a,b đều bằng 0 nhe´ bn

103 . ( x - 4 ) + 14 = 40

103 x ( x - 4 )        = 40 - 14

103 x ( x - 4 )         = 26

            x - 4             = 26 : 103 

            x - 4              =  26/103

             x                   = 26/103 + 4

              x                  = 438/103.

Chúc bạn học tốt!!!!!!!!!!!!!!

103 x ( x - 4 ) + 14 = 40

103 x ( x - 4 ) = 40 - 14

103 x ( x - 4 ) = 26

x - 4 = 26 : 103

x - 4 = 26/103

x = 26/103 + 4 

x = 438/103

Hok tốt

x : 2 + Y : 3 = x + y : 2 + 3

x/2 + y/3=x+y/5

3x/6 + 2y/6=x+y/5

3x+2y/6=x+y/5

5(3x+2y)/30=5(x+y)/30

=> x+y=3x+2y

=> 

\(S=1+2+2^2+2^3+...+2^{29}\)

\(S=\left(1+2+2^2\right)+\left(2^3+2^4+2^5\right)+...+\left(2^{27}+2^{28}+2^{29}\right)\)

\(S=7+2^3.\left(1+2+2^2\right)+...+2^{27}.\left(1+2+2^2\right)\)

\(S=7+2^3.7+...+2^{27}.7\)

\(S=7.\left(1+2^3+...+2^{27}\right)\)

Vì \(7⋮7\) nên \(7.\left(1+2^3+...+2^{27}\right)⋮7\)

Vậy \(S⋮7\)

______

\(2^{x+1}+2^x.3=320\)

\(=>2^x.2+2^x.3=320\)

\(=>2^x.\left(2+3\right)=320\)

\(=>2^x.5=320\)

\(=>2^x=320:5\)

\(=>2^x=64=2^6\)

\(=>x=6\)

\(#NqHahh\)

\(#Nulc`\)

mình cho thử thôi chứ mình biết 

tìm chữ số tận cùng thì dc nhưng tính thì math error bạn ơi

bạn hỏi thế trả lời = niềm tin à!

Lời giải:

$A=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{19.20}$

$=\frac{2-1}{1.2}+\frac{3-2}{2.3}+\frac{4-3}{3.4}+...+\frac{20-19}{19.20}$

$=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{19}-\frac{1}{20}$

$=1-\frac{1}{20}=\frac{19}{20}$

19/20

\(x=\dfrac{7}{25}+\dfrac{-1}{5}.\Leftrightarrow x=\dfrac{7-5}{25}=\dfrac{2}{25}.\)

\(x=\dfrac{3}{11}+\dfrac{4}{-9}.\Leftrightarrow x=\dfrac{33-44}{99}=\dfrac{-1}{9}.\)

\(\dfrac{5}{9}+\dfrac{x}{-1}=\dfrac{-1}{3}.\Leftrightarrow\dfrac{5}{9}-x=\dfrac{-1}{3}.\Leftrightarrow x=\dfrac{8}{9}.\)

\(a,\Rightarrow x=\dfrac{7}{25}+\dfrac{-5}{25}\\ \Rightarrow x=\dfrac{2}{25}\\ b,\Rightarrow x=\dfrac{5}{11}+\dfrac{-4}{9}\\ \Rightarrow x=\dfrac{45}{99}+\dfrac{-44}{99}\\ \Rightarrow x=\dfrac{1}{99}\)

làm theo dạng toán qui nạp