$a={\mathrm{2^}}^{13}{\mathrm{.5^}}^7=640000000$Vậy có 9 chữ số

Làm bừa

Bài 6 :

a) \(\dfrac{625}{5^n}=5\Rightarrow\dfrac{5^4}{5^n}=5\Rightarrow5^{4-n}=5^1\Rightarrow4-n=1\Rightarrow n=3\)

b) \(\dfrac{\left(-3\right)^n}{27}=-9\Rightarrow\dfrac{\left(-3\right)^n}{\left(-3\right)^3}=\left(-3\right)^2\Rightarrow\left(-3\right)^{n-3}=\left(-3\right)^2\Rightarrow n-3=2\Rightarrow n=5\)

c) \(3^n.2^n=36\Rightarrow\left(2.3\right)^n=6^2\Rightarrow\left(6\right)^n=6^2\Rightarrow n=6\)

d) \(25^{2n}:5^n=125^2\Rightarrow\left(5^2\right)^{2n}:5^n=\left(5^3\right)^2\Rightarrow5^{4n}:5^n=5^6\Rightarrow\Rightarrow5^{3n}=5^6\Rightarrow3n=6\Rightarrow n=3\)

Bài 7 :

a) \(3^x+3^{x+2}=9^{17}+27^{12}\)

\(\Rightarrow3^x\left(1+3^2\right)=\left(3^2\right)^{17}+\left(3^3\right)^{12}\)

\(\Rightarrow10.3^x=3^{34}+3^{36}\)

\(\Rightarrow10.3^x=3^{34}\left(1+3^2\right)=10.3^{34}\)

\(\Rightarrow3^x=3^{34}\Rightarrow x=34\)

b) \(5^{x+1}-5^x=100.25^{29}\Rightarrow5^x\left(5-1\right)=4.5^2.\left(5^2\right)^{29}\)

\(\Rightarrow4.5^x=4.25^{2.29+2}=4.5^{60}\)

\(\Rightarrow5^x=5^{60}\Rightarrow x=60\)

c) Bài C bạn xem lại đề

d) \(\dfrac{3}{2.4^x}+\dfrac{5}{3.4^{x+2}}=\dfrac{3}{2.4^8}+\dfrac{5}{3.4^{10}}\)

\(\Rightarrow\dfrac{3}{2.4^x}-\dfrac{3}{2.4^8}+\dfrac{5}{3.4^{x+2}}-\dfrac{5}{3.4^{10}}=0\)

\(\Rightarrow\dfrac{3}{2}\left(\dfrac{1}{4^x}-\dfrac{1}{4^8}\right)+\dfrac{5}{3.4^2}\left(\dfrac{1}{4^x}-\dfrac{1}{4^8}\right)=0\)

\(\Rightarrow\left(\dfrac{1}{4^x}-\dfrac{1}{4^8}\right)\left(\dfrac{3}{2}+\dfrac{5}{3.4^2}\right)=0\)

\(\Rightarrow\dfrac{1}{4^x}-\dfrac{1}{4^8}=0\)

\(\Rightarrow\dfrac{4^8-4^x}{4^{x+8}}=0\Rightarrow4^8-4^x=0\left(4^{x+8}>0\right)\Rightarrow4^x=4^8\Rightarrow x=8\)

a) \(\dfrac{81}{\left(-3\right)^n}=-243\)

\(\dfrac{\left(-3\right)^4}{\left(-3\right)^n}=\left(-3\right)^5\)

\(\left(-3\right)^n=\dfrac{\left(-3\right)^4}{\left(-3\right)^5}=\left(-3\right)^{-1}\)

n = -1

Vậy n = -1

b) \(\dfrac{25}{5^n}=5\)

\(\dfrac{5^2}{5^n}=5^1\)

\(5^n=\dfrac{5^2}{5^1}=5^1\)

n = 1

Vậy n = 1

c) \(\dfrac{1}{2}\cdot2^n+4\cdot2^n=9\cdot2^5\)

\(2^{n-1}+4\cdot2^{n-1}\cdot2=9\cdot2^5\)

\(2^{n-1}+8\cdot2^{n-1}=9\cdot2^5\)

\(\left(8+1\right)\cdot2^{n-1}=9\cdot2^5\)

\(9\cdot2^{n-1}=9\cdot2^5\)

\(2^{n-1}=2^5\cdot\dfrac{9}{9}=2^5\)

n - 1 = 5

n = 5 + 1 = 6

Vậy n = 6

a) 81/(-3)ⁿ = -243

(-3)ⁿ = 81 : (-243)

(-3)ⁿ = -1/3

n = -1

b) 25/5ⁿ = 5

5ⁿ = 25 : 5

5ⁿ = 5

n = 1

c) 1/2 . 2ⁿ + 4 . 2ⁿ = 9 . 2⁵

2ⁿ . (1/2 + 4) = 9 . 32

2ⁿ . 9/2 = 288

2ⁿ = 288 : 9/2

2ⁿ = 64

2ⁿ = 2⁶

n = 6

a) \(\left(\frac{1}{16}\right)^{25}\div\left(\frac{1}{2}\right)^{30}=\left(\frac{1}{2^4}\right)^{25}\div\left(\frac{1}{2}\right)^{30}=\left[\left(\frac{1}{2}\right)^4\right]^{25}\div\left(\frac{1}{2}\right)^{30}=\left(\frac{1}{2}\right)^{4.25}\div\left(\frac{1}{2}\right)^{30}\)

\(=\left(\frac{1}{2}\right)^{100}\div\left(\frac{1}{2}\right)^{30}=\left(\frac{1}{2}\right)^{100-30}=\left(\frac{1}{2}\right)^{70}\)

b) \(584^{100}\div292^{100}=\left(584-292\right)^{100}=292^{100}\)

c) \(125^4\cdot16^3=\left(5^3\right)^4\cdot\left(2^4\right)^3=5^{3\cdot4}\cdot2^{4\cdot3}=5^{12}\cdot2^{12}=\left(5+2\right)^{12}=7^{12}\)

a) \(\frac{7^3.5^8}{49.25^4}=\frac{7^3.5^8}{7^2.\left(5^2\right)^4}=7.\frac{5^8}{5^8}=7\)

b) \(\frac{3^9.25.5^3}{15.625.3^8}=\frac{3.3^8.5^2.5^3}{3.5.5^4.3^8}=\frac{5^5}{5^5}=1\)

c) Đề hơi sai roi bạn oi

d) \(\left(\frac{2}{5}-\frac{1}{2}\right)^2+\left(\frac{1}{2}+\frac{3}{5}\right)^2=\left(\frac{-1}{10}\right)^2+\left(\frac{11}{10}\right)^2=\frac{1}{100}+\frac{121}{100}=\frac{61}{50}\)

Khanh Nguyễn Ngọc  :câu d ko sai bạn nha dấu "/" là trên nhó

a/ \(\left(-2x^2y\right)5xy^4\)

\(=-10x^3y^5\)

tự lm tiếp, rất dễ