\((x+1)+(x+2)+(x+3)+...+(x+100)=570\)

\(\Rightarrow(x+x+x+...+x)+(1+2+3+...+100)=570\)

\(\Rightarrow100x+\frac{(1+100)\cdot100}{2}=570\)

\(\Rightarrow100x+5050=570\)

\(\Rightarrow100x=570-5050\)

\(\Rightarrow100x=-4480\)

\(\Rightarrow x=-44,8\)

P/S : Làm bừa :> Hoq chắc 

\(\left(x+1\right)+\left(x+2\right)+...+\left(x+100\right)=570\)

\(\left(x+x+x+...+x\right)+\left(1+2+...+100\right)=570\)

\(100x+5050=570\)

\(100x=-4480\)

\(x=-44,8\)

=> (x+1+x+100) x 100 : 2 = 5550

=> (2x+101) x 100 = 5550 x 2 = 11100

=> 2x+101 = 11100 + 100 = 111

=> 2x = 111-101 = 10

=> x = 10 : 2 = 5

k mk nha

(x+1)+(x+2)+(x+3)+...+(x+100)=5550

=> (x+x+x+...+x)+...+(1+2+3+...+100)=5550

=> 100x+5050=5550

100x=5550-5050

100x=500

x=500:100

x=5

=100.x + (1+2+3+....+100 )

=100.x +100.101/2

=>100x +101 + 50 =5750

100x =5750 -5050 =700

=>700 :100 = 7

Vậy X = 7

[x+1]+[x+2]+...+[x+100]=5750

[1+2+...+100].x=5750

Số các số hạng:

(100-1):1+1=100 số

=>có 100 thừa số x

Tổng trên là:

(1+100)x100:2=5050

=>x.100=5750-5050

=>x.100=700

=>x=700:100

=>x=7

Vậy x = 7

(x+1)+(x+2)+(x+3)+....+(x+100)=5750

100x+(1+2+3+...+100)=5750

100x+5050=5750

100x=5750-5050

100x=700

x=700:100

x=7

<=>(x+x+x..+x)+(1+2+...+100)=5750

=>100x+5050=5750

=>100x=700

=>x=700:100

=>x=7

100^(x-3).(x-2) = 1

=> 100^(x-3).(x-2) = 100⁰

=> (x - 3)(x - 2) = 0 

=> x - 3 = 0 => x = 3

hoặc x - 2 = 0 => x = 2

Vậy x = 3; x = 2

50 x {x+1} = 25

{x+1} = 50 : 2

{x+1} = 2

x = 2-1=1

\(\frac{100}{2}\left(x+1\right)=25\)

\(=>50\left(x+1\right)=25\)

\(=>x+1=\frac{25}{50}\)

\(=>x+1=\frac{1}{2}\)

\(=>x=\frac{1}{2}-1\)

\(=>x=-\frac{1}{2}\)

mình làm cách cấp 1 nhé

(x+1)+(x+2)+(x+3)+........+(x+100)=5750

=> (x+x+...+x)+(1+2+3+...+100)=5750

=> (x.100)+(1+100).100:2=5750

=> (x.100)+5050=5750

=>x.100=5750-5050

=>x.100=700

=>x       =700:100

x       = 7

 (x+1)+(x+2)+(x+3)+...+(x+100)=5750 
= 100x + (1+2+...+100) = 5750 
=> x = [ 5750 - (1+2+...+100) ]/100 
=> x = (5750 - 5050) / 100 
=> x = 7

(x + 1) + (x + 2) + (x + 3) + ...... + (x + 100) = 5750

x + 1 + x + 2 + x + 3 + ..... + x + 100 = 5750

100x + (1 + 2 + 3 + ..... + 100) = 5750

Áp dụng công thức tình dãy số ta có :

1 + 2 + 3 + .... + 100 = 5050

=> 100x + 5050 = 5750

=> 100x = 5750 - 5050

=> 100x = 700

=> x = 7