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a) \(24=2^3.3\)
\(60=2^2.3.5\)
\(UCLN\left(a;b\right)=UCLN\left(24;60\right)=2^2.3=6\)
\(BCNN\left(a;b\right)=BCNN\left(24;60\right)=2^3.3.5=120\)
\(a.b=UCLN\left(a;b\right).BCNN\left(a;b\right)\)
\(\Rightarrow a.b=6.120=720\)
mà \(\dfrac{a}{b}=\dfrac{24}{60}\Rightarrow\dfrac{a}{24}=\dfrac{b}{60}=\dfrac{720}{24.60}=\dfrac{1}{2}\)
\(\Rightarrow\left\{{}\begin{matrix}a=24.\dfrac{1}{2}=12\\b=60.\dfrac{1}{2}=30\end{matrix}\right.\)
Vậy Phân số cần tìm là \(\dfrac{12}{30}\)
b) \(\left\{{}\begin{matrix}14=2.7\\21=3.7\end{matrix}\right.\)
\(\Rightarrow UCLN\left(a;b\right)=UCLN\left(14;21\right)=7\)
\(a.b=UCLN\left(14;21\right).BCNN\left(14;21\right)\)
\(\Rightarrow a.b=7.3456=24192\)
\(\dfrac{a}{b}=\dfrac{14}{21}\Rightarrow\dfrac{a}{14}=\dfrac{b}{21}=\dfrac{a.b}{14.21}=\dfrac{24192}{294}=\dfrac{576}{7}\)
\(\Rightarrow\left\{{}\begin{matrix}a=\dfrac{576}{7}.14=1152\\b=\dfrac{576}{7}.21=1728\end{matrix}\right.\)
Vậy phân số cần tìm là \(\dfrac{1152}{1728}\)
45=3^2*5
204=2^3*3*17
126=2*3^2*7
=>ƯCLN(45;204;126)=3
BCNN(45;204;126)=3^3*5*2*17*7=80325
Ta có:
\(a=45=3^2\cdot5\)
\(b=204=2^2\cdot3\cdot17\)
\(c=126=2\cdot3^2\cdot7\)
\(\RightarrowƯCLN\left(a,b,c\right)=3\)
\(\Rightarrow BCNN\left(a,b,c\right)=3^3\cdot5\cdot2\cdot17\cdot7=80325\)
Xl nhìu nha!!!!!
a) ta có UCLN(a;b).BCNN(a;b)=a.b=120.10=1200
UCLN(a;b)=10 \(\Rightarrow\)\(\left\{{}\begin{matrix}a⋮10\\b⋮10\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}a=10k\\b=10h\end{matrix}\right.\left(k;h\right)=1;k\ge h\)
a.b=1200\(\Leftrightarrow\)10k.10h=1200
nên k.h =1200:100=12
mà (k;h)=1 nên (k;h)=(12;1);(4;3)
nên (a;b)=(120;10);(40;30)
a) goi hai so la a ; b va a >b
vi UCLN(a,b)=18=>a=18k ; b=18q (trong do UCLN (k,q)=1 va k>q)
=>a+b=162
18k+18q =162
18(k+q)=162
k+q=9
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c, Gọi ƯCLN(a; b) = d; d \(\in\) k
⇒ d = 1944 : 108 = 18
⇒ a = 18.k; b = 18.n (k;n) =1; k;n \(\in\) N*
⇒18.k.18.n = 1944
⇒k.n =1944 : (18.18)
k.n = 6
6 = 2.3 Ư(6) = {1; 2; 3;6)
⇒(k; n) = (1; 6); (2; 3); (3; 2); (6; 1)
⇒ (a; b) = (18; 108); (36; 54); (54; 36); (108; 18)
Vì a> b nên (a; b) = (54; 36); (108; 18)
a, a + b = 72; Ư CLN(a; b) = 9 (a > b)
a = 9.k; b = 9.d (k; d) = 1; k; d \(\in\) N*; k >d
9.k + 9.d = 72
9.(k + d) = 72
k + d = 72 : 9
k + d = 8
(k; d) =(1; 7); (2; 6); (3; 5); (4; 4); (5; 3); (6; 2); (7; 1)
vì (k;d) = 1; k > d ⇒ (k;d) = (5; 3); (7; 1)
⇒ (a; b) = (45; 27); (63; 9)
a, Gọi hai số tự nhiên cần tìm là a và b
Ta có : a=6.k1;b=6.k2a=6.k1;b=6.k2
Trong đó : ƯCLN(k1,k2)=1ƯCLN(k1,k2)=1
Mà : a+b=84⇒6.k1+6.k2=84a+b=84⇒6.k1+6.k2=84
⇒6(k1+k2)=84⇒k1+k2=84÷6=14⇒6(k1+k2)=84⇒k1+k2=84÷6=14
+) Nếu : k1=1⇒k2=13⇒{a=6b=78k1=1⇒k2=13⇒{a=6b=78
+)Nếu : k1=3⇒k2=11⇒{a=18b=66k1=3⇒k2=11⇒{a=18b=66
+)Nếu : k1=5⇒k2=9⇒{a=30b=54k1=5⇒k2=9⇒{a=30b=54
Vậy ...
b, Tương tự câu a,
c, Gọi hai số tự nhiên cần tìm là a và b
Vì : ƯCLN(a,b)=10;BCNN(a,b)=900ƯCLN(a,b)=10;BCNN(a,b)=900
⇒ƯCLN(a,b).BCNN(a,b)=a.b=900.10=9000⇒ƯCLN(a,b).BCNN(a,b)=a.b=900.10=9000
Phần còn lại giống câu a và câu b bạn tự làm nha
chúc bạn hok tốt