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Vd 3:
a) 9/10 > 5/42 b) -4/27 < 10/-73
Vd 4:
5/-6: -7/12; 5/8; 3/4
Vd 5:
x<y
Vd 6:
-16/27= -16/27> -16/29
a) \(\dfrac{11}{2}=\dfrac{10+1}{2}=5+\dfrac{1}{2}\)
\(\dfrac{32}{9}=\dfrac{27+5}{9}=3+\dfrac{5}{9}< 5+\dfrac{1}{2}\)
Vậy \(\dfrac{11}{2}>\dfrac{32}{9}\)
b)\(\dfrac{100}{23}=\dfrac{92+8}{23}=4+\dfrac{8}{23}\)
\(\dfrac{302}{123}=\dfrac{246+56}{123}=2+\dfrac{56}{123}< 4+\dfrac{8}{23}\)
Vậy \(\dfrac{100}{23}>\dfrac{302}{123}\)
c) \(\dfrac{515}{605}< \dfrac{515+1}{605+1}=\dfrac{516}{606}\Rightarrow\dfrac{515}{605}< \dfrac{516}{606}\)
a: \(-\dfrac{11}{33}< 0< \dfrac{25}{16}\)
b: \(-\dfrac{17}{23}=\dfrac{-171717}{232323}\)
d: -11/17=-22/34
22/31>22/34
=>-22/31<-22/34
e: -23/91=-1587/91*69
-17/69=-1547/91*69
mà -1587<-1547
nên -23/91<-17/69
\(\frac{11}{13}\)và \(\frac{22}{27}\)
Ta có:
\(\frac{11}{13}=\frac{297}{351}\)
\(\frac{22}{27}=\frac{242}{351}\)
Mà: \(\frac{297}{351}>\frac{242}{351}\)
Vậy \(\frac{11}{13}>\frac{22}{27}\)
\(\frac{-5}{11}\)và \(\frac{-9}{23}\)
Ta có:
\(\frac{-5}{11}=\frac{-115}{253}\)
\(\frac{-9}{23}=\frac{-99}{253}\)
Mà: \(\frac{-115}{253}< \frac{-99}{253}\)
Vậy \(\frac{-5}{11}< \frac{-9}{23}\)