(7x - 11)³ = 2⁵.5² + 200

<=> (7x - 11)³  = 32.25 + 200

<=> (7x - 11)³ = 800 + 200

<=> (7x - 11)³ = 1000

<=> (7x - 11)³ = 10³

<=> 7x - 11 = 10

<=> 7x = 21

<=> x = 3 

\(\left(7x-11\right)^3=2^5\cdot5^2+200\cdot2023^0\\ \left(7x-11\right)^3=32\cdot25+200\cdot1\\ \left(7x-11\right)^3=1000\\ \left(7x-11\right)^3=10^3\\ 7x-11=10\\ 7x=21\\ x=\dfrac{21}{7}=3\)

Lời giải:

$(7x-11)^3=2^5.5^2+200.2023^0=32.25+200=1000=10^3$

$\Rightarrow 7x-11=10$

$\Rightarrow 7x=21$

$\Rightarrow x=3$

\(\left(7x-11\right)^3=25.5^2+200\)

\(\left(7x-11\right)^3=25.25+200\)

\(\left(7x-11\right)^3=625+200\)

\(\left(7x-11\right)^3=825\)

Hình như đề sai rồi bạn ơi

so sánh 15¹⁵ và 81³ .125⁵

1: \(6x^2-8=40\)

\(\Leftrightarrow x^2=8\)

hay \(x\in\left\{2\sqrt{2};-2\sqrt{2}\right\}\)

1)

a) 2x + 5 = 3⁴ : 3²

2x + 5 = 3²

2x + 5 = 9

2x = 9 - 5

2x = 4

x = 4 : 2

x = 2

b) (3x - 24).73 = 2.74

(3x - 24).73 = 148

3x - 24 = 148/73

3x = 148/73 + 24

3x = 1900/73

x = 1900/73 : 3

x = 1900/219

c) [3.(42 - x)] + 15 = 23.3

126 - 3x + 15 = 69

141 - 3x = 69

3x = 141 - 69

3x = 72

x = 72 : 3

x = 24

d) 126 + (132 - x) = 300

132 - x = 300 - 126

132 - x = 174

x = 132 - 174

x = -42

2)

a) 120 - (x + 55) = 60

x + 55 = 120 - 60

x + 155 = 60

x = 60 - 55

x = 5

b) (7x - 11).3 = 25.52 + 200

(7x - 11).3 = 1500

7x - 11 = 1500 : 3

7x - 11 = 500

7x = 500 + 11

7x = 511

x = 511 : 7

x = 73

c) 2x + 2x + 4 = 544

4x = 544 - 4

4x = 540

x = 540 : 4

x = 135

Ta có: \(\left(7x-11\right)^3=2^5+5^2+200=1000\)

\(\Rightarrow\left(7x-11\right)^3=10^3\)

\(\Rightarrow7x-11=10\)

\(\Rightarrow7x=21\)

\(\Rightarrow x=3\)

Trả lời:

\(\left(7x-11\right)^3=2^5.5^2+200\)

\(\Leftrightarrow\left(7x-11\right)^3=32.25+200\)

\(\Leftrightarrow\left(7x-11\right)^3=800+200\)

\(\Leftrightarrow\left(7x-11\right)^3=1000\)

\(\Leftrightarrow7x-11=10\)

\(\Leftrightarrow7x=21\)

\(\Leftrightarrow x=3\)

Vậy\(x=3\)

Hok tốt!

Good girl

a, 7*(x-3) + 4 = 18

<=> 7*(x+3) = 14

<=> x+3=2

<=> x= -1

b, ( 7x - 11)³ =825

 <=> 7x - 11=\(\sqrt[3]{825}\) 

<=> x=\(\frac{\sqrt[3]{825}+11}{7}\) (loại)

$\dfrac{2}{3}$

( 7x - 11 )³ = 32 . 25 + 200

( 7x - 11 )³ = 800 + 200

( 7x - 11 )³ = 1000

( 7x - 11 )³ = 10³

=> 7x - 11 = 10

7x = 10 + 11

7x = 21

x = 21 : 7

x = 3

=>(7x-11)^3=800+200=1000=10^3

=>7x-11=10

=>7x=21=>x=3

 Vậy x=3

\(\left(7x-11\right)^3=2^5.5^2+200\)

\(\left(7x-11\right)^3=800+200\)

\(\left(7x-11\right)^3=1000\)

\(\left(7x-11\right)^3=10^3\)

\(\left(7x-11\right)=10\)

\(7x=21\)

\(x=3\)