3 x X + X = 20

(3+1) x X =20

4 x X = 20

X= 20:4

X=5

x = 5

\(\dfrac{3}{4}\times X-1=\dfrac{1}{2}\times X\\ \dfrac{3}{4}\times X-\dfrac{1}{2}\times X=1\\ \left(\dfrac{3}{4}-\dfrac{1}{2}\right)\times X=1\\ \dfrac{1}{4}\times X=1\\ X=1:\dfrac{1}{4}\\ X=4\)

\(\dfrac{3}{4}\times x-1=\dfrac{1}{2}\times x\\ \dfrac{3}{4}\times x-\dfrac{1}{2}\times x=1\\ x\times\left(\dfrac{3}{4}-\dfrac{1}{2}\right)=1\\ x\times\dfrac{1}{4}=1\\ x=1:\dfrac{1}{4}\\x=4\)

D=1/1.5+1/5.9+...+1/41.45

4D=4/1.5+4/5.9+...+4/41.45

4D=1-1/5+1/5-1/9+...+1/41-1/45

4D=1-1/45

D=44/45:4=11/45

\(A=\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{20}+...+\dfrac{1}{420}\\ \Rightarrow A=\dfrac{1}{2\times3}+\dfrac{1}{3\times4}+...+\dfrac{1}{20\times21}\\ \Rightarrow A=\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{20}-\dfrac{1}{21}\\\Rightarrow A=\dfrac{1}{2}-\dfrac{1}{20}=\dfrac{9}{20}\)

Sau khi rút gọn phải còn:

\(A=\dfrac{1}{2}-\dfrac{1}{21}\) (chứ anh)

\(A=\dfrac{19}{42}\)

\(X+X:0,5=27\)

\(\Rightarrow X\left(1+\dfrac{1}{0,5}\right)=27\)

\(\Rightarrow X\left(1+2\right)=27\)

\(\Rightarrow3X=27\Rightarrow X=27:3=9\)

bằng 9 nhaa

\(\dfrac{4}{5}+\dfrac{19}{18}-\dfrac{1}{2}+\dfrac{1}{5}-\dfrac{10}{8}\)

\(=\left(\dfrac{4}{5}+\dfrac{1}{5}\right)-\left(\dfrac{4}{8}+\dfrac{10}{8}\right)+\dfrac{19}{18}\)

\(=\dfrac{5}{5}-\dfrac{14}{8}+\dfrac{19}{18}\)

\(=1-\dfrac{7}{4}+\dfrac{19}{18}\)

\(=-\dfrac{3}{4}+\dfrac{19}{18}=\dfrac{11}{36}\)

\(\dfrac{4}{5}+\dfrac{19}{18}-\dfrac{1}{2}+\dfrac{1}{5}-\dfrac{10}{8}=\dfrac{4}{5}+\dfrac{19}{18}-\dfrac{1}{2}+\dfrac{1}{5}-\dfrac{5}{4}=\left(\dfrac{4}{5}+\dfrac{1}{5}\right)+\left(\dfrac{19}{18}-\dfrac{1}{2}\right)-\dfrac{5}{4}=1+\dfrac{5}{9}-\dfrac{5}{4}=\dfrac{36}{36}+\dfrac{20}{36}-\dfrac{45}{36}=\dfrac{11}{36}\)

\(\left(x+1\right)^2=\left(x+1\right)^4\)

\(\Rightarrow\left(x+1\right)^4-\left(x+1\right)^2=0\)

\(\Rightarrow\left(x+1\right)^2\left[\left(x+1\right)^2-1\right]=0\)

\(\Rightarrow\orbr{\begin{cases}\left(x+1\right)^2=0\\\left(x+1\right)^2-1=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x+1=0\\\left(x+1\right)^2=1\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=-1\\x+1=\pm1\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=-1\\x=0\text{ or }x=-2\end{cases}}\)