\(\left(x+1\right)^3=2^3.3+3\)

\(\Rightarrow\left(x+1\right)^3=24+3=27=3^3\)

\(\Rightarrow x+1=3\Rightarrow x=2\)

\(5+2.3^x+2=23\)

\(\Rightarrow7+2.3^x=23\)

\(\Rightarrow2.3^x=23-7=16\)

\(\Rightarrow3^x=8.\)

Mà số 3 lũy thừa mấy cũng không thể bằng 8 => x không thỏa mãn.

a) 32-6.(8-2³)+18

= 32 - 6 . (8 - 8) +18

=32 - 0 +18

= 50

b) (3.5-9)³.(1+2.3)²+4²

= (15-9 )³. (1+6)² + 4 ²

= 6³ . 7 ² + 4²

= 216 x 49 + 16

= 10584 + 16

=10600

c) 9234:[3.3.(1+8³)]

= 9234 : [ 3.3.9³]

= 9234 : [ 3.3 . 729]

= 9234 :6561

= 1,407407407

d) 76- {2.[2.5²-(31-2.3)]}+3.25

= 76 - { 2. [ 2.5² - ( 31 - 6)]} + 3.25

= 76 - { 2 . [ 2. 5² - 25 ]} + 3 .25

= 76 - { 2 . [2. 25 - 25]} + 3.25

= 76 - { 2.[ 50 - 25 ]} + 3.25

= 76 - { 2. 25} + 3 . 25

= 76 - 50 + 3. 25

= 76 - 50 + 75

= 101

1.6

2.6

3.0

huhu júp mình đi các bạn @@@@@@

\(\left(2x+1\right)^3=125\\ \Rightarrow\left(2x+1\right)^3=5^3\\ \Rightarrow2x+1=5\\ \Rightarrow2x=4\\ \Rightarrow x=2.\\ b,\left(2x-1\right)^4=16\\ \Rightarrow\left(2x-1\right)^4=2^4\\ \Rightarrow2x-1=2\\ \Rightarrow2x=3\\ \Rightarrow x=\dfrac{3}{2}.\\ c,6.3^x-2.3^x=36\\ \Rightarrow3^x.\left(6-2\right)=36\\ \Rightarrow3^x.4=36\\ \Rightarrow3^x=9\\ \Rightarrow3^x=3^2\\ \Rightarrow x=2.\\ d,2^{x+1}-2^x=32\\ \Rightarrow2^x.\left(2-1\right)=32\\ \Rightarrow2^x=2^5\\ \Rightarrow x=5.\)

ƯCLN(2^3*3^a;2^b*3^5)=2^2*3^5 nên b=2 và a<=5

BCNN(2^3*3^a;2^2*3^5)=2^3*3^6 nên a=6

b Ta có

3^x+2+3^x=10

=>3^x(3^2+1)=10

=>3^x.10=10

=>3^x=1

=>x=0 ( tick nhé)

\(a,9234:\left[3\cdot3\cdot\left(1+8^3\right)\right]\\ =9234:\left[9\cdot\left(1+512\right)\right]\\ =9234:\left(9\cdot513\right)\\ =9234:4617\\ =2\\ b,76-\left\{2\cdot\left[2\cdot5^2-\left(31-2\cdot3\right)\right]\right\}+3\cdot25\\ =76-\left\{2\cdot\left[2\cdot25-\left(31-6\right)\right]\right\}+75\\ =76-\left[2\cdot\left(50-25\right)\right]+75\\ =76-\left(2\cdot25\right)+75\\ =76-50+75\\ =26+75\\ =-49\)

e) 96-5(2x-1)=41

5(2x-1)= 96-41

5(2x-1)=55

2x-1=55:5

2x-1=11

2x=11+1

2x=12

x=12:2

x=6

sao có 1 câu zị bn:)?