a) \(x-\dfrac{3}{4}=6\times\dfrac{3}{8}\)

\(x-\dfrac{3}{4}=\dfrac{9}{4}\)

=> \(x=\dfrac{9}{4}+\dfrac{3}{4}=3\)

b) \(\dfrac{7}{8}:x=3-\dfrac{1}{2}\)

\(\dfrac{7}{8}:x=\dfrac{5}{2}\)

=> \(x=\dfrac{7}{8}:\dfrac{5}{2}=\dfrac{7}{20}\)

c) \(x+\dfrac{1}{2}\times\dfrac{1}{3}=\dfrac{3}{4}\)

\(x+\dfrac{1}{6}=\dfrac{3}{4}\)

=> \(x=\dfrac{3}{4}-\dfrac{1}{6}=\dfrac{7}{12}\)

d) \(\dfrac{3}{2}\times\dfrac{4}{5}-x=\dfrac{2}{3}\)

\(\dfrac{6}{5}-x=\dfrac{2}{3}\)

=> \(x=\dfrac{6}{5}-\dfrac{2}{3}=\dfrac{8}{15}\)

e) \(x\times3\dfrac{1}{3}=3\dfrac{1}{3}:4\dfrac{1}{4}\)(?)

\(x\times\dfrac{10}{3}=\dfrac{40}{51}\)

=> \(x=\dfrac{40}{51}:\dfrac{10}{3}=\dfrac{4}{17}\)

f) \(5\dfrac{2}{3}:x=3\dfrac{2}{3}-2\)

\(\dfrac{17}{3}:x=\dfrac{5}{3}\)

=> \(x=\dfrac{17}{3}:\dfrac{5}{3}=\dfrac{17}{5}\)

a: =>x-3/4=18/8=9/4

=>x=9/4+3/4=12/4=3

b: =>7/8:x=5/2

=>x=7/8:5/2=7/8*2/5=14/40=7/20

c: x+1/2*1/3=3/4

=>x+1/6=3/4

=>x=3/4-1/6=9/12-2/12=7/12

d: =>12/10-x=2/3

=>6/5-x=2/3

=>x=6/5-2/3=18/15-10/15=8/15

e: =>x*10/3=10/3:17/4=10/3*4/17

=>x=4/17

f: =>17/3:x=13/3-5/2=26/6-15/6=11/6

=>x=17/3:11/6=17/3*6/11=34/11

\(a,\dfrac{-1}{8}=\dfrac{3}{x}\\ \dfrac{3}{-24}=\dfrac{3}{x}\\ x=-24\\ b,\dfrac{x}{3}=\dfrac{3}{x}\\ x.x=3.3\\ x^2=9\\ x=\pm3\\ c,\dfrac{3}{4}.x=1\dfrac{1}{2}\\ \dfrac{3}{4}.x=\dfrac{3}{2}\\ x=\dfrac{3}{2}:\dfrac{3}{4}\\ x=2\\ d,x-\dfrac{3}{10}=\dfrac{7}{15}:\dfrac{3}{5}\\ x-\dfrac{3}{10}=\dfrac{7}{9}\\ x=\dfrac{7}{9}+\dfrac{3}{10}\\ x=\dfrac{97}{90}\\ e,\dfrac{-4}{7}-x=\dfrac{-8}{3}.\dfrac{3}{7}\\ \dfrac{-4}{7}-x=\dfrac{-8}{7}\\ x=\dfrac{-4}{7}+\dfrac{8}{7}\\ x=\dfrac{4}{7}\\ \)

fan liver tốt ghê

a) \(\dfrac{5}{8}-\left(x+\dfrac{3}{4}\right)=\dfrac{7}{6}\)

     \(-x-\dfrac{3}{4}=\dfrac{13}{24}\)

    \(-x=\dfrac{31}{24}\)

\(\Rightarrow x=\dfrac{-31}{24}\)

b) \(\left(x-\dfrac{3}{4}\right)+\dfrac{3}{2}=\dfrac{11}{3}\)

    \(x-\dfrac{3}{4}=\dfrac{13}{6}\)

    \(x=\dfrac{35}{12}\)

c) \(\left(x+\dfrac{1}{2}\right)-\dfrac{5}{8}=2\)

    \(x+\dfrac{1}{2}=\dfrac{21}{8}\)

    \(x=\dfrac{17}{8}\)

d) \(\dfrac{11}{2}-\left(\dfrac{4}{5}+x\right)=2-\dfrac{1}{3}\)

    \(\dfrac{11}{2}-\left(\dfrac{4}{5}+x\right)=\dfrac{5}{3}\)

    \(-\dfrac{4}{5}-x=\dfrac{-23}{6}\)

    \(-x=\dfrac{-91}{30}\)

\(\Rightarrow x=\dfrac{91}{30}\) 

`5/8-(x+3/4)=7/6`

`=> x+3/4 = 5/8 -7/6`

`=> x+3/4 = -13/24`

`=>x= -13/24 -3/4`

`=>x= -13/24 - 18/24`

`=>x= -31/24`

`-----------`

`(x-3/4)+3/2+11/3`

`=11/3` hả bn?

`----------`

`(x+1/2)-5/8=2`

`=>x+1/2=2+5/8`

`=>x+1/2= 16/8+5/8`

`=> x+1/2=21/8`

`=>x=21/8-1/2`

`=>x= 21/8 - 4/8`

`=>x= 17/8`

`---------`

`11/2-(4/5+x)=2-1/3`

`=> 11/2-(4/5+x)=6/3-1/3`

`=> 11/2-(4/5+x)=5/3`

`=>4/5+x=11/2-5/3`

`=>4/5+x=23/6`

`=>x=23/6-4/5`

`=>x= 91/30`

=11/3 nha mk ghi nhầm

a)x-5=7

=> x=9

b)2.x+6=24

=>2x=18

=>x=9

Tìm x :

a) \(x-5=49:7\)

\(\Leftrightarrow x-5=7\)

\(\Leftrightarrow x=7+5\)

\(\Leftrightarrow x=12\)

Vậy : \(x=12\)

b) \(2x+6=24\)

\(\Leftrightarrow2x=24-6=18\)

\(\Leftrightarrow x=18:2\)

\(\Leftrightarrow x=9\)

Vậy : \(x=9\)

c) \(\frac{1}{3}:x+\frac{1}{2}=5\)

\(\Leftrightarrow\frac{1}{3}:x=5-\frac{1}{2}=\frac{9}{5}\)

\(\Leftrightarrow x=\frac{1}{3}:\frac{9}{5}\)

\(\Leftrightarrow x=\frac{5}{27}\)

Vậy : \(x=\frac{5}{27}\)

d) \(\frac{1}{6}.x-\frac{1}{3}=2\)

\(\Leftrightarrow\frac{1}{6}.x=2-\frac{1}{3}=\frac{5}{3}\)

\(\Leftrightarrow x=\frac{5}{3}:\frac{1}{6}\)

\(\Leftrightarrow x=10\)

Vậy : \(x=10\)

e) \(\frac{x}{27}=\frac{3}{x}\)

\(\Leftrightarrow x.x=27.3\)

\(\Leftrightarrow x^2=81\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-9\\x=9\end{matrix}\right.\) mà \(x\in N\)

\(\Rightarrow x=9\)

Vậy : \(x=9\)

g) \(1200:24-\left(17-x\right)=36\)

\(\Leftrightarrow50-17+x=36\)

\(\Leftrightarrow33+x=36\)

\(\Leftrightarrow x=36-33\)

\(\Leftrightarrow x=3\)

Vậy : \(x=3\)

h) \(674-\left(12+x\right)=427\)

\(\Leftrightarrow12+x=674-427=247\)

\(\Leftrightarrow x=247-12\)

\(\Leftrightarrow x=230\)

Vậy : \(x=230\)

k) \(36.\left(x-9\right)=900\)

\(\Leftrightarrow x-9=900:36\)

\(\Leftrightarrow x-9=25\)

\(\Leftrightarrow x=25+9\)

\(\Leftrightarrow x=34\)

m) \(1,2:x+3,8:x=2,5\)

\(\Leftrightarrow\left(1,2-3,8\right):x=2,5\)

\(\Leftrightarrow-2,6:x=2,5\)

\(\Leftrightarrow x=\frac{-2,6}{2,5}=-\frac{26}{25}\)

Vậy : \(x=-\frac{26}{25}\)

n) \(\left(\frac{1}{2.4}+\frac{1}{4.6}+\frac{1}{6.8}+\frac{1}{8.10}\right).x=\frac{1}{3}\)

\(\Leftrightarrow\frac{1}{2}.\left(\frac{2}{2.4}+\frac{2}{4.6}+\frac{2}{6.8}+\frac{2}{8.10}\right).x=\frac{1}{3}\)

\(\Leftrightarrow\left[\frac{1}{2}.\left(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+\frac{1}{8}-\frac{1}{10}\right)\right].x=\frac{1}{3}\)

\(\Leftrightarrow\left[\frac{1}{2}.\left(1-\frac{1}{10}\right)\right].x=\frac{1}{3}\)

\(\Leftrightarrow\frac{1}{2}.\frac{9}{10}.x=\frac{1}{3}\)

\(\Leftrightarrow\frac{9}{20}.x=\frac{1}{3}\)

\(\Leftrightarrow x=\frac{1}{3}:\frac{9}{20}\)

\(\Leftrightarrow x=\frac{20}{27}\)

Vậy : \(x=\frac{20}{27}\)

Lời giải:

1. $(x+2)-2=0$

$x+2=2$

$x=0$

2.

$(x+3)+1=7$

$x+3=7-1=6$

$x=6-3=3$

3.

$(3x-4)+4=12$

$3x-4+4=12$

$3x=12$

$x=12:3=4$

4.

$(5x+4)-1=13$

$5x+4=13+1=14$

$5x=14-4=10$

$x=10:5=2$

5.

$(4x-8)-3=5$

$4x-8=5+3=8$

$4x=8+8=16$

$x=16:4=4$

6.

$3+(x-5)=7$

$x-5=7-3=4$

$x=4+5=9$

7.

$8-(2x-4)=2$

$2x-4=8-2=6$

$2x=6+4=10$

$x=10:2=5$

8.

$7+(5x+2)=14$

$5x+2=14-7=7$

$5x=7-2=5$

$x=5:5=1$

9.

$5-(3x-11)=1$

$3x-11=5-1=4$

$3x=11+4=15$

$x=15:3=5$

10.

$16-(8x+2)=6$

$8x+2=16-6=10$

$8x=10-2=8$

$x=8:8=1$

`(x - 2)/3 = (x + 1)/4`

`(x - 2) . 4 = (x + 1) . 3`

`<=> 4x - 8 = 3x + 3`

`<=> 4x - 3x = 3 + 8`

`<=> (4 - 3)x = 11`

`=> x = 11`

`=>` `x = 11`

???

a) \(x-\dfrac{3}{4}=6.\dfrac{3}{8}=\dfrac{9}{4}\)

\(\Rightarrow x=\dfrac{9}{4}+\dfrac{3}{4}=3\)

c) \(x+\dfrac{1}{2}.\dfrac{1}{3}=\dfrac{3}{4}\)

\(\Rightarrow x+\dfrac{1}{6}=\dfrac{3}{4}\Rightarrow x=\dfrac{3}{4}-\dfrac{1}{6}=\dfrac{9}{12}-\dfrac{2}{12}=\dfrac{7}{12}\)

Bạn xem lại đề c

Xin lỗi, bạn xem lại đề b

\(\dfrac{3}{2}x-0,2=\dfrac{3}{5}\)

\(\dfrac{3}{2}x-\dfrac{1}{5}=\dfrac{3}{5}\)

\(\dfrac{3}{2}x=\dfrac{3}{5}+\dfrac{1}{5}\)

\(\dfrac{3}{2}x=\dfrac{4}{5}\)

   \(x=\dfrac{4}{5}:\dfrac{3}{2}\)

   \(x=\dfrac{4}{5}\cdot\dfrac{2}{3}\)

   \(x=\dfrac{8}{15}\)

\(\dfrac{1}{3}+x=\dfrac{3}{4}\)

        \(x=\dfrac{3}{4}-\dfrac{1}{3}\)

        \(x=\dfrac{9}{12}-\dfrac{4}{12}\)

        \(x=\dfrac{5}{12}\)

\(1\dfrac{1}{2}x-\dfrac{2}{5}=\dfrac{1}{4}\)

\(\dfrac{3}{2}x-\dfrac{2}{5}=\dfrac{1}{4}\)

\(\dfrac{3}{2}x=\dfrac{1}{4}+\dfrac{2}{5}\)

\(\dfrac{3}{2}x=\dfrac{13}{20}\)

   \(x=\dfrac{13}{20}:\dfrac{3}{2}\)

   \(x=\dfrac{13}{20}\cdot\dfrac{2}{3}\)

   \(x=\dfrac{13}{30}\)

\(\dfrac{11}{8}-\dfrac{3}{8}\cdot x=\dfrac{1}{8}\)

          \(\dfrac{3}{8}\cdot x=\dfrac{11}{8}-\dfrac{1}{8}\)

          \(\dfrac{3}{8}\cdot x=\dfrac{5}{4}\)

                \(x=\dfrac{5}{4}:\dfrac{3}{8}\)   

                \(x=\dfrac{5}{4}\cdot\dfrac{8}{3}\)

                \(x=\dfrac{10}{3}\)