\(\frac{2011x2010-1}{2009x2011+2010}=\frac{2011x\left(2009+1\right)-1}{2009x2011+2010}\)

\(=\frac{2011x2009+2011-1}{2009x2011+2010}=\frac{2011x2009+2010}{2009x2011+2010}=1\)

2016x2015-1/2014x2016-2015

=2016x(2014+1)-1/2014x2016-2015

=2016x2014-2016x1-1/2014x2016-2015

=2016x2014-2016-1/2014x2016-2015

=2016x2014-2015/2014x2016-2015

=1

thank bn nha~

vì 1/1*2=1-1/2

   1/2*3=1/2-1/3

.....................

1/2014*2015=1/2014-1/2015

=1-1/2+1/2-1/3+1/3-....+1/2014-1/2015

=1-1/2015

=2014/2115

\(\frac{1}{1x2}+\frac{1}{2x3}+\frac{1}{3x4}+....+\frac{1}{2014x2015}\)

=\(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+....+\frac{1}{99}-\frac{1}{100}\)

=\(1-\frac{1}{100}\)

=\(\frac{99}{100}\)

Ta có: \(\frac{2015.2016-2}{2014.2015+4028}=\frac{2015.2016-2}{2014.2015+2.2014}=\frac{\left(2015+2\right).\left(2016-2\right)}{2014.\left(2015+2\right)}=\frac{2017.2014}{2017.2014}=1\)

Bài 1 : Tính nhanh : 

a) 19 . 64 + 76 .34

= 38 . 32 + 38 . 68

= 38 . (32 + 68)

= 38 .100

= 3800

b) 35 . 12 + 65 . 13

= 35 . 12 + 65 . (12 + 1)

= 35 . 12 + 65 . 12 + 65

= 12 . (35 + 65) + 65

= 1200 + 65

 = 1265.

Bài 2 :

a)

A = 1998 . 1998 

=1998 . 1996 + 1998 . 2

B = 1996 . 2000

    =1998 . 1996 + 1996 . 2

Vì 1998 . 2 >1996 . 2

=>A > B

b)

A= 2000 . 2000 

   = 1990 . 2000 + 2000 . 10

B = 1990 . 2010

    =1990 . 2000 + 1990 . 10

Vì 2000 . 10 > 1990 . 10

=>A > B

a,19.64+76.34          b,35.12+63.13

TẤT CẢ CÁC SỐ CỦA A ĐỀU LỚN HƠN MỌI SỐ CỦA B NÊN A>B

Đúng rồi.

\(\frac{2319}{2010}-\frac{1789}{2000}-\frac{309}{2010}+\frac{2009}{2010}-\frac{211}{2000}\)

\(=\left(\frac{2319}{2010}-\frac{309}{2010}+\frac{2009}{2010}\right)-\left(\frac{1789}{2000}-\frac{211}{2000}\right)\)

\(=\frac{4019}{2010}-\frac{789}{1000}\)

=))

(-376)+|-2010|-|-2000|-(-486)

=(-376)+2010-2000+486

=  (-376)+2010+(-2000)+486

=[(-376)+486]+[2010+(-2000)]

=       110        +       10

=         120

(-376) + |-2010| - |-2000| - (-486)

= (-376) + 2010 - 2000 + 486

= [ (-376) + 486 ] + ( 2010 - 2000 )

= 110 + 10

= 120