a) \(5^2.3^5.\left(\frac{3}{5}\right)^2\)
\(=25.243.\frac{9}{25}\)
\(=6075.\frac{9}{25}\)
\(=2187\)
b) \(4.32.2^3.\frac{1}{16}\)
\(=4.32.8.\frac{1}{16}\)
\(=128.8.\frac{1}{16}\)
\(=1024.\frac{1}{16}\)
\(=64\)
c) \(\left(-2\frac{1}{3}\right)^2.\left(-\frac{1}{4}\right)^2\)
\(=\frac{49}{9}.\frac{1}{16}\)
\(=\frac{49}{144}\)
d) \(\frac{9^5.5^7}{45^7}\)
\(=\frac{9^5}{9^7}\)
\(=\frac{1}{9^2}=\frac{1}{81}\)
e) 10³ + 5.10² + 5³
= 1000 + 5.100 + 125
= 1005 . 12500
= 13505
P/s: Mũ not ngũ ^^

=81*(27+9^15):(3^5+3^32)

\(=\dfrac{3^4\cdot\left(3^3+3^{30}\right)}{3^5+3^{32}}=\dfrac{3^7\left(1+3^{27}\right)}{3^5\left(1+3^{27}\right)}=\dfrac{3^7}{3^5}=9\)

X-31=5 NGŨ 2

ngũ hay mũ thế bn?

\(=10^{12}\cdot10^{15}\cdot10^{12}=10^{39}\)

`@` `\text {Ans}`

`\downarrow`

`100^6 * 1000^5 * 10000^3`

`= (10^2)^6 * (10^3)^5 * (10^4)^3`

`= 10^12 * 10^15 * 10^12`

`=`\(10^{12+15+12}=10^{39}\)

a) 4^x  .  4² = 256

=> 4^x . 16 = 256 

=> 4^x = 256 : 16

=> 4^x = 16

=> 4^x = 4²

=> x = 2

b) x⁵ = 243 

=> x⁵ = 3⁵ 

=> x = 5

đề bài : 

a) \(4^x.4^2=256\)

b) \(x^5=243\)

                                                                      giải

a) \(4^x.4^2=256\)

\(4^{x+2}=4^4\)

= x + 2 = 4

x = 4 - 2

x = 2

b) \(x^5=243\)

\(x^5=3^5\)

=> x = 3

\(15^8.2^4=\left(15^2\right)^4.2^4=225^4.2^4=\left(225.2\right)^4=450^4\\ 27^5:32^3=\left(3^3\right)^5:\left(2^5\right)^3=3^{15}:2^{15}=\left(\dfrac{3}{2}\right)^{15}\)

Ngũ hay mũ bạn ???

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