\(a,18.\left(x-16\right)=18\)

\(x-16=18:18\)

\(x-16=1\)

\(x=16+1\)

\(x=17\)

\(b,45.\left(11-x\right)=45\)

\(11-x=45:45\)

\(11-x=1\)

\(x=11-1\)

\(x=10\)

\(18.\left(x-16\right)=18\)

\(=>x-16=1\)

\(=>x=17\)

\(45\left(11-x\right)=45\)

\(=>11-x=1\)

\(=>x=10\)

Ủng hộ mik nha

Thanks

đưa câu kahcs đi bạn

ban oi minh biet dap so thoi 

48.13 + 61 . 16 

= 48 . ( 10 + 3 ) + ( 60 + 1 ) . 16 

= [ 48 . 10 + 48.3 ] + [ 60 . 16 + 1 . 16 ] 

= 624 + 976 

= 1600 

1, \(48.13+61.16=16.3.13+61.16=16.\left(39+61\right)=16.100=1600\)

\(2,5.6.32+60.15.2+3.16.5=5.6.2.16+60.15.2+3.5.4.4=60.16+60.30+60.4=60.\left(16+30+4\right)=60.50=3000\)

câu 1: 
UCLN(15;19)=1

bạn giúp mình nốt đi mà

Bạn đi học rồi hả

Gọi số tự nhiên đó là x.

Ta có: BC{2,3,4,5,6}={60,120,180,240,....}

mà \(7\inƯ\left(BC\left\{2,3,4,5,6\right\}-1\right)\)

=> Xét : +)60=>x=59 không chia hết cho 7(loại)

             +)120=>x=119 chia hết cho 7(tm)

vậy số đó là 119

xy+3x-7y=23

x(y+3)-7(y+3)+21-23=0

(y+3)(x-7)=2

    vì x,y thuộc Z=> 2=2x1=1x2=-1x(-2)=(-2)x(-1)

                  TH1:(y+3)(x-7)=2x1

                    =>y+3=2

                        y=(-1)

                   =>x-7=1

                      x=8

              các trường hợp còn lại thì chỉ cần lam tương tự thôi nha

                           Học tốt nha

cảm ơn bạn nhíe 

\(a)24\times(x-16)=12^2\\\Rightarrow 24\times(x-16)=144\\\Rightarrow x-16=144:24\\\Rightarrow x-16=6\\\Rightarrow x=6+16\\\Rightarrow x=22\\---\\b)(x^2-10):5=5\\\Rightarrow x^2-10=5\times5\\\Rightarrow x^2-10=25\\\Rightarrow x^2=25+10\\\Rightarrow x^2=35\\\Rightarrow x=\pm\sqrt{35}\\---\)

\(c)(5x+335):2=400\\\Rightarrow 5x+335=400\times2\\\Rightarrow 5x+335=800\\\Rightarrow 5x=800-335\\\Rightarrow 5x=465\\\Rightarrow x=465:5\\\Rightarrow x=93\\---\\d)63:(5x+4)=2^3-1\\\Rightarrow 63:(5x+4)=8-1\\\Rightarrow 63:(5x+4)=7\\\Rightarrow 5x+4=63:7\\\Rightarrow 5x+4=9\\\Rightarrow 5x=9-4\\\Rightarrow 5x=5\\\Rightarrow x=5:5\)

\(\Rightarrow x=1\)

\(Toru\)

\(A=\frac{\left(23\frac{11}{15}-26\frac{13}{20}\right)}{12^2+5^2}\cdot\frac{1-\frac{1}{30}-\frac{1}{42}-\frac{1}{56}}{3^2.13.2-13.5}-\frac{19}{37}\)

\(A=\frac{\left(23+\frac{11}{15}-26+\frac{13}{20}\right)}{144+25}\cdot\frac{1-\frac{1}{5.6}-\frac{1}{6.7}-\frac{1}{7.8}}{9.13.2-13.5}-\frac{19}{37}\)

\(A=\frac{\left(23+26+\frac{11}{15}-\frac{13}{20}\right)}{169}\cdot\frac{1-\left(\frac{1}{5}-\frac{1}{6}\right)-\left(\frac{1}{6}-\frac{1}{7}\right)-\left(\frac{1}{7}-\frac{1}{8}\right)}{13.\left(9.2-5\right)}-\frac{19}{37}\)

\(A=\frac{49+\frac{44}{60}-\frac{39}{60}}{169}\cdot\frac{1-\frac{1}{5}+\frac{1}{6}-\frac{1}{6}+\frac{1}{7}-\frac{1}{7}+\frac{1}{8}}{13.13}-\frac{19}{37}\)

\(A=\frac{49+\frac{1}{20}}{169}\cdot\frac{1-\frac{1}{5}+\frac{1}{8}}{169}-\frac{19}{37}\)

\(A=\frac{49\frac{1}{20}}{169}\cdot\frac{\frac{4}{5}+\frac{5}{40}}{169}-\frac{19}{37}\)

\(A=\frac{981}{169}\cdot\frac{\frac{32}{40}+\frac{5}{40}}{169}-\frac{19}{37}\)

\(A=\frac{981}{169}\cdot\frac{\frac{37}{40}}{169}-\frac{19}{37}\)

\(A=\frac{981.\frac{37}{40}}{169^2}-\frac{19}{37}\)

\(A=\frac{\frac{36297}{40}}{28561}-\frac{19}{37}\)

\(A=\frac{907,425}{28561}-\frac{19}{37}\)

\(A=\frac{33574,725}{1056757}-\frac{542659}{1056757}\)

\(A=\frac{-509084,275}{1056757}=-0,04604282...\)

Mik chỉ làm đc thế này thôi, ôn thi học kì II tốt nha bạn!