a) $34-29+(-14)+129-(-114)$

$=34-29-14+129+114$

$=34+(129-29)+(114-14)$

$=34+100+100$

$=234$

b) $27\cdot(-35)+(-27)\cdot64-27$

$=(-27)\cdot35+(-27)\cdot64+(-27)\cdot1$

$=(-27)\cdot(35+64+1)$

$=(-27)\cdot(99+1)$

$=(-27)\cdot100$

$=-2700$

c) $160-(4\cdot5^2-3\cdot2^3)\cdot2-(-12)$

$=160-(4\cdot25-3\cdot8)\cdot2+12$

$=160-(100-24)\cdot2+12$

$=160-76\cdot2+12$

$=160-152+12$

$=160-(152-12)$

$=160-140$

$=20$

a, 34 - 29 + (-14) + 129 - (-114)

= 34 + (129 - 29) + (114  - 14)

= 34 + 100 + 100

= 234

b, 27.(-35) + (-27).64 - 27

= (-27).(35 + 64 + 1)

= - 27 . 100

= - 2700

c, 160 - (4.5² - 3.2³).2 - (-12)

= 160 - (4.25 - 3.8).2 + 12

=  160 - (100 - 24).2 + 12

=  160 - 76.2 + 12

= 160 - 152 + 12

= 8 + 12

= 20 

Bài 3:

a) \(159-\left(25-x\right)=43\)

\(\Rightarrow25-x=159-43\)

\(\Rightarrow25-x=116\)

\(\Rightarrow x=25-116\)

\(\Rightarrow x=-91\)

b) \(\left(79-x\right)-43=-\left(17-52\right)\)

\(\Rightarrow\left(79-x\right)-43=-\left(-35\right)\)

\(\Rightarrow79-x=35+43\)

\(\Rightarrow79-x=78\)

\(\Rightarrow x=79-78\)

\(\Rightarrow x=1\)

c) \(-\left(-x+13-142\right)+18=55\)

\(\Rightarrow-\left(-x+13-142\right)=55-18\)

\(\Rightarrow x-13+142=37\)

\(\Rightarrow x+129=37\)

\(\Rightarrow x=37-129\)

\(\Rightarrow x=-92\)

\(\dfrac{4x}{3}=\dfrac{-8}{9}\)

\(4x=\dfrac{\left(-8\cdot3\right)}{9}\)

\(4x=-\dfrac{24}{9}\)

 \(x=-\dfrac{24}{9}\div4\)

 \(x=-\dfrac{24}{36}\)

 \(x=-\dfrac{2}{3}\)

| x - \(\frac{1}{2}\)| = 1

TH1:x - \(\frac{1}{2}\) = 1                                 TH2:x - \(\frac{1}{2}\) = -1

        x              = 1 + \(\frac{1}{2}\)                           x             = -1 + \(\frac{1}{2}\)

        x              = \(\frac{3}{2}\)                                 x             = \(\frac{-1}{2}\)

Vậy x thuộc \(\frac{3}{2}\)và \(\frac{-1}{2}\)

Trả lời:

\(a,\left|x-\frac{1}{2}\right|=1\)

\(\Leftrightarrow\orbr{\begin{cases}x-\frac{1}{2}=1\\x-\frac{1}{2}=-1\end{cases}\Leftrightarrow\orbr{\begin{cases}x=\frac{3}{2}\\x=-\frac{1}{2}\end{cases}}}\)

Vậy x = 3/2; x = - 1/2

\(2^{35}< 2^{36}=8^{12}\)

\(3^{24}=\left(3^2\right)^{12}=9^{12}\)

\(8^{12}< 9^{12}\)

=>\(2^{36}< 3^{24}\)

=>\(2^{35}< 3^{24}\)

tạm thời cái đề bài là tìm x vậy

tiếp tục thui

=) (6x-10)-(6x-3)\(⋮\)2x-1

=)6x-10-6x+3\(⋮\)2x-1

=) (6x-6x)-(10-3)\(⋮\)2x-1

=)0-7\(⋮\)2x-1

=)-7\(⋮\)2x-1=)2x-1\(\in\)Ư(-7)={-7;-1;1;7}

=)2x\(\in\){-6;0;2;8}

=)x\(\in\){-3;0;1;4}

\(=80-100+24=4\)

=55

3n + 4 = 3n - 6 + 10

= 3(n - 2) + 10

Để (3n + 4) ⋮ (n - 2) thì 10 ⋮ (n - 2)

⇒ n - 2 ∈ Ư(10) = {-10; -5; -2; -1; 1; 2; 5; 10}

⇒ n ∈ {-8; -3; 0; 1; 3; 4; 7; 12}

Mà n là số tự nhiên

⇒ n ∈ {0; 1; 3; 4; 7; 12}

a)\(\frac{18}{-5}.\frac{-5}{6}=\frac{18}{6}=3\)

c)\(\frac{115}{30}\div\frac{-5}{6}=\frac{115}{30}.\frac{6}{-5}=\frac{-23}{5}\)

d)\(-3x+\frac{1}{2}=3\)

\(-3x=3-\frac{1}{2}\)

\(-3x=\frac{5}{2}\)

\(x=\frac{5}{2}\div3\)

\(x=\frac{5}{6}\)

a)= 18/-5 . -5/6 , bỏ -5=3

c)= 115/30 : 5/6 = 23/6 :5/6 =23/6 . 6/5 bỏ 6 = 23/5

d) 3.x +1/2 = 3:

3.x = 3-1/2 =5/2

x  =5/2 : 3 = 5/6

nhanh con mẹ mày