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/-28/ + (129 - 182 + 99) - (129 + 199 - 182)
= 28 + 129 - 182 + 99 - 129 - 199 + 182
= 129 - 129 + 182 - 182 + 99 - 199 + 28
= 0 + 0 + (-100) + 28
= -72
\(\left|-28\right|+\left(129-182+99\right)-\left(129+199-182\right)\)
\(=28+129-182+99-129-199+182\)
\(=28+129+\left(-182\right)+99+\left(-129\right)+\left(-199\right)+182\)
\(=\text{ }\left[129+\left(-129\right)\right]+\text{ }\left[\left(-182\right)+182\right]+\text{ }\left[99+\left(-199\right)\right]+28\)
\(=0+0+\left(-100\right)+28\)
\(=\left(-100\right)+28\)
\(=-72\)
a)
\(-68+\left(-72\right)+2017+\left(-28\right)+168.\)
\(=\left(-68+168\right)+\left(-28-72\right)+2017.\)
\(=\left(168-68\right)+\text{ }\left[-\left(72+28\right)\right]+2017.\)
\(=100+\left(-100\right)+2017.\)
\(=100-100+2017.\)
\(=2017\)
b)
\(\left|-28\right|+\left(129-182+99\right)\)\(-\left(129+199-182\right)\)
\(=28+129-182+99\)\(-129-199+182.\)
\(=28+\left(129-129\right)+\left(182-182\right)\)\(-\left(199-99\right)\)
\(=28+0+0-100.\)
\(=-\left(100-28\right)\)
\(=-72\)
c)
\(17\left(-83\right)+18\times83.\)
\(=-17\left(83\right)+18\left(83\right)\)
\(=83\left[18+\left(-17\right)\right]\)
\(=83\left(18-17\right)\)
\(=83\left(1\right)\)
\(=83\)
d)
\(2018^0-\left(15^2\div\left[175+\left(2^3\times5^2-6\times25\right)\right]\right).\text{ }\)
\(=1-\left(15^2\div\left[175+\left(8\times25-6\times25\right)\right]\right)..\)
\(=1-\left(15^2\div\left[175+\left(25\left[8-6\right]\right)\right]\right)\)
\(=1-\frac{15^2}{175+\left(25\times2\right)}.\)
\(=1-\frac{15^2}{175+50}\)
\(=1-\frac{225}{225}\)
\(=1-1\)
\(=0\)
Học tốt
a) (-68) + (-72) + 2017 + (-28) + 168
= (-68 + 168) + [(-72) + (-28)] + 2017
= 100 + (-100) + 2017
= 0 + 2017
= 2017
-129 - 72 - { -29 } + {-28 } + 2017
= -129 - 72 + 29 - 28 + 2017
= {-129 - 72 } + { 29 - 28 } + 2017
= {-129 + 29 } - { 72 + 28 } + 2017
= { 129 - 29 } - 100 +2017
= 100 -100 + 2017
= 0 + 2017
= 2017
\(=\dfrac{29}{22}+\dfrac{41}{44}+\dfrac{33}{52}+\dfrac{73}{182}\)
\(=\dfrac{58+41}{44}+\dfrac{33}{52}+\dfrac{73}{182}\)
\(=\dfrac{9}{4}+\dfrac{33}{52}+\dfrac{73}{182}=\dfrac{23}{7}\)
A=(13+132)+(133+134)+.......................+(1399+13100)
A=1.(13+132)+132.(13+132)+..............+1398.(13+132)
A=1.182+132.182+..........................+1398.182
A+182.(1+132+..............+1398) Chia hết cho 182
--> A chia hết cho 182
Đầu tiên: Rút gọn từng số hạng của A
Tiếp theo: Nhóm lại
Cuối cùng: Ra đáp án
A = 16/9 + 11/9 +9/11 +17/33 +11/39 + 2/13
A= (16/9+11/9) + (9/11+17/33) + (11/39+2/13)
A=3+4/3+17/39=62/13
\(\left|-28\right|+\left(129-182+99\right)-\left(129+199-182\right)\\ =28+129-182+99-129-199+182\\ =28+\left(129-129\right)+\left(182-182\right)+\left(99-199\right)\\ =28-100=-72\)
Ta có: