64 . 4^x = 168

<=> 43. 4^x = 416

=> 3 + x = 16

<=> x = 13

Vậy x = 13

2^x.16² = 1024

<=> 2^x. 2⁸ = 210

=> x + 8 = 10

<=> x = 2

Vậy x = 2

b: Ta có: \(2^x\cdot16^2=1024\)

\(\Leftrightarrow2^x\cdot2^8=2^{10}\)

\(\Leftrightarrow x+8=10\)

hay x=2

\(a.2^6.\left(x-2\right)=104\)

\(x-2=104:2^6\)

\(x-2=1,652\)

\(x=1,625+2\)

\(x=3,625\)

\(b.2\times4^{x+1}=128\)

\(4^{x+1}=128:2\)

\(4^{x+1}=64\)

\(4^{x+1}=4^3\)

\(\Rightarrow x+1=3\)

\(x=3-1\)

\(\Leftrightarrow x=3\)

\(c.227-5\left(x+8\right)=3^6:3^3\)

\(227-5\left(x+8\right)=3^3\)

\(227-5\left(x+8\right)=27\)

\(5\left(x+8\right)=227-27\)

\(5\left(x+8\right)=200\)

\(x+8=200:5\)

\(x+8=40\)

\(x=40-8\)

\(x=32\)

ủng hộ mk nha, chắc đúng đó

cả tháng nay ms online lại

thx bn

a) \(2^{x+1}-2^x=32\)

\(\Rightarrow2^x\left(2-1\right)=2^5\)

\(\Rightarrow2^x.1=2^5\)

\(\Rightarrow x=5\)

b) \(2^{x+1}=2\)

\(\Rightarrow2^{x+1}=2^1\)

\(\Rightarrow x+1=1\)

\(\Rightarrow x=0\)

\(2^{x+1}-2^x=32\)

\(2^x.2-2^x=32\)

\(2^x\left(2-1\right)=32\)

\(2^x=32\)

\(x=5\)

a) (x-1)² = 0

=> x - 1 =0 => x = 1

b) (x-5)³ =  8 = 2³

=> x-5 = 2 => x = 7

c) 2x + 1⁴ = 81

2x = 80

x = 40

d) (x-4)³ =(x-4)⁶

=> (x-4)⁶ -(x-4)³ = 0

(x-4)³. [ (x-4)³ -1 ] = 0

=> (x-4)³ = 0 => x - 4 = 0 => x = 4

(x-4)³ - 1 = 0 => (x-4)³ = 1 => x - 4 = 1 => x = 5

KL:...

a ) 2^x = 32 
=> 2⁵       
b ) 3^x = 243
=> 3⁵
c ) 2^x = 256
=> 2⁸ 

a,x=5

b,x=5

c,x=8

1. 2^x=16\(\Rightarrow\)X=4

2. 2^2x-1=2⁷

\(\Rightarrow\)2⁷=2^2.4-1

Vậy x =4

x=4 nha chị

\(2^{x+1}-2^x=32\\ \Rightarrow2^x\cdot2^1-2^x=32\\ \Rightarrow2^x\left(2-1\right)=32\\ \Rightarrow2^x=32:1\\ \Rightarrow2^x=32\\ \Rightarrow2^x=2^5\\ \Rightarrow x=5\)

\(2^{x+1}-2^x=32\\ =>2^x.\left(2^1-1\right)=32\\ =>2^x.1=2^5\\ =>x=5\)