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2 2 3 ⋅ 2 5 ⋅ 3 8 ⋅ 10 ⋅ 19 92 = 8 3 . 2 5 . 3 8 .10. 19 92 = 8.2.3.10.19 3.5.8.92 = 19 23
c) và d) của Trí sai nên sửa lại
c) (2x - 4)/7 < 0
⇒ 2x - 4 < 0 (vì 7 > 0)
⇒ 2x < 4
⇒ x < 2
d) (5x - 8)/-10 < 0
⇒ 5x - 8 > 0 (vì -10 < 0)
⇒ 5x > 8
⇒ x > 8/5
a) \(\dfrac{x-2}{45}>0\Rightarrow x-2>0\Rightarrow x>2\)
b) \(\dfrac{x+3}{-2}>0\Rightarrow x+3< 0\Rightarrow x< -3\)
c) \(\dfrac{2x-4}{7}< 0\Rightarrow2x-4>0\Rightarrow2x>4\Rightarrow x>2\)
d) \(\dfrac{5x-8}{10}< 0\Rightarrow5x-8< 0\Rightarrow5x< 8\Rightarrow x< \dfrac{8}{5}\)
a: \(-\dfrac{8}{25}=\dfrac{-7}{10}\cdot\dfrac{16}{35}\)
b: \(-\dfrac{8}{25}=\dfrac{12}{5}:\dfrac{-15}{2}\)
3,
a)
= \(-\frac{5}{21}:\frac{4}{5}+\frac{5}{21}:\frac{4}{5}\)
= \(\left(-\frac{5}{21}+\frac{5}{21}\right):\frac{4}{5}\)
= \(0:\frac{4}{5}=0\)
2,
a) \(\frac{-3}{4}\).\(\frac{12}{-5}\).(\(\frac{-25}{6}\))
= \(\frac{-3.4.3.\left(-5\right).5}{4.\left(-5\right).3.3}\)
= \(-5\)
b) (−2).\(\frac{-38}{21}\).\(\frac{-7}{4}\).(\(\frac{-3}{8}\))
= \(\frac{-2.\left(-38\right)\left(-7\right)\left(-3\right)}{\left(-7\right)\left(-3\right)\left(-2\right)\left(-2\right).8}\)
= \(\frac{19}{8}\)
c) (\(\frac{11}{12}:\frac{33}{16}\)).\(\frac{3}{5}\)
= \(\left(\frac{11}{12}.\frac{16}{33}\right).\frac{3}{5}\)
= \(\frac{4}{9}.\frac{3}{5}\)
= \(\frac{4}{15}\)
d) \(\frac{7}{23}\left[\left(\frac{-8}{6}\right)-\frac{45}{18}\right]\)
= \(\frac{7}{23}.\left(\frac{-41}{10}\right)\)
= \(\frac{-287}{203}\)
3. Tính:
a) (\(\frac{-2}{3}+\frac{3}{7}\)):\(\frac{4}{5}\)+(\(\frac{-1}{3}+\frac{4}{7}\)):\(\frac{4}{5}\)
= (\(\frac{-2}{3}+\frac{3}{7}\)\(+\)\(\frac{-1}{3}+\frac{4}{7}\)) : \(\frac{4}{5}\)
= 0 : \(\frac{4}{5}\)
= 0
b) \(\frac{5}{9}\):(\(\frac{1}{11}-\frac{5}{22}\))+\(\frac{5}{9}\):(\(\frac{1}{15}-\frac{2}{3}\))
= \(\frac{5}{9}\): \(\frac{-3}{22}\)+ \(\frac{5}{9}\): \(\frac{-3}{5}\)
= \(\frac{5}{9}\): \(\frac{-81}{110}\)
= \(\frac{-550}{729}\)
( − 2 ) ⋅ − 38 21 ⋅ − 7 4 ⋅ − 3 8 = ( − 2 ) . ( − 38 ) . ( − 7 ) . ( − 3 ) 21.4.8 = 2.38.7.3 21.4.8 = 19 8 = 2 3 8