- (15 – 16+ 230) + (15-16+230) |
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a, ( x + 17 ) : 21 + 3 = 7
( x + 17 ) : 21 = 7 - 3
( x + 17 ) : 21 = 4
x + 17 = 4 x 21
x + 17 = 84
x = 84 - 17
x = 67
b, 3x+3 - 13 = 230
=> 3x + 3 = 230 + 13
=> 3x+3 = 243
=> 3x+3 = 35
=> x + 3 = 5
=> x = 5 -3
=> x = 2
c, 2x - 15 = 23
2x = 23 + 15 = 38
x = 38 : 2
x = 19
d, ( x + 16 ) : 31 - 3 = 7
( x + 16 ) : 31 = 10
x + 16 = 10 x 31 = 310
x = 310 - 16
x = 294
a) = 64/17 + 38/17 + 230/47 + 52/47
= 102/17 + 282/47
= 6 + 6
= 12
b) = 16/15 + 8/5 + 69/27 + 5/9
= 8/3 + 23/9 + 5/9 (tự quy đồng)
= 8/3 + 28/9 ( // )
= 52/9
Lần này k mình nha !
\(\frac{64}{17}\)\(+\)\(\frac{230}{47}\)\(+\)\(\frac{38}{17}\)\(+\)\(\frac{52}{47}\)\(=\)\(\left[\frac{64}{17}+\frac{38}{17}\right]\)\(+\)\(\left[\frac{230}{47}+\frac{52}{47}\right]\)\(=\)\(6\)\(+\)\(6\)\(=\)\(12\)
\(\frac{16}{15}\)\(+\frac{69}{27}+\frac{5}{9}\)\(+\frac{8}{5}=\)\(5\frac{7}{9}\)Nhớ phải k mình đấy !!!!!!!!!!!!!!!!!!!!!!!!!!!
720 : [ 41 - (2\(x\) - 5)] = 22.5
41 - (2\(x\) - 5) = 720 :110
2\(x\) - 5 = 41 - \(\dfrac{72}{11}\)
2\(x\) - 5 = \(\dfrac{379}{11}\)
2\(x\) = \(\dfrac{379}{11}\) + 5
2\(x\) = \(\dfrac{434}{11}\)
\(x\) = \(\dfrac{434}{11}\) : 2
\(x\) = \(\dfrac{217}{11}\)
15 - \(x\) = 7 - (-2)
15 - \(x\) = 7 + 2
15 - \(x\) = 9
\(x\) = 15 - 9
\(x\) = 6
\(15\times\left(32-24\div x\right)-230=70\)
\(15\times\left(32-24\div x\right)=300\)
\(32-24\div x=20\)
\(24\div x=12\)
\(x=2\)
\(15\times\left(32-24:x\right)-230=70\)
\(15\times\left(32-24:x\right)=70+230\)
\(15\times\left(32-24:x\right)=300\)
\(32-24:x=300:15\)
\(32-24:x=20\)
\(24:x=32-20\)
\(24:x=12\)
\(x=24:12\)
\(x=2\)
\(#WendyDang\)
230 - 35 - 15 = ? x 2 = ? x ? = ?
= 230 - { 35 + 15 } = ? x 2 = ? x ?
= 230 - 50 = ? x 2 = ? x ?
= 180 x 2 = ? x ?
= 360 x 360
= ?
296 : a dư 16 ⇒ 296 - 16 ⋮ a ⇒ 280 ⋮ a
230 : a dư 10 ⇒ 230 - 10 ⋮ a ⇒ 220 ⋮ a
⇒ a \(\in\) UC(280; 220)
280 = 23.5.7; 220 = 22.5.11
ƯCLN (280; 220) = 22.5 = 20
a \(\in\) Ư(20) = {1; 2; 4;5;10; 20}
230+[ 16+(x-5)]=315.23
230+[ 16+(x-5)]=2520
16+(x-5)=2520-230
16+(x-5)=2290
x-5=2290-16
x-5=2274
x=2274+5
x=2279
230+[ 16+(x-5) ]=315.23
230+[ 16+(x-5) ]=2520
16+(x-5)=2520-230
16+(x-5)=2290
x-5=2290-16
x-5=2274
x=2274+5
x=2279
k cho minh nha
296 : a dư 16 ⇒ 296 - 16 ⋮ a ⇒ 280 ⋮ a
230 : a dư 10 ⇒ 230 - 10 ⋮ a ⇒ 220 ⋮ a
⇒ a \(\in\) ƯC(280; 220)
280 = 23.5.7; 220 = 22.5.11
ƯCLN (280 ; 220) = 22.5 = 20
a \(\in\) Ư(20) = {1; 2; 4; 5; 10; 20}
-(15 - 16 + 230) + (15 - 16 + 230)
= -15 + 16 - 230 + 15 - 16 + 230
= (-15 + 15) + (16 - 16) + (-230 + 230)
= 0 + 0 + 0
= 0
- (15 - 16 + 230) + (15 - 16 + 230)
= - ( 229 ) + 229
= + ( 229 - 229 )
= 0.