a) Ta có: \(A=\dfrac{7}{12}+\dfrac{5}{12}:6-\dfrac{11}{36}\)

\(=\dfrac{7}{12}+\dfrac{5}{72}-\dfrac{11}{36}\)

\(=\dfrac{42}{72}+\dfrac{5}{72}-\dfrac{22}{72}\)

\(=\dfrac{25}{36}\)

b) Ta có: \(B=\left(\dfrac{4}{5}+\dfrac{1}{2}\right):\left(\dfrac{3}{13}-\dfrac{8}{13}\right)\)

\(=\left(\dfrac{8}{10}+\dfrac{5}{10}\right):\dfrac{-5}{13}\)

\(=\dfrac{13}{10}\cdot\dfrac{13}{-5}\)

\(=-\dfrac{169}{50}\)

c) Ta có: \(C=\left(\dfrac{2}{3}-\dfrac{1}{4}+\dfrac{5}{11}\right):\left(\dfrac{5}{12}+1-\dfrac{7}{11}\right)\)

\(=\left(\dfrac{88}{132}-\dfrac{33}{132}+\dfrac{60}{132}\right):\left(\dfrac{55}{132}+\dfrac{132}{132}-\dfrac{84}{132}\right)\)

\(=\dfrac{115}{132}\cdot\dfrac{132}{103}=\dfrac{115}{103}\)

mình cám ơn bạn rất nhiều ạ

`1a)-17/30-11/(-15)+(-14)/24`

`=-17/30+22/30+(-7)/12`

`=5/30+(-7)/12`

`=1/6-7/12=2/12-7/12=-5/12`

`1b)(-10)/11*4/7+(-10)/11*3/7+1 10/11`

`=(-10)/11*(4/7+3/7)+1+10/11`

`=-10/11+10/11+1=1`

`1c)(5/7*0,6-5:3 1/2).(40%-1,4).(-2)^3`

`=(5/7*3/5-5:7/2).(0,4-1,4).(-8)`

`=(3/7-10/7).(-1).(-8)`

`=8.(-1)=-8`

mình cảm ơn bạn rất nhiều ạ 

Bài 1:

a) \(\dfrac{4}{5}-\dfrac{7}{6}+\dfrac{-6}{15}=\dfrac{24}{30}-\dfrac{35}{30}+\dfrac{-12}{30}=\dfrac{24-35+-12}{30}=\dfrac{-23}{30}\) 

b) \(\dfrac{-5}{9}.\dfrac{7}{13}+\dfrac{6}{13}.\dfrac{-5}{9}+3\dfrac{7}{9}\) 

\(=\dfrac{-5}{9}.\left(\dfrac{7}{13}+\dfrac{6}{13}\right)+\dfrac{34}{9}\) 

\(=\dfrac{-5}{9}.1+\dfrac{34}{9}\) 

\(=\dfrac{-5}{9}+\dfrac{34}{9}\) 

\(=\dfrac{29}{9}\) 

c) \(6\dfrac{3}{8}-\left(4\dfrac{3}{8}-\dfrac{1}{2}\right)=\dfrac{51}{8}-\dfrac{35}{8}+\dfrac{1}{2}=\left(\dfrac{51}{8}-\dfrac{35}{8}\right)+\dfrac{1}{2}=2+\dfrac{1}{2}=\dfrac{5}{2}\) 

d) \(2\dfrac{1}{3}.1,5-\left(\dfrac{11}{10}+50\%\right):\dfrac{4}{15}\) 

\(=\dfrac{7}{3}.1,5-\dfrac{8}{5}:\dfrac{4}{15}\) 

\(=\dfrac{7}{2}-6\) 

\(=\dfrac{-5}{2}=-2,5\) 

`B=(2015+2016+2017)/(2016+2017+2018)`

`=2015/(2016+2017+2018)+2016/(2016+2017+2018)+2017/(2016+2017+2018)`

Vì `2015/(2016+2017+2018)<2015/2016`

`2016/(2016+2017+2018)<2016/2017`

`2017/(2016+2017+2018)<2017/2018`

`=>B<A`

Bài 5

B= \(\dfrac{2015}{2016+2017+2018}\)+\(\dfrac{2016}{2016+2017+2018}\)+\(\dfrac{2017}{2016+2017+2018}\)

Ta có:\(\dfrac{2015}{2016}\)>\(\dfrac{2015}{2016+2017+2018}\),\(\dfrac{2016}{2017}\)>\(\dfrac{2016}{2016+2017+2018}\),\(\dfrac{2017}{2018}\)>\(\dfrac{2017}{2016+2017+2018}\)

⇒A>B

ta nhân 3 cả hai vế, được : 

\(\left(\frac{3}{1.4}+\frac{3}{4.7}+\frac{3}{7.10}+...+\frac{3}{102.105}\right)x=3\)

hay 

\(\left(\frac{4-1}{1.3}+\frac{7-4}{4.7}+...+\frac{105-102}{102.105}\right)x=3\) \(\Leftrightarrow\left(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{10}+..+\frac{1}{102}-\frac{1}{105}\right)x=3\)

\(\Leftrightarrow\left(1-\frac{1}{105}\right)x=3\Leftrightarrow\frac{104}{105}.x=3\Leftrightarrow x=\frac{315}{104}\)

Mik nghĩ là dấu "-" chứ ko phải "+" bạn ak

125 x13-125 x87 

 = 125 x ( 13 - 87 ) 

 = 125 x ( -74 )

= -9250

a) Ta có: 3x-17=x+3

\(\Leftrightarrow3x-x=3+17\)

\(\Leftrightarrow2x=20\)

hay x=10

b) Ta có: \( \left|x-3\right|-12=\left|-5\right|\)

\(\Leftrightarrow\left|x-3\right|=17\)

\(\Leftrightarrow\left[{}\begin{matrix}x-3=17\\x-3=-17\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=20\\x=-14\end{matrix}\right.\)

Vậy: \(x\in\left\{20;-14\right\}\)

c) Ta có: \(25-\left(x-5\right)=-415-\left(15-415\right)\)

\(\Leftrightarrow25-x+5=-415-15+415\)

\(\Leftrightarrow30-x=-15\)

hay x=45

Vậy: x=45

3x - 17 = x + 3 

3x = x+3 +17 

3x = x+20

3x-x=20

2x = 20

x= 20:2

x = 10

b ) |x-3| -12 = |-5|

|x-3| = 12 + 5

|x-3|=17

\(\left[{}\begin{matrix}x-3=17\\x-3=-17\end{matrix}\right.\)   =>\(\left[{}\begin{matrix}x=17-3\\x=-17-3\end{matrix}\right.\)=>\(\left[{}\begin{matrix}x=14\\x=-20\end{matrix}\right.\)  

vậy x= 14 hoặc x= -20

c) 25 -(x-5) = -415 -(15-145)

25-(x-5) = 15

x-5 = 25 -15

x-5 = 10

x = 10 - 5

x = 5

341 x 67 + 341 x 16 + 659 x 83

= 341 x ( 67 + 16 ) + 659 x 83

= 341 x 83 + 659 x 83

= 83 x ( 341 + 659 )

= 83 x 1000

= 83000

Học tốt nhé :)

=341x(67+16)+659x83

=341x83+659x83

=(341+659)x83

=1000x83

=83000

Lời giải:

1. Đ

2. Đ

3. S

4. Đ

cám ơn bạn ạ