0,4 :x = x: 0.9

=> x.x = 0,4 . 0,9

=> x² = 0,36

=> x= 0,6 hoặc x= -0,6

vậy x=  0,6 hoặc x= -0,6

\(\frac{0.4}{x}=\frac{x}{0.9}=>x^2=0.4\times0.9=\frac{9}{25}\)

\(=>x=\frac{3}{5}\)

0,4 : x = x : 0,9

= > x.x = 0,4.0,9

= > x² = 0,36

= > x = 0,6 hoặc x = -0,6

Vậy x = 0,6 hay x = -0,6

\(0,4:x=x:0,9\)

\(\Rightarrow x^2=0,4.0,9=0,36\)

=>\(x=\pm0,6\)

0,4 : x = x : 0,9 

(=) x² = 0,4 x 0,9 

(=) x² = 0,36

(=) x = \(\sqrt{0,36}\)

(=) x = { -6 ; 6 }

nha ban

\(\frac{0,4}{x}=\frac{x}{0,9}\Rightarrow x^2=0,4\times0,9=0,36\Rightarrow x=0,6\)hoặc x = -0,6

Vậy x = {0,6 ; -0,6}

Giải:

\(0,4:x=x:0,9\)

\(\Leftrightarrow\dfrac{0,4}{x}=\dfrac{x}{0,9}\)

\(\Leftrightarrow x.x=0,4.0,9\)

\(\Leftrightarrow x^2=0,36\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0,6\\x=-0,6\end{matrix}\right.\)

Vậy ...

\(\dfrac{2}{\dfrac{5}{x}}=\dfrac{x}{\dfrac{9}{10}}\)\(\Rightarrow\)x^2=\(\dfrac{2}{5}.\dfrac{9}{10}=\dfrac{9}{25}\)

Nên x=\(\dfrac{3}{5}\)hoặc x=\(\dfrac{-3}{5}\)

Bài 1: 

a) Ta có: \(\dfrac{17}{6}-x\left(x-\dfrac{7}{6}\right)=\dfrac{7}{4}\)

\(\Leftrightarrow\dfrac{17}{6}-x^2+\dfrac{7}{6}x-\dfrac{7}{4}=0\)

\(\Leftrightarrow-x^2+\dfrac{7}{6}x+\dfrac{13}{12}=0\)

\(\Leftrightarrow-12x^2+14x+13=0\)

\(\Delta=14^2-4\cdot\left(-12\right)\cdot13=196+624=820\)

Vì Δ>0 nên phương trình có hai nghiệm phân biệt là:

\(\left\{{}\begin{matrix}x_1=\dfrac{14-2\sqrt{205}}{-24}=\dfrac{-7+\sqrt{205}}{12}\\x_2=\dfrac{14+2\sqrt{2015}}{-24}=\dfrac{-7-\sqrt{205}}{12}\end{matrix}\right.\)

b) Ta có: \(\dfrac{3}{35}-\left(\dfrac{3}{5}-x\right)=\dfrac{2}{7}\)

\(\Leftrightarrow\dfrac{3}{5}-x=\dfrac{3}{35}-\dfrac{10}{35}=\dfrac{-7}{35}=\dfrac{-1}{5}\)

hay \(x=\dfrac{3}{5}-\dfrac{-1}{5}=\dfrac{3}{5}+\dfrac{1}{5}=\dfrac{4}{5}\)

ai giúp mik vs

Ta có: \(0,\left(3\right)+\frac{31}{3}+0,4\left(2\right)=\frac{3}{9}+\frac{31}{3}+\frac{42-4}{90}=\frac{1}{3}+\frac{31}{3}+\frac{19}{45}=\frac{32}{3}+\frac{19}{45}=\frac{499}{45}.\)

\(\frac{4}{9}+0,\left(13\right)=\frac{4}{9}+\frac{13}{99}=\frac{44}{99}+\frac{13}{99}=\frac{57}{99}=\frac{19}{33}\)

\(0,\left(37\right).x\Rightarrow\frac{37}{99}.x=1\)

\(\Rightarrow x=1:\frac{37}{99}=\frac{99}{37}\)

\(0,\left(26\right).x=1,2\left(31\right)\)

\(\Rightarrow\frac{26}{99}.x=\frac{1219}{990}\)

\(\Rightarrow x=\frac{1219}{990}:\frac{26}{99}=\frac{1219}{260}\)

a) 7/x-1=x+1/9
7/x-x-1=1/9
7/x-x=1/9+1
7/x-x=10/9
còn lại thì bạn tự tính nhé
câu b làm tương tự

tick cho mik nha

b: \(\Leftrightarrow3x-36-5x-175+x-15=0\)

\(\Leftrightarrow-x-226=0\)

hay x=-226

a) (x - 6)² = 9

\(\Rightarrow\left[{}\begin{matrix}x-6=3\\x-6=-3\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=9\\x=3\end{matrix}\right.\)

b) \(\left|x\right|=3\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-3\end{matrix}\right.\)

ok