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\(56.\left(15+23\right)-15.\left(23+56\right)\)
\(=\left(56.15+56.23\right)-\left(15.23+15.56\right)\)
\(=56.15+56.23-15.23-15.56\)
\(=\left(56.15-56.15\right)+\left(56.23-15.23\right)\)
\(=0.\left[23.\left(56-15\right)\right]\)
\(=23.41\)
\(=943\)
a) 56.[ 15 + 23 ] - 15.[ 23 + 56 ]
= 56. 38 - 15. 79
= 2128 - 1185
= 943
b) 12.[ 47 - 23 ] + 23. [12 + 47]
= 12 . 24 + 23. 59
= 288 + 1357
= 1645
~ chúc bạn hok tốt nha ~ ^_^
\(445-52+155+452\\ =\left(445+155\right)+\left(452-52\right)\\ =600+4000\\ =1000\\ 102\cdot55-102\cdot73+51\cdot36\\ =102\cdot\left(55-73\right)+51\cdot36\\ =102\cdot\left(-18\right)+102\cdot18\\ =0\\ 4\cdot5\cdot2\cdot25\cdot5-1000\\ =5000-1000\\ =4000\\ 8782-291\cdot13\\ =4999\\ 254+\left\{38\cdot\left[\left(42-16\right):2\right]\right\}\\ =254+\left[38\cdot\left(26:2\right)\right]\\ =254+\left(38\cdot13\right)\\ =748\\ \left(2791\cdot34+7882:14\right)\cdot0+1510-510:2\\ =1510-255\\ =1255\)
a. \(445-52+155+452=\left(445+155\right)+\left(452-52\right)=600+400=1000\)
b. \(102\cdot55-102\cdot73+51\cdot36=102\left(55-73+18\right)=102\cdot0=0\)
c.\(4\cdot5\cdot2\cdot25\cdot5-1000=4\cdot25\cdot5\cdot5\cdot2-1000=100\cdot50-1000=5000-1000=4000\)
d. \(8782-291\cdot13=8782-3783=4999\)
e. \(254+\left\{38\left[\left(42-16\right)\div2\right]\right\}=254+\left\{30\cdot13\right\}=254+494=748\)
f. \(\left(2791\cdot34+7882\div14\right)\cdot0+1510-510\div2=0+1510-255=1255\)\
3 x ( X -18) +23 = 59
3 x ( X -18 ) = 59 - 23
3 x ( X - 18) = 36
X - 18 = 36 : 3
X - 18 = 12
X = 12 + 18
X = 30
k nha
3x(x-180+23=59
3x-18=59-23
3x-18=36
3x=36+18
3x=54
x=54:3
x=18
Vậy x=18
Bài làm :
\(a,2.x-3=185\)
\(2.x=185+3\)
\(2.x=188\)
\(x=94\)
\(b,357-\left(2.x-23\right)=122\)
\(2.x-23=357-122\)
\(2.x-23=235\)
\(2.x=258\)
\(x=129\)
\(c,152+\left(x+231\right):2=358\)
\(\left(x+231\right):2=358-152\)
\(\left(x+231\right):2=206\)
\(x+231=412\)
\(x=181\)
Học tốt nhé
x - 4867 = (175 . 2 - 5 . 70): 25 .23
x - 4867 = ( 52.7.2 - 52.7.2) : 25.23
x - 4867 = 0 : 25 . 23 = 0
x = 0 + 4867
x=4867.
\(x\left(x+y+z\right)=10\) (1)
\(y\left(y+z+x\right)=25\) (2)
\(z\left(z+x+y\right)=-10\) (3)
Lấy (1) + (2) + (3) theo vế ta có:
\(x\left(x+y+z\right)+y\left(y+z+x\right)+z\left(z+x+y\right)=10+25-10\)
\(\Leftrightarrow\)\(\left(x+y+z\right)^2=25\)
\(\Leftrightarrow\)\(x+y+z=\pm\sqrt{25}=\pm5\)
Nếu \(x+y+z=5\) thì: \(\hept{\begin{cases}x=2\\y=5\\z=-2\end{cases}}\)
Nếu \(x+y+z=-5\)thì \(\hept{\begin{cases}x=-2\\y=-5\\z=2\end{cases}}\)
Vậy...