nguyên .

\(\Leftrightarrow x+1\inƯ_{\left(1\right)}\)

\(\Leftrightarrow x+1\in\left\{1;-1\right\}\)

\(\Leftrightarrow x\in\left\{0;-2\right\}\)

Vậy ...

\(x^{2010}.x^{2015}:x^{4020}=2^{10}:32\Rightarrow x^{2010+2015-4020}=2^{10}:2^5\Rightarrow x^5=2^5\Rightarrow x=2\)

\(780-\left(x-45\right):2=120\)

\(\Rightarrow\left(x-45\right):2=780-120\)

\(\Rightarrow\left(x-45\right):2=660\)

\(\Rightarrow x-45=660\times2\)

\(\Rightarrow x-45=1320\)

\(\Rightarrow x=1320+45\)

\(\Rightarrow x=1365\)

Vậy x = 1365

_Chúc bạn học tốt_

780 - (x - 45) : 2 = 120

=> (x - 45) : 2 = 780 - 120

=> (x - 45) : 2 = 660

=> x - 45 = 660 x 2

=> x - 45 = 1320

=> x = 1320 + 45

=> x = 1365

vậy_

=>5=1x5=-1x(-5)

=>x-1=1=1+1   =>x=2                       x-1=5=5+1  =>x=6

    y+2=5=5-2   =>y=3                       y+2=1=1-2  =>y=-1

    x-1=-1=-1+1 =>x=0                       x-1=-5=-5+1 =>x=-4

    y+2=-5=-5-2 =>y=-7                      y+2=-1=-1-2 =>x=-3

   tick cho mình mình tick lại cho

Th1 : x >= 2013

Th2 : x<2013

TuanMinhAms sai rồi bn

để  A lớn nhất \(\Rightarrow\left|x-2013\right|+2\) bé nhất

\(\left|x-2013\right|\ge0\Rightarrow\left|x-2013\right|+2\ge2\)

dấu "=" xảy ra khi \(\left|x-2013\right|=0\Rightarrow x=2013\)

khi đó GTLN của A = \(\frac{2026}{2}=1013\)

p/s: sai mk góp ý ko pk soi bài hay xúc phạm bn nha =]