\(A=2^5.5^2-3^2-10\\ \\ A=32.25-9-10=800-9-10\\ \\ A=781\)

\(B=3^3.3^2+2^2+3^2\\ \\ B=3^{3+2}+4+9\\ \\ B=3^5+13=243+13\\ \\ B=256\)

1: =29-16-3*2=13-6=7

2: =35-12+(-14)-2

=23-16=7

3: =4*3125-32:16

=12500-2

=12498

4: =-452+67-75+452=-8

5: =18+99*18-3^5-2^5

=1800-275

=1525

a)  B   =   3 3 . 3 2   + 2 2   + 3 2 = 256 = 16 2 .

b)  D   =   5 . 4 3   +   2 4 . 5 = 400 =  20 2

x=3 k cho minh nhe

b. (-274).71+(-274).29

  = (-274).(71+29)

  = (-274). 100

  = -27400

 (-274).71+(-274).29

=(-274).(71+29)

=(-274).100

=(-27400)

a, A =  2 2 . 5 2 - 3 2 - 10 = 81 =  3 4 = 9 2

b, B =  3 3 . 3 2 + 2 2 + 3 2 = 256 =  16 2 = 2 8 = 4 4

c, C =  5 . 4 3 + 2 4 . 5 = 400 =  20 2

d, D =  5 3 + 6 3 + 7 3 + 79 . 2 2 = 1000 =  10 3

a)  A = 2 5 . 5 2 - 3 2 - 10 = 81 = 3 4 ( = 9 2 ) .

b)  B = 3 3 . 3 2 + 2 2 + 3 2 = 256 = 16 2 ( = 2 8 = 4 4 ) .

c)  C = 5 . 4 3 + 2 4 . 5 = 400 = 20 2

d)  D = 5 3 + 6 3 + 7 3 + 7 9 . 2 2 = 1000 = 10 3 .

a) Đặt: \(A=1+2^2+2^3+...+2^{10}\)

\(\Rightarrow2A=2\left(1+2^2+2^3+...+2^9+2^{10}\right)\)

\(\Rightarrow2A=2+2^3+2^4+...+2^{10}+2^{11}\)

\(\Rightarrow2A-A=\left(2+2^3+2^4+...+2^{10}+2^{11}\right)-\left(1+2^2+2^3+...+2^{10}\right)\)

\(\Rightarrow A=\left(2^3-2^3\right)+\left(2^4-2^4\right)+...+\left(2-1\right)+\left(2^{11}-2^2\right)\)

\(\Rightarrow A=0+0+...+1+\left(2^{11}-2^2\right)\)

\(\Rightarrow A=1+2^{11}-2^2=1+2048-4=2045\)

Vậy: \(1+2^2+2^3+...+2^{10}=2045\)

b) 

a] \(60-3\left(x-1\right)=2^3\cdot3\)

\(\Rightarrow60-3\left(x-1\right)=24\)

\(\Rightarrow3\left(x-1\right)=36\)

\(\Rightarrow x-1=12\)

\(\Rightarrow x=13\)

b] \(\left(3x-2\right)^3=2\cdot2^5\)

\(\Rightarrow\left(3x-2\right)^3=2^6\)

\(\Rightarrow\left(3x-2\right)^3=\left(2^2\right)^3\)

\(\Rightarrow3x-2=2^2\)

\(\Rightarrow3x=6\)

\(x=2\)

c] \(5^{x+1}-5^x=500\)

\(\Rightarrow5^x\left(5-1\right)=500\)

\(\Rightarrow5^x\cdot4=500\)

\(\Rightarrow5^x=125\)

\(\Rightarrow5^x=5^3\)

\(\Rightarrow x=3\)

d] \(x^2=x^4\)

\(\Rightarrow x=x^2\)

\(\Rightarrow x-x^2=0\)

\(\Rightarrow x\left(1-x\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x=0\\1-x=0\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=0\\x=1\end{matrix}\right.\)

giúp mình đi các bạn

x + 20 + 21 + x + 22 + 23 + x + 24 + 25 + x + 26 + 27 + x + 28 + 29 + x + 30 = 330

6x + (30 + 20) . (30 - 20 + 1) : 2 = 330

6x + 50 . 11 : 2 = 330

6x + 275 = 330

6x = 330 - 275

6x = 55

x = 55 : 6

x = 55/6

\(x+20+21+x+22+23+x+24+25+x+26+27+x+28+29+x+30=330\)

\(\Rightarrow\left(x+x+x+x+x+x\right)+\left(20+21+22+23+24+25+26+27+28+29+30\right)=330\)

\(\Rightarrow6x+\left[\left(30-20\right):1+1\right]\left(20+30\right):2=330\)

\(\Rightarrow6x+11.50:2=330\)

\(\Rightarrow6x+275=330\)

\(\Rightarrow6x=55\)

\(\Rightarrow x=\dfrac{55}{6}\)