a, Ta có: \(-\left|x+3\right|\le0\)

\(\Rightarrow A=-\left|x+3\right|+2017\le2017\)

Dấu " = " xảy ra khi \(-\left|x+3\right|=0\Rightarrow x=-3\)

Vậy \(MAX_A=2017\) khi x = -3

b, Ta có: \(\left\{{}\begin{matrix}-\left|30-x\right|\le0\\-\left|40+y\right|\le0\end{matrix}\right.\Rightarrow-\left|30-x\right|-\left|40+y\right|\le0\)

\(\Rightarrow B=120-\left|30-x\right|-\left|40+y\right|\le120\)

Dấu " = " xảy ra khi \(\left\{{}\begin{matrix}\left|30-x\right|=0\\\left|40+y\right|=0\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=30\\y=-40\end{matrix}\right.\)

Vậy \(MAX_B=120\) khi x = 30, y = -40

c, Ta có: \(-\left|2x+1\right|\le0\)

\(\Rightarrow C=2016-\left|2x+1\right|\le2016\)

Dấu " = " xảy ra khi \(\left|2x+1\right|=0\Rightarrow x=\dfrac{-1}{2}\)

Vậy \(MAX_C=2016\) khi \(x=\dfrac{-1}{2}\)

d, Sai đề

hayy

đề sai hay đúng vậy bạn

Ta có : \(\dfrac{2017+2018}{2018+2019}=\dfrac{2017}{2018+2019}+\dfrac{2018}{2018+2019}\)

Rõ ràng ta thấy : \(\dfrac{2017}{2018}>\dfrac{2017}{2018+2019}\) (1)

\(\dfrac{2018}{2019}>\dfrac{2018}{2018+2019}\) (2)

Từ (1) và (2), suy ra :

\(\dfrac{2017}{2018}+\dfrac{2018}{2019}>\dfrac{2017+2018}{2018+2019}\)

Vậy ......................

~ Học tốt ~

Ta có : \(\dfrac{2017}{2018}+\dfrac{2018}{2019}+\dfrac{2019}{2020}=\left(1-\dfrac{1}{2018}\right)+\left(1-\dfrac{1}{2019}\right)+\left(1-\dfrac{1}{2020}\right)\)\(=\left(1+1+1\right)-\left(\dfrac{1}{2018}+\dfrac{1}{2019}+\dfrac{1}{2020}\right)\)

\(=3+\left(\dfrac{1}{2018}+\dfrac{1}{2019}+\dfrac{1}{2020}\right)< 3\)

Vậy \(\dfrac{2017}{2018}+\dfrac{2018}{2019}+\dfrac{2019}{2020}< 3\)

kết quả là 1

`@` `\text {Ans}`

`\downarrow`

`c)`

`( 34 - 2x ) . ( 2x - 6 ) = 0`

`=>`\(\left[{}\begin{matrix}34-2x=0\\2x-6=0\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}2x=34\\2x=6\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=34\div2\\x=6\div2\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=17\\x=3\end{matrix}\right.\)

Vậy, `x \in {17; 3}`

`d)`

`( 2019 - x ) . ( 3x - 12 ) =0` `?`

`=>`\(\left[{}\begin{matrix}2019-x=0\\3x-12=0\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=2019-0\\3x=12\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=2019\\x=12\div3\end{matrix}\right.\)

`=>`\(\left[{}\begin{matrix}x=2019\\x=4\end{matrix}\right.\)

Vậy, `x \in {2019; 4}`

`e) `

`57 . ( 9x - 27 ) = 0`

`=>`\(9x-27=0\div57\)

`=> 9x - 27 = 0`

`=> 9x = 27`

`=> x = 27 \div 9`

`=> x = 3`

Vậy, `x = 3`

`f)`

`25 + ( 15 - x ) = 30`

`=> 15 - x = 30 - 25`

`=> 15 - x = 5`

`=> x = 15 -5 `

`=> x = 10`

Vậy, `x = 10`

`g) `

`43 - ( 24 - x ) = 20`

`=> 24 - x = 43 - 20`

`=> 24 - x = 23`

`=> x = 24 - 23`

`=> x = 1`

Vậy, `x = 1`

`h) `

`2 . ( x - 5 ) - 17 = 25`

`=> 2 ( x - 5) = 25+17`

`=> 2 ( x - 5) = 42`

`=> x - 5 = 42 \div 2`

`=> x - 5 = 21`

`=> x = 21 + 5`

`=> x = 26`

Vậy, `x = 26`

`i)`

`3 . ( x + 7 ) - 15 = 27`

`=> 3(x + 7) = 27 + 15`

`=> 3(x + 7) = 42`

`=> x +7 = 42 \div 3`

`=> x + 7 = 14`

`=> x = 14 - 7`

`=> x = 7`

Vậy, `x = 7`

`j)`

`15 + 4 . ( x - 2 ) = 95`

`=> 4(x - 2) = 95 - 15`

`=> 4(x - 2) = 80`

`=> x - 2 = 80 \div 4`

`=> x - 2 = 20`

`=> x = 20 + 2`

`=> x = 22`

Vậy, `x = 22`

`k)`

`20 - ( x + 14 ) = 5`

`=> x + 14 = 20 - 5`

`=> x + 14 = 15`

`=> x = 15 - 14`

`=> x = 1`

Vậy, `x = 1`

`l) `

`14 + 3 . ( 5 - x ) = 27`

`=> 3(5 - x) = 27 - 14`

`=> 3(5 - x) = 13`

`=> 5 - x = 13 \div 3`

`=> 5 - x = 13/3`

`=> x = 5- 13/3`

`=> x = 2/3`

Vậy, `x = 2/3.`

`@` `\text {Kaizuu lv uuu}`

nhanh mik tick cho nha

Bài 1:

a. 31.72 - 31.70 - 31.2

= 31.(72-70-2)

= 31.0 = 0

b. 25. ( 32 + 47 ) - 32. ( 25 + 47 )

= 25.32 + 25.47 - 32.25 - 32.47

= (25.32 - 32.25) + 25.47 -32.47

= 0 + 47.( 25-32)

= 47.(-7) = -329

c. [ 3. ( - 2 ) - ( - 8 ) ] . ( - 7 ) - ( - 2 ) . ( - 5 )

= [ -6 + 8 ] . (-7)+2.(-5)

= 2. [(-7)+(-5) ]

= 2.(-12) = -24

d. ( - 3 ) ^ 2 + 3 ^ 3 - ( - 3 ) ^ 0

= 9 + 27 - 1

= 35

Đây là cách mình làm thôi. Có j sai thì bạn thông cảm nha...

Bài 1:

a. 31.72 - 31.70 -31.2

=31.(72-70-2)

=31.0

=0

b. 25. (32+47) -32 .(25+47)

=25.79 -32. 72

= 1975 -2304

= -329

c,[ 3.(-2)-(-8) ].(-7) - (-2) . (-5)

=[3.(-2)+8].(-7)+2.(-5)

=[(-6)+8].(-7)+(-10)

= 2.(-7)+(-10)

= (-14)+(-10)

= (-24)

d.(-3)² + 3³ - (-3)⁰

= 9 + 27 +3⁰

= 36

Bài 2:

a. -2x -3 =15

-2x=15 +3

-2x =18

x = 18 : -2

x= -9

b. 5-4x =17

4x =5 -17

4x = -12

x = -12 : 4

x= -3

c. -2 / x-3 /=16 : (-2)

-2 /x - 3/= -8

/x-3 /= -8 : -2

/x-3/=4

=>x-3 =4 hoặc x - 3=-4

x=4+3 ; x= -4+3

x=7 ; x= -1

Vậy x=7 hoặc x= -1

d. (x-1)² =4

( x-1)²=2²

=> x - 1 = 2

x=2+1

x=3

Bài 3:GTNN của A=2017 nha bạn

Bài 4:

43⁴³ - 17¹⁷ = (........7) - (.......7)

= (.........0)

Vì 43 ⁴³ - 17¹⁷ có tận cùng bằng 0 => \(⋮\) cho 2

Bài 5:

52⁵² - 13⁵² = (.....6) - (......1)

= (......5)

Vì 52⁵² - 13⁵² có tận cùng bằng 5 =>\(⋮\) cho 5

*Lưu ý:mk áp dụng tính chất Chữ số tận cùng.