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Lời giải:
a. $x(\frac{4}{5}x-1)(0,1x-10)=0$
$\Rightarrow x=0$ hoặc $\frac{4}{5}x-1=0$ hoặc $0,1x-10=0$
Nếu $\frac{4}{5}x-1=0$
$\Rightarrow x=1: \frac{4}{5}=\frac{5}{4}$
Nếu $0,1x-10=0$
$\Rightarrow x=10:0,1=100$
Vậy $x=0; \frac{5}{4}; 100$
b.
$(\frac{1}{4}x-1)-(\frac{5}{6}x+2)-(1-\frac{5}{8}x)=0$
$(\frac{1}{4}x-\frac{5}{6}x+\frac{5}{8}x)-(1+2+1)=0$
$\frac{1}{24}x-4=0$
$x=4: \frac{1}{24}=96$
a.=> \(\frac{\left(\frac{1}{3}\right).x}{\frac{2}{3}}=\frac{\frac{7}{4}}{\frac{2}{5}}\)
=> \(\frac{1}{3}.x=\frac{7}{4}.\frac{2}{3}:\frac{2}{5}\)
=>\(\frac{1}{3}.x=\frac{35}{12}\)
=> x\(=\frac{35}{12}:\frac{1}{3}\)
Vậy x=\(\frac{35}{4}\).
b. => \(\frac{4,5}{0,3}=\frac{2,25}{0,1.x}\)
=>\(0,1.x=\frac{2,25.0,3}{4,5}\)
=>\(0,1.x=0,15\)
=>\(x=0,15:0,1\)
Vậy x=1,5
c. =>\(\frac{8}{\frac{1}{4}.x}=\frac{2}{0,02}\)
=>\(\frac{1}{4}.x=\frac{8.0,02}{2}\)
=>\(\frac{1}{4}.x=0,08\)
=>\(x=0,08:\frac{1}{4}\)
Vậy x=0,32.
d. =>\(\frac{3}{\frac{9}{4}}=\frac{\frac{3}{4}}{6.x}\)
=>\(3.6x=\frac{9}{4}.\frac{3}{4}\)
=>\(18x=\frac{27}{16}\)
=>\(x=\frac{27}{16}:18\)
Vậy x=\(\frac{3}{32}\)
a) \(\left(\frac{1}{3}.x\right):\frac{2}{3}=\frac{7}{4}:\frac{2}{5}\)
\(\left(\frac{1}{3}.x\right):\frac{2}{3}=\frac{35}{8}\)
\(\Rightarrow\frac{1}{3}.x=\frac{35}{8}.\frac{2}{3}\)
\(\Rightarrow\frac{1}{3}.x=\frac{35}{12}\)
\(\Rightarrow x=\frac{35}{12}:\frac{1}{3}\)
\(\Rightarrow x=\frac{35}{4}\)
Vậy \(x=\frac{35}{4}\)
(x + 0,1).(x - 2/7) = 0
x + 0,1 = 0 hoặc x - 2/7 = 0
*) x + 0,1 = 0
x = 0 - 0,1
x = -0,1
*) x - 2/7 = 0
x = 0 + 2/7
x = 2/7
Vậy x = -0,1; x = 2/7
\(\left(0,1\right)^4.\left(0,1\right)^2.10^4\)
\(=\frac{1}{10^4}.10^4.\frac{1}{10^2}\)
\(=1.\frac{1}{100}=\frac{1}{100}\)
Ta có :
(0,1)4 x (0,1)2 x 104
=( 0,1 x 10)4 x 0,01
= 14 x 0,01
= 0,01
a) 5/3 : 0,5 = 4/3 : 0,1 . x
10/3 = 40/3.x
x = 1/4
b) 1816 = 2x.332
216.(32)16 = 2x .332
216.332 = 2x.332
=> 216 = 2.x
=> x = 216 : 2 = 215
\(a.\frac{5}{3}:0,5=\frac{4}{3}:0,1\times x\)
\(\Leftrightarrow\frac{4}{3}:0,1\times x=\frac{10}{3}\)
\(\frac{4}{3}:0,1=\frac{10}{3}:x\)
\(\frac{40}{3}=\frac{10}{3}:x\)
\(\Rightarrow x=\frac{10}{3}:\frac{40}{3}\)
\(x=\frac{1}{4}\)
\(b.18^{16}=2x.3^{32}\)
\(2^{16}.\left(3^{16}\right)^2=2x.3^{32}\)
\(2^{16}.\left(3^{32}\right)=2x.3^{32}\)
\(2^{16}=2x\)
\(\Rightarrow x=2^{16}:2\)
\(x=2^{15}\)
\(\)
a)4,5:0,3=2,25:(0,1.x)
2,25:(0,1.x)=15
0,1.x=0,15
x=0,15:0,1
x=1,5
Vậy x=1,5
b)8:\(\left(\frac{1}{4}.x\right)\)=2:0,02
8:\(\left(\frac{1}{4}.x\right)\)=100
\(\left(\frac{1}{4}.x\right)\)=\(\frac{8}{100}\)
x=\(\frac{8}{100}\):\(\frac{1}{4}\)
x=\(\frac{8}{25}\)
Vậy x=\(\frac{8}{25}\)
c)\(3:2\frac{1}{4}=\frac{3}{4}:\left(6.x\right)\)
\(\frac{3}{4}:\left(6.x\right)=\frac{4}{3}\)
6.x=\(\frac{3}{4}:\frac{4}{3}\)
6.x=\(\frac{9}{16}\)
x=\(\frac{9}{16}\):6
x=\(\frac{3}{32}\)
Vậy x=\(\frac{3}{32}\)
a.
\(4,5\div0,3=2,25\div\left(0,1\times x\right)\)
\(2,25\div\left(0,1\times x\right)=15\)
\(0,1\times x=\frac{2,25}{15}\)
\(0,1\times x=0,15\)
\(x=\frac{0,15}{0,1}\)
\(x=1,5\)
b.
\(8\div\left(\frac{1}{4}\times x\right)=2\div0,02\)
\(8\div\left(\frac{1}{4}\times x\right)=100\)
\(\frac{1}{4}\times x=\frac{8}{100}\)
\(\frac{1}{4}\times x=\frac{2}{25}\)
\(x=\frac{2}{25}\div\frac{1}{4}\)
\(x=\frac{2}{25}\times4\)
\(x=\frac{8}{25}\)
c.
\(3\div2^1_4=\frac{3}{4}\div\left(6\times x\right)\)
\(\frac{3}{4}\div\left(6\times x\right)=3\div2,25\)
\(\frac{3}{4}\div\left(6\times x\right)=\frac{4}{3}\)
\(6\times x=\frac{3}{4}\div\frac{4}{3}\)
\(6\times x=\frac{3}{4}\times\frac{3}{4}\)
\(6\times x=\frac{9}{16}\)
\(x=\frac{9}{16}\div6\)
\(x=\frac{9}{16}\times\frac{1}{6}\)
\(x=\frac{3}{32}\)
\(-2,\left(6\right).x=0,1\left(6\right)\\ \Leftrightarrow x=0,1\left(6\right):-2,\left(6\right)\\ \Leftrightarrow x=\left[0,1+\dfrac{6.1}{99}\right]:\left[-2-\dfrac{6.1}{9}\right]\\ \Leftrightarrow x=-\dfrac{53}{880}\)
(x - 0,1)⁶ = (x - 0,1)⁴
(x - 0,1)⁶ - (x - 0,1)⁴ = 0
(x - 0,1)⁴.[(x - 0,1)² - 1] = 0
(x - 0,1)⁴ = 0 hoặc (x - 0,1)² - 1 = 0
*) (x - 0,1)⁴ = 0
x - 0,1 = 0
x = 0,1
*) (x - 0,1)² - 1= 0
(x - 0,1)² = 1
x - 0,1 = 1 hoặc x - 0,1 = -1
**) x - 0,1 = 1
x = 1 + 0,1
x = 1,1
*) x - 0,1 = -1
x = -1 + 0,1
x = -0,9
Vậy x = -0,9; x = 0,1; x = 1,1