a ) 25⁵⁰và 2525²⁵

\(25^{50}=\left(25^2\right)^{25}=625^{25}\)(1)

\(2525^{25}\)(2)

Từ (1)(2) => \(2525^{25}>625^{25}\)

                     hay\(2525^{25}>25^{50}\)

b) Tương tự câu a

làm giúp mình với

Tất cả đều bằng nhau.

Ta có :

\(\left(\frac{16}{25}\right)^{10}=\left(\frac{4^2}{5^2}\right)^{10}=\left(\frac{4}{5}\right)^{2.10}=\left(\frac{4}{5}\right)^{20}\)

\(\left(\frac{3}{7}\right)^{40}=\left(\frac{3}{7}\right)^{2.20}=\left(\frac{3^2}{7^2}\right)^{20}=\left(\frac{9}{49}\right)^{20}\)

Vì 20 = 20 và \(\frac{4}{5}>\frac{9}{49}\)nên \(\left(\frac{4}{5}\right)^{20}>\left(\frac{9}{49}\right)^{20}\)

Vậy \(\left(\frac{16}{25}\right)^{10}>\left(\frac{3}{7}\right)^{40}\)

Ta có : 25¹⁶ = (5²)¹⁶ = 5³² = (5⁴)⁸ = 625⁸

Lại có 6²⁴ = (6³)⁸ = 216⁸

Vì 625⁸ > 216⁸

=> 25¹⁶ > 6²⁴

                                        Bài làm :

Ta có :

• 25¹⁶ = (5²)¹⁶ = 5³² = (5⁴)⁸ = 625⁸
• 6²⁴ = (6³)⁸ = 216⁸

Vì  625⁸ > 216⁸  => 25¹⁶  > 6²⁴ 

Chúc bạn học tốt !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

\(\dfrac{297}{16}>\dfrac{297+9}{16+9}=\dfrac{306}{25}\)

\(\Rightarrow\dfrac{297}{16}>\dfrac{306}{25}\)

Ta co

21/25<1 va 25/21>1 Vi vay 21/25<25/21

Ta có:

\(\frac{21}{25}\)vì 21<25 nên \(\frac{21}{25}< 1\)

Ta lại có:

\(\frac{25}{21}\)vì 25>21 nên \(\frac{25}{21}>1\)

Vì \(\frac{21}{25}< 1< \frac{25}{21}\)

Nên \(\frac{21}{25}< \frac{25}{21}\)

a) => \(\left(\frac{1}{3}-\frac{5}{6}x\right)^3=\frac{5}{6}-\frac{21}{54}=\frac{24}{54}=\frac{4}{9}\)

=> \(\frac{1}{3}-\frac{5}{6}x=\sqrt[3]{\frac{4}{9}}\) => \(\frac{5}{6}x=\frac{1}{3}-\sqrt[3]{\frac{4}{9}}\) => \(x=\frac{6}{5}.\left(\frac{1}{3}-\sqrt[3]{\frac{4}{9}}\right)\)

b) \(\frac{1}{3}\left(\frac{1}{2}x-1\right)^4=\frac{1}{12}-\frac{1}{16}=\frac{1}{48}\) => \(\left(\frac{1}{2}x-1\right)^4=\frac{3}{48}=\frac{1}{16}\)

=> \(\frac{1}{2}x-1=\frac{1}{2}\) hoặc  \(\frac{1}{2}x-1=-\frac{1}{2}\)

=> \(\frac{1}{2}x=\frac{3}{2}\) hoặc \(\frac{1}{2}x=\frac{1}{2}\) => x = 3 hoặc x = 1

c) \(\left(1+5\right).\left(\frac{3}{5}\right)^{x-1}=\frac{54}{25}\) => \(\left(\frac{3}{5}\right)^{x-1}=\frac{9}{25}=\left(\frac{3}{5}\right)^2\)

=> x - 1= 2 => x = 3

d) \(\left(1+\left(\frac{2}{3}\right)^2\right).\left(\frac{2}{3}\right)^x=\frac{101}{243}\) => \(\frac{13}{9}.\left(\frac{2}{3}\right)^x=\frac{101}{243}\)

=> \(\left(\frac{2}{3}\right)^x=\frac{101}{243}:\frac{13}{9}=\frac{101}{351}\) (có lẽ đề sai)

2) \(\frac{1}{27^{11}}=\frac{1}{\left(3^3\right)^{11}}=\frac{1}{3^{33}}\); \(\frac{1}{81^8}=\frac{1}{\left(3^4\right)^8}=\frac{1}{3^{32}}\)

Vì 3³³ > 3³² => \(\frac{1}{3^{33}}\) < \(\frac{1}{3^{32}}\) => \(\frac{1}{27^{11}}\) < \(\frac{1}{81^8}\)

b) \(\frac{1}{3^{99}}=\frac{1}{\left(3^3\right)^{33}}=\frac{1}{27^{33}}

nhjeu wa bạn giải 1 mjk luôn đi

a) Thì rất dễ 

Mình làm 

c) Ta có ; 21¹² = (21³)⁴ = 9261⁴

Mà :   9261⁴ > 54⁴

Nên : 21¹² > 54⁴

A) 25⁵⁰ >25²⁵                                                 

c ) 54⁴=54⁴

     21¹²= (21³)⁴ = 9261⁴

=> 54⁴< 21¹²