\(10x+2^2.5=10^2\)

\(10x+4.5=100\)

\(10x+20=100\)

\(10x=100-20\)

\(10x=80\)

\(x=80:10\)

\(x=8\)

x = 8

Các bn giúp mình với mình đang cần gấp

nhiều quá bạn ơi , mk nghĩ bạn nên tách ra rồi hãy đăng lên

b) \(9x-2:3^2=3^4\)

\(9x-2:9=81\)

\(2:9=9x-81\)

\(\dfrac{2}{9}=9x-81\)

\(9x=81+\dfrac{2}{9}\)

\(9x=\dfrac{731}{9}\)

\(x=\dfrac{731}{9}:9\)

\(x=\dfrac{731}{81}\)

\(a.5x-5^2=10\)                        \(b.9x-2:3^2=3^4\)

\(5x=10+5^2\)                              \(9x-2=3^4.3^2\)

\(5x=35\)                                      \(9x-2=729\)

\(x=35:5=7\)                             \(9x=729+2=731\)

                                                    \(x=731:9\)

                                                     \(x=\dfrac{731}{81}\)

\(c=10x+\left(2^2\right).5=10^2\)

\(10x+20=100\)

\(10x=100-20\)

\(10x=80\)

\(x=80:10=8\)

10x+2^2x5=10^2

10x+4x5=100

10x+20=100

10x=100-20=80

x=80:10=8

10x + 2² x 5 = 10²

=> 10x + 4 x 5 = 100

=> 10x + 20 = 100

=> 10x = 100 - 20

=> 10x = 80

=> x = 80 : 10

=> x = 8

k  mk đi rồi mk giải cho

giúp mình đi mà

sai đề 

10X=124416^2

X=124416^2/10

\(a,80-\left(10x-5\right)=45\\ \Rightarrow80-10x+5=45\\ \Rightarrow-10x=-40\\ \Rightarrow x=4\)

\(b,\left(x+1\right)\left(x-2\right)=0\\ \Rightarrow\left[{}\begin{matrix}x+1=0\\x-2=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=-1\\x=2\end{matrix}\right.\)

\(c,\left|5+5x\right|=2^2.5\\ \Rightarrow\left|5+5x\right|=20\\ \Rightarrow\left[{}\begin{matrix}5+5x=20\\5+5x=-20\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}5x=15\\5x=-25\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=3\\x=-5\end{matrix}\right.\)

\(d,-10-\left(-5\right)+\left(3-x\right)=-8\\ \Rightarrow-10+5+3-x=-8\\ \Rightarrow-x=-6\\ \Rightarrow x=6\)

a) 80-(10x-5)=45

=> 80 - 10 x + 5 =45

=>-10x = -40

=>x=4

b)(x+1)×(x-2)=0

\(\Rightarrow\left[{}\begin{matrix}x+1=0\\x=2+0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-1\\x=2\end{matrix}\right.\)

c) |5+5x|=2^2×5

=>|5+5x|=20

\(\Rightarrow\left[{}\begin{matrix}5+5x=-20\\5+5x=20\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-5\\x=3\end{matrix}\right.\)

d) -10-(-5)+(3-x)=-8

=>-10+5 +3-x=-8

=>2+x=8

=>x=6

(x+1) + (2x+2) + (3x+3) + ...+ (10x+10) = 550

( x + 2x + 3x + ...+ 10x) + (1+2+3+..+10) = 550

x.(1+2+3+...+10) + 55 = 550

x.55 + 55 = 550

55.(x+1) = 550

x+ 1 = 10

x = 9

(x+1)+(2x+2)+.....+(10x+10)=550

x+1+2x+2+...+10x+10=550

(x+2x+3x+...+10x)+(1+2+3+4+...+10)=550

x nhân (1+2+3+...+10)+1 nhân (1+2+3+...+10)=550

(1+2+3+...+10) nhân (x+1)=550

55 nhân (x+1)=550 =>x+1=550:55=10

                                                 x   =9

nk nghĩ v,hc tốt