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AH
Akai Haruma
Giáo viên
29 tháng 10 2023

Lời giải:

$\frac{10}{19}< \frac{....}{20}< \frac{11}{19}$
$\frac{200}{380}< \frac{19\times ...}{380}< \frac{220}{380}$

Suy ra: $200< 19\times ....< 220$

$\frac{200}{19}< ....< \frac{220}{19}$

$10,5< ....< 11,6$

Suy ra .... = 11

1 tháng 11 2023

không biết

 

`@` `\text {Ans}`

`\downarrow`

`a)`

\(\dfrac{7}{5}\cdot\dfrac{8}{19}+\dfrac{7}{5}\cdot\dfrac{12}{19}-\dfrac{7}{5}\cdot\dfrac{1}{19}\)

`=`\(\dfrac{7}{5}\cdot\left(\dfrac{8}{19}+\dfrac{12}{19}-\dfrac{1}{19}\right)\)

`=`\(\dfrac{7}{5}\cdot\dfrac{19}{19}=\dfrac{7}{5}\cdot1=\dfrac{7}{5}\)

`b)`

\(-\dfrac{3}{5}\cdot\dfrac{5}{7}+\left(-\dfrac{3}{5}\right)\cdot\dfrac{3}{7}+\left(-\dfrac{3}{5}\right)\cdot\dfrac{6}{7}\)

`=`\(-\dfrac{3}{5}\cdot\left(\dfrac{5}{7}+\dfrac{3}{7}+\dfrac{6}{7}\right)\)

`=`\(-\dfrac{3}{5}\cdot\dfrac{14}{7}\)

`=`\(-\dfrac{3}{5}\cdot2=-\dfrac{6}{5}\)

`c)`

\(10\dfrac{2}{9}+\left(2\dfrac{2}{5}-7\dfrac{2}{9}\right)\)

`=`\(10\dfrac{2}{9}+2\dfrac{2}{5}-7\dfrac{2}{9}\)

`=`\(\left(10\dfrac{2}{9}-7\dfrac{2}{9}\right)+2\dfrac{2}{5}\)

`=`\(3+2\dfrac{2}{5}=\dfrac{27}{5}\)

`d)`

\(6\dfrac{3}{10}-\left(3\dfrac{4}{7}+2\dfrac{3}{10}\right)\)

`=`\(6\dfrac{3}{10}-3\dfrac{4}{7}-2\dfrac{3}{10}\)

`=`\(\left(6\dfrac{3}{10}-2\dfrac{3}{10}\right)-3\dfrac{4}{7}\)

`=`\(4-3\dfrac{4}{7}=\dfrac{3}{7}\)

23 tháng 7 2023

a) \(\dfrac{7}{5}.\dfrac{8}{19}+\dfrac{7}{5}.\dfrac{12}{19}-\dfrac{7}{5}.\dfrac{1}{19}\)

\(=\dfrac{7}{5}.\left(\dfrac{8}{19}+\dfrac{12}{19}-\dfrac{1}{19}\right)\)

\(=\dfrac{7}{5}.1\)

\(=\dfrac{7}{5}\)

b) \(\dfrac{-3}{5}.\dfrac{5}{7}+\dfrac{-3}{5}.\dfrac{3}{7}+\dfrac{-3}{5}.\dfrac{6}{7}\)

\(=\dfrac{-3}{5}.\left(\dfrac{5}{7}+\dfrac{3}{7}+\dfrac{6}{7}\right)\)

\(=\dfrac{-3}{5}.2\)

\(=\dfrac{-6}{5}\)

c) \(10\dfrac{2}{9}+\left(2\dfrac{2}{5}-7\dfrac{2}{9}\right)\)

\(=\dfrac{92}{9}+\dfrac{12}{5}-\dfrac{65}{9}\)

\(=\dfrac{92}{9}-\dfrac{65}{9}+\dfrac{12}{5}\)

\(=3+\dfrac{12}{5}\)

\(=\dfrac{15}{5}+\dfrac{12}{5}\)

\(=\dfrac{27}{5}\)

d) \(6\dfrac{3}{10}-\left(3\dfrac{4}{7}+2\dfrac{3}{10}\right)\)

\(=\dfrac{63}{10}-\dfrac{25}{7}-\dfrac{23}{10}\)

\(=\dfrac{63}{10}-\dfrac{23}{10}-\dfrac{25}{7}\)

\(=4-\dfrac{25}{7}\)

\(=\dfrac{28}{7}-\dfrac{25}{7}\)

\(=\dfrac{3}{7}\)

Chúc bạn học tốt

 

31 tháng 10 2019

\(\frac{3^{19}.2^9+5.9^9.2^9}{3^{19}.2^9+9^{10}.2^{10}}\)

\(=\frac{3^{19}.2^9+5.\left(3^2\right)^9.2^9}{3^{19}.2^9+\left(3^2\right)^{10}.2^{10}}\)

\(=\frac{3^{19}.2^9+5.3^{18}.2^9}{3^{19}.2^9+3^{20}.2^{10}}\)

\(=\frac{3^{18}.2^9\left(3+5\right)}{3^{19}.2^9\left(1+6\right)}\)

\(=\frac{8}{3.7}=\frac{8}{21}\)

3 tháng 1 2018

1 - 4 - 7 + 10 + 13 - 16 - 19 + 22 - 25

= -25

Đáp án đó

^ ^

3 tháng 1 2018

1 - 4 - 7 + 10 + 13 - 16 - 19 + 22 - 25

=-25

^^

11 tháng 10 2017

64^10   -   32^11 - 16^13

=  (2^6)^10   -    (2^5)^11  -   (2^4)^13

= 2^60 - 2^55 - 2^52

= 2^52 ( 2^8 - 2^3 -1)

= 2^52 . 243

Vi 243 chia het cho 19 nen 2^52 . 243 chia het cho 9

Vay tong tren chia het cho 19

2 tháng 12 2021

=19.[(-257)+47-(-10)]

=19.(-200)

=-3800