giúp mik vs 4h 30 ) hc rồi

\(\frac{0,1\left(6\right)+0,\left(3\right)}{0,\left(3\right)+1,1\left(6\right)}-x=0,\left(2\right)\)

\(\Rightarrow\frac{\frac{1}{6}+\frac{1}{3}}{\frac{1}{3}+\frac{7}{6}}-x=\frac{2}{9}\)

\(\Rightarrow\frac{\frac{1}{2}}{\frac{3}{2}}-x=\frac{2}{9}\)

\(\Rightarrow\frac{1}{3}-x=\frac{2}{9}\)

\(\Rightarrow x=\frac{1}{3}-\frac{2}{9}=\frac{1}{9}\)

Vậy \(x=\frac{1}{9}\)

(x - 0,1)⁶ = (x - 0,1)⁴

(x - 0,1)⁶ - (x - 0,1)⁴ = 0

(x - 0,1)⁴.[(x - 0,1)² - 1] = 0

(x - 0,1)⁴ = 0 hoặc (x - 0,1)² - 1 = 0

*) (x - 0,1)⁴ = 0

x - 0,1 = 0

x = 0,1

*) (x - 0,1)² - 1= 0

(x - 0,1)² = 1

x - 0,1 = 1 hoặc x - 0,1 = -1

**) x - 0,1 = 1

x = 1 + 0,1

x = 1,1

*) x - 0,1 = -1

x = -1 + 0,1

x = -0,9

Vậy x = -0,9; x = 0,1; x = 1,1

mấy bài này dễ vậy mà mày cx phải hỏi

người ta ko bt thì hỏi , đừng có mak ns mấy câu vô văn hóa thế nhá

B1      :

\(\frac{0,1\left(6\right)+0,\left(3\right)}{0,\left(3\right)+1,1\left(6\right)}\) . x = 0,(2)

=\(\frac{0,5}{1,5}\).x=0,(2)

x=0,(2):\(\frac{0,5}{1,5}\)

x=0,(6)=\(\frac{2}{3}\)

b2:

 [12,(1) - 2,3(6)] : 4,(21)

=9,7(4):4,(21)

=\(\frac{9,7\left(4\right)}{4,\left(21\right)}\)

di ban

a.=> \(\frac{\left(\frac{1}{3}\right).x}{\frac{2}{3}}=\frac{\frac{7}{4}}{\frac{2}{5}}\)

=> \(\frac{1}{3}.x=\frac{7}{4}.\frac{2}{3}:\frac{2}{5}\)

=>\(\frac{1}{3}.x=\frac{35}{12}\)

=> x\(=\frac{35}{12}:\frac{1}{3}\)

Vậy x=\(\frac{35}{4}\).

b. => \(\frac{4,5}{0,3}=\frac{2,25}{0,1.x}\)

=>\(0,1.x=\frac{2,25.0,3}{4,5}\)

=>\(0,1.x=0,15\)

=>\(x=0,15:0,1\)

Vậy x=1,5

c. =>\(\frac{8}{\frac{1}{4}.x}=\frac{2}{0,02}\)

=>\(\frac{1}{4}.x=\frac{8.0,02}{2}\)

=>\(\frac{1}{4}.x=0,08\)

=>\(x=0,08:\frac{1}{4}\)

Vậy x=0,32.

d. =>\(\frac{3}{\frac{9}{4}}=\frac{\frac{3}{4}}{6.x}\)

=>\(3.6x=\frac{9}{4}.\frac{3}{4}\)

=>\(18x=\frac{27}{16}\)

=>\(x=\frac{27}{16}:18\)

Vậy x=\(\frac{3}{32}\)

1. a) -0,35 = -7/20 ; b) 1,14 = 57/50

  c) 2,108 = 527/250 ; -0,725 = -29/40

2. a) 0,2(3) = 0,2 + 0,0(3) = 0,2 + 0,3. 0,(1) = 0,2 + 0,3.1/9 = 1/5 + 1/30 = 7/30 

  b 1,4(51) = 1,4 + 0,0(51) = 7/5 + 5,1. 0,(01) = 7/5 + 5,1. 1/99 = 7/5 + 17/330 = 479/330

  c) -2,(412) = -2 - 0,(412) = -2 - 412. 0,(001) = -2 - 412. 1/999 = -2 - 412/999 = -2410/999

d) 3,1(45) = 3,1 + 0,0(45) = 3,1 + 4,5. 0,(01) = 3,1 + 4,5 . 1/99 = 3,1 + 1/22 = 173/55

3. Ta có: -2,(6).x = 0,1(6)

=> [-2 - 0,(1).6].x = (0,1 + 0,6. 0,(1)]

=> (-2 - 2/3)x = 0,1 + 1/15

=> -8/3x = 1/6

=>  x = 1/6 : (-8/3)

=> x = -1/16

a) \(\left(\frac{1}{3}.x\right):\frac{2}{3}=\frac{7}{4}:\frac{2}{5}\)

\(\left(\frac{1}{3}.x\right):\frac{2}{3}=\frac{35}{8}\)

\(\Rightarrow\frac{1}{3}.x=\frac{35}{8}.\frac{2}{3}\)

\(\Rightarrow\frac{1}{3}.x=\frac{35}{12}\)

\(\Rightarrow x=\frac{35}{12}:\frac{1}{3}\)

\(\Rightarrow x=\frac{35}{4}\)

Vậy \(x=\frac{35}{4}\)

a) x= \(\frac{35}{4}\)