Khong thuc hien phep tinh de tim ket qua.Hay chung minh rang cac tong sau lon hon 1

M = \(\frac{3}{7}+\frac{3}{8}+\frac{3}{10}\)

Khong thuc hien phep tinh de tim ket qua. Hay chung minh rang cac tong sau lon hon 1

N = \(\frac{21}{90}+\frac{31}{72}+\frac{21}{40}+\frac{-1}{45}+\frac{-1}{50}\)

Khong thuc hien phep tinh de tim ket qua. Hay chung minh rang tong sau lon hon 1

N = \(\frac{21}{90}+\frac{31}{72}+\frac{21}{40}+\frac{-1}{45}+\frac{-1}{50}\)

BAI1: CHO BIEU THUC.

A= 1494 x 1495 x 1496

KHONG THUC HIEN PHEP TINH GIAI THICH VI SAO

a; a chia het 180

b; a chia het 495

BAI2:CHUNG MINH RANG : n thuoc N thi cac so sau chia het cho 9

a; 10^n-1

b; 10ⁿ⁺⁸

BAI3: TIM DIEU KIEN n thuoc N de so 10^n-1 chia het cho 9 va 11

khong thuc hien phep tinh , cho biet cac tong hoac hieu sau day la nguyen to hay hop so

3²+3.17+3.43^3;   7+7²+7³+7⁴+7^{5 ;} 46-30+2002 ; 3.4.5.6.7+7.8.9.10

tinh tong cac uoc so cua 5.2^10.neu khong tinh ket qua cua tong thi co chung minh duoc tong la B(6) hay khong

khong thuc hien phep tinh o mau , hay so sanh cac phan so sau

a) A = \(\frac{244.395-151}{244+395.243}\)va   B=\(\frac{423134.846267-423133}{4423133.846267+423134}\)

Ai giup minh voi

Giup minh nhe

Khong tinh tong cua 3 phan so sau, hay chung to rang tong do nho hon 2:

A = 11/29 + 9/17 + 10/19

a) CHO TONG A = 270 + 3150 + 150 . KHONG THUC HIEN PHEP TINH XET XEM TONG TREN CO CHIA HET CHO 2 ; 3 ; 5 ;9

b) CHO B = 12+ 18 + 21 + x VOI x THUOC N . TIM DIEU KIEN CUA x DE A CHIA HET CHO 3 , DE A KHONG CHIA CHO 3

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