Tìm x:

a) \(2x-12-x=0\)

\(2x-x=12\)

\(x=12\)

b) \(2x+69\cdot2=69\cdot4\)

\(2x=69\cdot4-69\cdot2\)

\(2x=69\cdot2\)

\(x=69\cdot2:2\)

\(x=69\)

Tính nhanh:

\(769\cdot85-769-75=769\cdot84-75\)

(sao tính nhanh được)

a) 2*x - 12- x = 0

 2*x - x - 12 = 0

 x * ( 2 - 1) - 12 = 0

 x = 12

b) 2 * x + 69 *2 = 69 * 4

    2 * ( x + 69 ) = 276

           x + 69   = 276/2

           x + 69   = 138

           x          = 69

769 * 85 - 769 - 75

= 769*(85-75)

=769*10

=7690

2 x X + 69 x 2 = 69 x 4

2 x X = 69 x (4 - 2)

2 x X =  69 x 2

=> X = 2

2 x (-12) - X = 0

-24 - X = 0

X = -24 - 0

X = -24

96 - 3 x (X + 1) = 42

3 x (X + 1) = 96 - 42

3 x (X +1) = 54

X + 1 = 54 : 3

X + 1 = 17

X = 17 -1

X = 16

chúc bạn học tốt nha

ủng hộ mk với nha

Mk viết dấu nhân là dấu . nhé

a, 2x + 69.2 = 69.4

➡️2x + 138 = 276

➡️2x = 276 - 138 

➡️2x = 138

➡️x = 138 ÷ 2 = 69

Vậy x = 69.

b, 2 .( -12) - x = 0

➡️- 24 - x = 0

➡️x = - 24

Vậy x = - 24.

c, 96 - 3( x + 1) = 42

➡️3( x + 1) = 96 - 42 

➡️3( x + 1) = 54

➡️x + 1 = 54 ÷ 3 

➡️x + 1 = 18

➡️x = 18 - 1 = 17

Vậy x = 17

Còn cái bài tính nhanh đó để mk nghĩ đã nhé.

câu hỏi hay......nhưng tui xin nhường cho các bn khác

Hãy tích đúng cho tui nha

THANKS

12 -x nhe mình quên

\(2\times x+69\times2=69\times4\)

\(2\times\left(x+69\right)=276\)

\(x+69=276:2\)

\(x+69=138\)

\(x=138-69\)

\(x=69\)

b) \(2\times x-12=0\)

    \(2\times x=0+12\)

    \(2\times x=12\)

     \(x=12:2\)

     \(x=6\)

uh là nhân

a) \(=\dfrac{254x\left(400-1\right)-145}{254+\left(400-1\right)x253}=\dfrac{254x400-254-145}{254+253x400-253}\)

\(=\dfrac{101600-399}{101200+1}=\dfrac{101211}{101201}=\dfrac{101201+10}{101201}=1+\dfrac{10}{101201}\)

b) \(=\dfrac{5392+\left(600+1\right)x5391}{5392x\left(600+1\right)-69}=\dfrac{5392+600x5391+5391}{5392x600+5392-69}\)

\(=\dfrac{10783+3234600}{3235200+5323}=\dfrac{\text{3245383}}{\text{3240523}}=\dfrac{3240523+60}{3240523}=1+\dfrac{60}{3240523}\)

c) \(=\dfrac{1}{2}x\left(\dfrac{1}{2}-\dfrac{1}{4}\right)+\dfrac{1}{2}x\left(\dfrac{1}{4}-\dfrac{1}{8}\right)+\dfrac{1}{32}\)

\(=\dfrac{1}{2}x\left(\dfrac{1}{2}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{8}\right)+\dfrac{1}{32}\)

\(=\dfrac{1}{2}x\left(\dfrac{1}{2}-\dfrac{1}{8}\right)+\dfrac{1}{32}=\dfrac{3}{16}+\dfrac{1}{32}=\dfrac{7}{32}\)

=498525

498525

1. A

2.A

( ko chắc đâu )

1A 2C 

ai nhanh nhất mình k cho

Bài 1:

\(A=\frac{1}{\left(1+2\right)}+\frac{1}{\left(1+2+3\right)}+\frac{1}{\left(1+2+3+4\right)}\)\(+\frac{1}{\left(1+2+3+4+5\right)}+...+\)\(\frac{1}{\left(1+2+3+...+10\right)}\)

\(A=\frac{1}{3}+\frac{1}{6}+....+\frac{1}{55}\)

\(A=2\left(\frac{1}{6}+\frac{1}{12}+....+\frac{1}{110}\right)\)

\(A=2\left(\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{10.11}\right)\)

\(A=2\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+....+\frac{1}{10}-\frac{1}{11}\right)\)

\(A=2.\left(\frac{1}{2}-\frac{1}{11}\right)\)

\(A=\frac{9}{11}\)

Bài 2 :

2)  Tử số = 11 x 13 x 15 + 3 x 3 x 3 x 11 x 13 x 15 + 5 x 5 x 5 x 11 x 13 x 15 + 9 x 9 x 9 x 11 x 13 x 15

= (1 + 3 x 3 x 3 + 5 x 5 x 5 + 9 x 9 x9) x 11 x 13 x 15 = (1+27+125+ 729) x 11 x 13 x 15

Mẫu số =  11 x 13 x 17 + 3 x 3 x 3 x 13 x 15 x 19  + 5 x 5 x 5 x 13 x 15 x 17 + 9 x 9 x 9 x 13 x 15 x 17 lớn hơn 11 x 13 x 15 + 3 x 3 x 3 x 13 x 15 x 17 + 5 x 5 x 5 x 13 x 15 x 17 + 9 x 9 x 9 x 13 x 15 x 17  

=  (1 + 3 x 3 x 3 + 5 x 5 x 5 + 9 x 9 x9) 13 x 15 x  17 = (1+27+125+729) x 13 x 15 x 17 

\(\Rightarrow A< \frac{\left(1+27+125+729\right)\times11\times13\times15}{\left(1+27+125+729\right)\times13\times15\times17}\)

\(=\frac{11}{17}\)

\(=\frac{1111}{1717}=B\)

Vậy \(A=B\)

a​, => x-12 = 0

 => x=12

b, => 27-x =1

=> x= 27-1 -26

c, => 2x = 69(4-2) =69.2

=> x=69

d, => x-12=0

=> x=12

a) (x - 12) . 105 = 0

=> x - 12 = 0

=> x = 12

b) 47 . (27 - x) = 47

=> 27 - x = 1

=> x = 27 - 1 = 26

c) 2x + 69 . 2 = 69 . 4

=> 2x = 69 . 4 - 69 . 2

=> 2x = 69 . (4 - 2) = 69 . 2

=> x = 69 . 2 : 2

=> x = 69

d) 2x - 12 - x = 0

=> x - 12 = 0

=> x = 12