Khong thuc hien phep tinh de tim ket qua. Hay chung minh rang tong sau lon hon 1

N = \(\frac{21}{90}+\frac{31}{72}+\frac{21}{40}+\frac{-1}{45}+\frac{-1}{50}\)

Khong thuc hien phep tinh de tim ket qua. Hay chung minh rang cac tong sau lon hon 1

M = \(\frac{3}{7}+\frac{3}{8}+\frac{3}{10}\)

Khong thuc hien phep tinh de tim ket qua.Hay chung minh rang cac tong sau lon hon 1

M = \(\frac{3}{7}+\frac{3}{8}+\frac{3}{10}\)

Chứng minh tổng sau lớn hơn 1  :  \(P=\frac{41}{90}+\frac{31}{72}+\frac{21}{40}+\frac{-11}{45}+\frac{-1}{36}\)

Chứng minh rằng : Các tổng sau lớn hơn 1

a) \(\frac{3}{8}+\frac{3}{7}+\frac{3}{15}\)

b) \(\frac{41}{90}+\frac{31}{72}+\frac{21}{40}+\frac{-11}{45}+\frac{-1}{36}\)

khong thuc hien phep tinh o mau , hay so sanh cac phan so sau

a) A = \(\frac{244.395-151}{244+395.243}\)va   B=\(\frac{423134.846267-423133}{4423133.846267+423134}\)

Ai giup minh voi

Khong thuc hien phep tinh o mau, hay so sanh cac phan so sau

b) M = \(\frac{53.71-18}{71.555552+53}\);      N=\(\frac{54.107-53}{53.107+54}\)va  P=\(\frac{135.269-133}{134.269+135}\)

Tinh nhanh:

\(\frac{6}{2.5}+\frac{6}{5.8}+\frac{6}{8.11}+......+\frac{6}{299.302};\)

So sanh cac phan so sau ma khong can thuc hien cac phep tinh o mau

\(A=\frac{54.107-53}{53.107+54}\)                   \(B=\frac{135.269-133}{134.269+135}\)

Thuc hien phep tinh sau

\(\frac{1}{1.2}+\frac{1}{2.3}+........+\frac{1}{999.1000}\)

Tui bit dap an nhung quen cach lam oj cac ban giup mik voi