Đặt \(A=x^{13}-\left(8x^{12}-8x^{11}+8x^{10}-8x^9+.....+8x^2-8x^1\right)+8\)

Đặt \(B=8x^{12}-8x^{11}+8x^{10}-....+8x^2-8x^1\)

\(B=8.\left(x^{12}-x^{11}+x^{10}-x^9+....+x^2-x^1\right)\)

Đặt \(C=x^{12}-x^{11}+x^{10}-x^9+...+x^2-x\)

Suy ra \(C.x=x^{13}-x^{12}+x^{11}-x^{10}+.....+x^3-x^2\)

Nên \(C.x-C=x^{13}-x\)hay \(C.\left(x-1\right)=x^{13}-x\)

Khi đó \(C=\frac{x^{13}-x}{x-1}\)nên\(B=8.\frac{x^{13}-x}{x-1}\)

Từ đó tính tương tự nha , cách làm thì có thể sai những em vẫn cố gắng giúp , ai có cách hay hơn thì giải nhé 

chả hiểu gì

a, \(\left|x-3\right|-16=-4\Leftrightarrow\left|x-3\right|=12\)

\(\Leftrightarrow\orbr{\begin{cases}x-3=12\\x-3=-12\end{cases}\Leftrightarrow\orbr{\begin{cases}x=15\\x=-9\end{cases}}}\)

b, \(26-\left|x+9\right|=-13\Leftrightarrow\left|x+9\right|=39\)

\(\Leftrightarrow\orbr{\begin{cases}x+9=39\\x+9=-39\end{cases}\Leftrightarrow\orbr{\begin{cases}x=30\\x=-48\end{cases}}}\)

f, \(9x+25=-\left(2x-58\right)\Leftrightarrow9x+25=-2x+58\)

\(\Leftrightarrow11x-33=0\Leftrightarrow x=3\)

Làm nốt nhé ! 

a. \(\left|x-3\right|-16=-4\)

\(\Rightarrow\left|x-3\right|=12\)

\(\Rightarrow\orbr{\begin{cases}x-3=12\\x-3=-12\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=15\\x=-9\end{cases}}\)

b. \(26-\left|x+9\right|=-13\)

\(\Rightarrow\left|x+9\right|=39\)

\(\Rightarrow\orbr{\begin{cases}x+9=39\\x+9=-39\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=30\\x=-48\end{cases}}\)

c. \(5-\left(10-x\right)=7\)

\(\Rightarrow10-x=-2\)

\(\Rightarrow x=12\)

d. \(11+\left(15-x\right)=1\)

\(\Rightarrow15-x=-10\)

\(\Rightarrow x=25\)

e. \(8x-75=5x+21\)

\(\Rightarrow8x-5x=75+21\)

\(\Rightarrow3x=96\)

\(\Rightarrow x=32\)

f. \(9x+25=-\left(2x-58\right)\)

\(\Rightarrow9x+25=-2x+58\)

\(\Rightarrow9x+2x=58-25\)

\(\Rightarrow11x=33\)

\(\Rightarrow x=3\)

g. \(\left|x+3\right|=4\)

\(\Rightarrow\orbr{\begin{cases}x+3=4\\x+3=-4\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=1\\x=-7\end{cases}}\)

h. \(15-\left|2x-1\right|=\left|-8\right|\)

\(\Rightarrow15-\left|2x-1\right|=8\)

\(\Rightarrow\left|2x-1\right|=7\)

\(\Rightarrow\orbr{\begin{cases}2x-1=7\\2x-1=-7\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=4\\x=-4\end{cases}}\)

⇔ 5(5x + 2) – 10(8x – 1) = 6(4x + 2) – 150

⇔ 25x + 10 – 80x + 10 = 24x + 12 – 150

⇔ 20 – 55x = 24x – 138

⇔ -55x – 24x = -138 – 20

⇔ -79x = -158

⇔ x = 2.

Vậy phương trình có tập nghiệm S = {2}.

a: =-5/9-4/9+8/15+7/15-2/11=-2/11

b: =10/17+7/17-5/13-8/13+11/25

=11/25

c: =(9/12-2/12)*3/2=7/12*3/2=21/24=7/8

d: =(31/10-25/10)*3-2

=3/5*3-2

=9/5-2

=-1/5

\(1)\)\(-\dfrac{10}{11}.\dfrac{8}{9}+\dfrac{7}{18}.\dfrac{10}{11}\)

\(=\dfrac{10}{11}\left(-\dfrac{8}{9}+\dfrac{7}{18}\right)\)

\(=\dfrac{10}{11}\left(\dfrac{-16}{18}+\dfrac{7}{18}\right)\)

\(=\dfrac{10}{11}.\left(-\dfrac{1}{2}\right)=-\dfrac{5}{11}\)

\(2)\)\(\dfrac{12}{25}.\dfrac{23}{7}-\dfrac{12}{7}.\dfrac{13}{25}\)

\(=\dfrac{12}{7}.\dfrac{23}{25}-\dfrac{12}{7}.\dfrac{13}{25}\)

\(=\dfrac{12}{7}.\left(\dfrac{23}{25}-\dfrac{13}{25}\right)\)

\(=\dfrac{12}{7}.\dfrac{2}{5}=\dfrac{24}{35}\)

\(3)\)\(\dfrac{3}{7}.\dfrac{16}{15}-\dfrac{2}{15}.\dfrac{-3}{7}\)

\(=\dfrac{3}{7}.\dfrac{16}{15}-\dfrac{3}{7}.\dfrac{-2}{15}\)

\(=\dfrac{3}{7}.\left(\dfrac{16}{15}+\dfrac{2}{15}\right)\)

\(=\dfrac{3}{7}.\dfrac{18}{15}=\dfrac{18}{35}\)

\(4)\)\(-\dfrac{4}{13}.\dfrac{5}{17}+\dfrac{-12}{13}.\dfrac{4}{17}\)

\(=-\dfrac{4}{13}.\dfrac{5}{17}+\dfrac{-4}{13}.\dfrac{12}{17}\)

\(=-\dfrac{4}{13}.\left(\dfrac{5}{17}+\dfrac{12}{17}\right)\)

\(=-\dfrac{4}{13}.\dfrac{17}{17}=-\dfrac{4}{13}\)

`#040911`

`1)`

`-10/11 * 8/9 + 7/18 . 10/11`

`= 10/11 * (-8/9 + 7/18)`

`= 10/11 * (-1/2)`

`= -5/11`

`2)`

`12/25 * 23/7 - 12/7 *13/25`

`= 12/7 * 23/25 - 12/7 * 13/25`

`= 12/7 * (23/25 - 13/25)`

`= 12/7 * 2/5`

`= 24/35`

`3)`

`3/7 * 16/15 - 2/15 * (-3)/7`

`= 3/7 * (16/15 + 2/15)`

`= 3/7 * 6/5`

`= 18/35`

`4)`

`-4/13 * 5/17 + (-12)/13 * 4/17`

`= -4/17 * 5/13 + (-12)/13 * 4/17`

`= 4/17 * (-5/13 - 12/13)`

`= 4/17 * (-17)/13`

`= -4/13`

8x = 7,8x + 25

\(a,\frac{-1}{9}.\frac{15}{22}.\frac{-9}{25}\)

\(=\frac{-1.15.\left(-9\right)}{9.22.25}\)

\(=\frac{3}{110}\)

\(b,\frac{-2}{7}.\left(\frac{5}{13}-\frac{9}{15}\right)-\frac{2}{7}.\frac{8}{13}\)

\(=\frac{-2}{7}.\left(\frac{5}{13}+\frac{8}{13}-\frac{3}{5}\right)\)

\(=\frac{-2}{7}.\left(1-\frac{3}{5}\right)\)

\(=\frac{-2}{7}.\frac{2}{5}\)

\(=\frac{-4}{35}\)

\(c,\frac{3}{10}.\left(\frac{-4}{9}+\frac{2}{5}\right)-\frac{3}{10}.\left(\frac{5}{9}-\frac{3}{5}\right)\)

\(=\frac{3}{10}.\left[\left(\frac{-4}{9}+\frac{2}{5}\right)-\left(\frac{5}{9}-\frac{3}{5}\right)\right]\)

\(=\frac{3}{10}.\left(\frac{-4}{9}+\frac{2}{5}-\frac{5}{9}+\frac{3}{5}\right)\)

\(=\frac{3}{10}.\left[\left(\frac{-4}{9}-\frac{5}{9}\right)+\left(\frac{2}{5}+\frac{3}{5}\right)\right]\)

\(=\frac{3}{10}.\left(-1+1\right)\)

\(=\frac{3}{10}.0\)

\(=0\)

\(d,\frac{4}{11}-\frac{5}{13}+\frac{7}{11}-\frac{8}{13}\)

\(=\left(\frac{4}{11}+\frac{7}{11}\right)+\left(\frac{-5}{13}-\frac{8}{13}\right)\)

\(=1-1\)

\(=0\)

Học tốt

`a)2019xx85+2019xx25-2019xx10`

`=2019xx(85+25-10)`

`=2019xx100=20190`

__________________________________________________

`b)13/5xx4/9+5/9xx13/9`

`=13/9xx4/5+5/9xx13/9`

`=13/9xx(4/5+5/9)`

`=13/9xx61/45=793/405`

Hoặc:

`b)13/5xx4/9+5/9xx13/5`

`=13/5xx(4/9+5/9)`

`=13/5xx9/9=13/5`

A

2019.(85+25-10)=201 900

B

13/5 . (4/9+5/9)=13/5

học tốt ^^

Bài 1:

a) 8 x 4 x 125 x 25

= ( 8 x 125 ) x ( 4 x 25 )

= 1000 x 100

= 100000

b) 2 x 178 x 5

= ( 2 x 5 ) x 178

= 10 x 178

= 1780

Bài 2:

a) 5/7 + 7/13 + 9/13 + 6/5 + 9/7 + 9/5

= ( 5/7 + 9/7 ) + ( 7/13 + 9/13 ) + ( 6/5 + 9/5 )

= 2 + 16/13 + 3

= 81/13

b) 1/11 + 2/11 + ... + 10/11

= 55/11 = 5