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Bài 1:
a) x.x.y.y.x.y.x = \(x^4.y^3\)
b) 1000.10.10= 1000. \(10^2\)
c) \(3^{15}:3^5=3^{15-5}=3^{10}\)
d) \(9^8:3=3^{16}:3=3^{15}\)
e) \(125:5^3=\dfrac{125}{5^3}=\dfrac{5^3}{5^3}=1\)
B2:
15 x 6 x 4 x 125 x 8
= (15 x 4) x (125 x 8) x 6
= 60 x 1000 x 6
= 60000 x 6
= 360000
15 x6x4x125x8
= (15x4)x6x(125x8)
= 60x6 x 1000
= 360 x 1000
= 360 000
\(x=\left(\frac{33}{5}:6-0,125\cdot8+\frac{32}{15}\cdot0,03\right)\cdot\frac{11}{4}\)
\(x=\left(\frac{33}{5}\cdot\frac{1}{6}-\frac{1}{8}\cdot8+\frac{32}{15}\cdot\frac{3}{100}\right)\cdot\frac{11}{4}\)
\(x=\left(\frac{11}{10}-1+\frac{8}{125}\right)\cdot\frac{11}{4}\)
\(x=\frac{41}{250}\cdot\frac{11}{4}\)
\(x=\frac{451}{100}\)
\(x=\left(\frac{33}{5}:6-0,125.8+\frac{32}{15}.0,03\right).\frac{11}{4}\)
\(< =>x=\left(\frac{33}{30}-1+\frac{32}{15}.\frac{3}{100}\right).\frac{11}{4}\)
\(< =>x=\left(\frac{3}{30}+\frac{32}{500}\right).\frac{11}{4}\)
\(< =>x=\left(\frac{1}{10}+\frac{8}{125}\right).\frac{11}{4}\)
\(< =>x=\frac{41}{250}.\frac{11}{4}=\frac{451}{100}\)
a) 12 : { 390 : [ 500 - ( 125 + 35. 7 ) ] }
= 12 : { 390 : [ 500 - ( 125 + 245 ) ] }
= 12 : { 390 : [ 500 - 370 ] }
= 12 : { 390 : 130 }
= 12 : 3
= 4
a)125 : x = 22 - (-1)
125 : x = 4 + 1
125 : x = 5
x = 125 : 5
x = 25
-------------------------------------------------
b) 2x - 8 = -4
2x = (-4) + 8
2x = 4
x = 4 : 2
x = 2
-----------------------------------------------------------
c) Xem lại đề.
\(125:x=2^2-\left(-1\right)\)
\(=>125:x=4+1\)
\(=>125:x=5\)
\(=>x=125:5\)
\(=>x=25\)
_____
\(2x-8=-4\)
\(=>2x=\left(-4\right)+8\)
\(=>2x=4\)
\(=>x=4:2\)
\(=>x=2\)
_______
\(6^{2x+5}=216\)
\(=>6^{2x+5}=6^3\)
\(=>2x+5=3\)
\(=>2x=3-5\)
\(=>2x=-2\)
\(=>x=\left(-2\right):2\)
\(=>x=-1\)
\(#NqHahh\)
a, 410. 230=220.230=250
b,925.274.813= 350.312.312=374
Tương tự các câu khác....
a, 410.230 = (22)10.230 = 220.230 = 250
b, 925.274.813 = (32)25.(33)4.(34)3 = 350.312.312 = 374
c, 2550.1255 = (52)50.(53)5 = 5100.515 = 5115
d, 643.48.164 = (26)3.(22)8.(24)4 = 218.216.216 = 250
e, 38 : 36 = 32
210 : 83 = 210 : (23)3 = 210 : 29 = 2
127 : 67 = (12 : 6)7 = 27
@Dương Tuyết Mai
1.
x.x.y.y.x.y.x=(x.x.x.x) (y.y.y)=x4.y3=(x.y)4.3=xy12
1000.10.10=103.10.10=103+1+1=105
315:35=315–5=310
98:3=(32)8:3=316:3=316–1=315
125:53=53:53=1
=>6000x=12000
hay x=2
125.(-6).x.(-8)=12000
125.[(-6).(-8)].x=12000
145.48.x=12000
6000.x=12000
x=12000:6000
x=2