thanks 

2:

a: \(A=\dfrac{x_1+x_2}{x_1x_2}=\dfrac{-6}{3}=-2\)

b: \(B=\dfrac{\left(x_1+x_2\right)^2-3x_1x_2}{1-x_1x_2}=\dfrac{36-3\cdot3}{1-3}=\dfrac{36-9}{-2}=-\dfrac{27}{2}\)

c: \(C=\sqrt{\left(x_1+x_2\right)^2-4x_1x_2}\)

\(=\sqrt{\left(-6\right)^2-4\cdot3}=2\sqrt{6}\)

d: \(D=\left(x_1+x_2\right)^3-3x_1x_2\left(x_1+x_2\right)-3x_1x_2\)

\(=\left(-6\right)^3-3\cdot3\cdot\left(-6\right)-3\cdot3\)

=261

chắc chữ không sáng thì làm thế nào

Chắc bạn bị mù thì làm thế nào

3 bài nào vậy bạn!?

V

1 an

2 some

3 some

4 some

5 some

6 a

7 some

8 some

VI

1 some

2 any

3 any

4 some

5 some

6 any

IX

1 as

2 as

3 as

4 from

5 as

1. an

2. some

3. some

4. some

5. a

6. some

7. some

VI,

1. some

2. any

3. any

4. some

5. some

6. any

VII,

1. as

2. as

3. as

4. from

5. as

8: \(x\sqrt{x}-1=\left(\sqrt{x}-1\right)\left(x+\sqrt{x}+1\right)\)

9: \(x\sqrt{x}+1=\left(\sqrt{x}+1\right)\left(x-\sqrt{x}+1\right)\)

10: \(x\sqrt{x}-y\sqrt{y}=\left(\sqrt{x}-\sqrt{y}\right)\left(x+\sqrt{xy}+y\right)\)

11: \(x\sqrt{x}+y\sqrt{y}=\left(\sqrt{x}+\sqrt{y}\right)\left(x-\sqrt{xy}+y\right)\)

các bn ơi...!!

à mình nhầm!!! đó là sách lớp 6 nha mn. ko phải lớp 5 đâu ạ. mong mn giúp !!!