Cho H = 2+22+23+.........+260
Hãy chứng tỏ H chia hêt cho 3, 7 và 15
K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Những câu hỏi liên quan
R
2
HV
5 tháng 10 2021
A= (2+22)+(23+24)+...+(259+260)
A=2.(1+2)+23.(1+2)+...+259.(1+2)
A=2.3+23.3+...+259.3
A=3.(2+23+...+259)
Vì 3 chia hết cho 3 => 3.(2+23+...+259) chia hết cho 3
=>A chia hết cho 3
A= (2+22+23)+...+(258+259+260)
A=2.(1+2+22)+...+258.(1+2+22)
A=2.7+...+258.7
A=7.(2+...+258)
Vì 7 chia hết cho 7 =>7.(2+...+258) chia hết cho 7
CHIA HẾT CHO 3 :
A= (2+22)+(23+24)+...+(259+260)
A=2.(1+2)+23.(1+2)+...+259.(1+2)
A=2.3+23.3+...+259.3
A=3.(2+23+...+259)
Vì 3 chia hết cho 3 => 3.(2+23+...+259) chia hết cho 3
=>A chia hết cho 3
AH
Akai Haruma
Giáo viên
29 tháng 10 2023
Lời giải:
$A=(2+2^2+2^3)+(2^4+2^5+2^6)+....+(2^{58}+2^{59}+2^{60})$
$=2(1+2+2^2)+2^4(1+2+2^2)+....+2^{58}(1+2+2^2)$
$=(1+2+2^2)(2+2^4+....+2^{58})$
$=7(2+2^4+....+2^{58})\vdots 7$.
29 tháng 10 2023
A = 2+22+23+...+260
A = 2.(1+2+22) + 24.(1+2+22) + ... + 258.(1+2+22)
A = 2.7+24.7+...+258.7
A= 7. (2+24+...+258) chia hết cho 7
--> A chia hết cho 7 (ĐPCM)
21 tháng 10 2023
a: \(G=8^8+2^{20}\)
\(=2^{24}+2^{20}\)
\(=2^{20}\left(2^4+1\right)=2^{20}\cdot17⋮17\)
b: Sửa đề: \(H=2+2^2+2^3+...+2^{60}\)
\(=2\left(1+2\right)+2^3\left(1+2\right)+...+2^{59}\left(1+2\right)\)
\(=3\left(2+2^3+...+2^{59}\right)⋮3\)
\(H=2+2^2+2^3+...+2^{60}\)
\(=2\left(1+2+2^2\right)+2^4\left(1+2+2^2\right)+...+2^{58}\left(1+2+2^2\right)\)
\(=7\left(2+2^4+...+2^{58}\right)⋮7\)
\(H=2+2^2+2^3+...+2^{60}\)
\(=\left(2+2^2+2^3+2^4\right)+...+\left(2^{57}+2^{58}+2^{59}+2^{60}\right)\)
\(=2\left(1+2+2^2+2^3\right)+...+2^{57}\left(1+2+2^2+2^3\right)\)
\(=15\left(2+2^5+...+2^{57}\right)⋮15\)
c: \(E=\left(1+3+3^2\right)+3^3\left(1+3+3^2\right)+...+3^{1989}\left(1+3+3^2\right)\)
\(=13\left(1+3^3+...+3^{1989}\right)⋮13\)
\(E=1+3+3^2+3^3+...+3^{1991}\)
\(=\left(1+3+3^2+3^3+3^4+3^5\right)+\left(3^6+3^7+3^8+3^9+3^{10}+3^{11}\right)+...+3^{1986}+3^{1987}+3^{1988}+3^{1989}+3^{1990}+3^{1991}\)
\(=364\left(1+3^6+...+3^{1986}\right)⋮14\)
![YTP] Huấn Hoa Hồng Chế](data:image/jpeg;base64,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)
20 tháng 12 2021
\(A=2\left(1+2+2^2+2^3\right)+...+2^{57}\left(1+2+2^2+2^3\right)\)
\(=15\left(2+...+2^{57}\right)⋮15\)
VN
1
VN
Võ Ngọc Phương
VIP
2 tháng 11 2023
Sửa dùm mình dòng cuối cùng là " Vậy \(A⋮5\) " nha. Cảm ơn bạn.
Ta có:
\(H=2+2^2+2^3+...+2^{60}\)
\(H=\left(2+2^2\right)+\left(2^3+2^4\right)+...+\left(2^{59}+2^{60}\right)\)
\(H=2\left(1+2\right)+2^3\left(1+2\right)+...+2^{59}\cdot\left(1+2\right)\)
\(H=3\cdot\left(2+2^3+...+2^{59}\right)\)
Vậy H chia hết cho 3
_______
\(H=2+2^2+2^3+...+2^{60}\)
\(H=\left(2+2^2+2^3\right)+...+\left(2^{58}+2^{59}+2^{60}\right)\)
\(H=2\cdot\left(1+2+4\right)+2^4\cdot\left(1+2+4\right)+...+2^{58}\cdot\left(1+2+4\right)\)
\(H=7\cdot\left(2+2^4+...+2^{58}\right)\)
Vậy H chia hết cho 7
__________
\(H=2+2^2+2^3+...+2^{60}\)
\(H=\left(2+2^2+2^3+2^4\right)+\left(2^5+2^6+2^7+2^8\right)+...+\left(2^{57}+2^{58}+2^{59}+2^{60}\right)\)
\(H=2\cdot\left(1+2+4+8\right)+2^5\cdot\left(1+2+4+8\right)+...+2^{57}\cdot\left(1+2+4+8\right)\)
\(H=15\cdot\left(2+2^5+...+2^{57}\right)\)
Vậy H chia hết cho 15
H=2+22+23+...+260�=2+22+23+...+260
Ta có:
H=2.(1+2)+23.(1+2)+...+259.(1+2)�=2.1+2+23.1+2+...+259.(1+2)
H=2.3+23.3+...+259.3�=2.3+23.3+...+259.3
H=3.(2+23+...+259)⋮3�=3.2+23+...+259 ⋮3
Ta có:
H=2.(1+2+22)+24.(1+2+22)+...+228.(1+2+22)�=2.1+2+22+24.1+2+22+...+228.1+2+22
H=2.7+24.7+...+258.7�=2.7+24.7+...+258.7H=7.(2+24+...+258)⋮7�=7.2+24+...+258 ⋮7
Ta có:
H=2.(1+2+22+23)+25.(1+2+22+23)+...+257.(1+2+22+23)�=2.1+2+22+23+25.1+2+22+23+...+257.1+2+22+23
H=2.15+25.15+...+257.15�=2.15+25.15+...+257.15
H=15.(2+25+...+257)⋮15�=15.2+25+...+257 ⋮15Vậy H chia hết cho 3;7;153; 7; 15.
nhớ tik đúng nha!!!