Ta có :

|x+2|+|x+3|=x

Mà : |x+2| lớn hơn hoặc bằng 0

|x+3| lớn hơn hoặc bằng 0

=> |x+2|+|x+3| lớn hơn  hoặc bằng 0

=> x lớn hơn hoặc bằng 0

=> x+2+x+3=x

=> 2x+5=x

=> 2x= x-5

=> x= (x-5)/2

\(\left|x+2\right|+\left|x+3\right|=x\)

\(\Rightarrow x-\left(2+3\right)=x\Leftrightarrow x-5=x\)

\(\Rightarrow x=\frac{x-5}{x}\)

\(\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-...+\frac{1}{19}-\frac{1}{21}\right).462-\left[2,04:\left(x+1,05\right)\right]:0,12=19\)

\(\left(\frac{1}{11}-\frac{1}{21}\right).462-\left[2,04:\left(x+1,05\right)\right]:0,12=19\)

\(\frac{10}{231}.462-\left[2,04:\left(x+1,05\right)\right]:0,12=19\)

\(20-\left[2,04:\left(x+1,05\right)\right]:0,12=19\)

\(\left[2,04:\left(x+1,05\right)\right]:0,12=20-19=1\)

\(2,04:\left(x+1,05\right)=0,12\)

\(x+1,05=2,04:0,12\)

x+1,05=17

x=17-1,05=15,95

cảm ơn bn nha

a.\(\Rightarrow\left(\frac{3}{5}+x\right):\frac{2}{7}=\frac{3}{35}-\frac{2}{7}\)

\(\Rightarrow\left(\frac{3}{5}+x\right):\frac{2}{7}=-\frac{1}{5}\)

\(\Rightarrow\frac{3}{5}+x=-\frac{1}{5}.\frac{2}{7}\)

\(\Rightarrow\frac{3}{5}+x=-\frac{2}{35}\)

\(\Rightarrow x=-\frac{2}{35}-\frac{3}{5}\)

Vậy \(x=-\frac{23}{35}\).

b. => 5x-1=0                hoặc 2x-1/3=0

=> 5x=1                       hoặc 2x=1/3

=> x=1/5                      hoặc x=1/6

c. \(\Rightarrow\frac{1}{7}:x=\frac{3}{14}-\frac{3}{7}\)

\(\Rightarrow\frac{1}{7}:x=-\frac{3}{14}\)

\(\Rightarrow x=\frac{1}{7}:\left(-\frac{3}{14}\right)\)

Vậy \(x=\frac{-2}{3}\).

- (-30) - (-x) = - (+13)

30 + x = -13

        x = -13 - 30

        x = -43

-(-30)-(-x)=-(-13)

30+x=13

=>x=13-30

=>x=-17

Ta có : \(\left(\frac{2}{11.13}+\frac{2}{13.15}+...+\frac{2}{19.21}\right)642-\left[0,04:\left(x+1,05\right)\right]:0,12=19\)

=> \(\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+...+\frac{1}{19}-\frac{1}{21}\right)642-0,04:\left(x+1,05\right):0,12=19\)

=> 

(nãy bấm nhầm) tiếp nà :

=> \(\left(\frac{1}{11}-\frac{1}{21}\right)462-0,04:\left(x+1,05\right):0,12=19\)

=> \(\frac{10}{231}.462-0,04:\left(x+1,05\right):0,12=19\)

=> \(20-0,04:\left(x+1,05\right):0,12=19\)

=> 0,04 : (x + 1,05) : 0,12 = 1

=> 0,04 : (x + 1,05) = 0,12

=> \(x+1,05=\frac{1}{3}\) 

=> \(x=\frac{1}{3}-1,05=...\)

a) \(\left(x+1\right)-\frac{x+1}{3}=\frac{5\left(x+1\right)-1}{6}\)

\(\Leftrightarrow6\left(x+1\right)-2\left(x+1\right)=5\left(x+1\right)-1\)

\(\Leftrightarrow6x+6-2x-2=5x+5-1\)

\(\Leftrightarrow6x-2x-5x=5-1-6+2\)

\(\Leftrightarrow-x=0\)

\(\Leftrightarrow x=0\)

b) \(\left(1-x\right)^2+\left(x+2\right)^2=2x\left(x-3\right)-7\)

\(\Leftrightarrow1-2x+x^2+x^2+4x+4=2x^2-6x-7\)

\(\Leftrightarrow2x^2+2x+5=2x^2-6x-7\)

\(\Leftrightarrow2x+6x=-7-5\)

\(\Leftrightarrow8x=-12\)

\(\Leftrightarrow x=-\frac{3}{2}\)

c) \(2+\frac{x-2}{2}-\frac{2x-4}{3}-\frac{5}{6}\left(2-x\right)=0\)

\(\Leftrightarrow2+\frac{x}{2}-1-\frac{2}{3}x+\frac{4}{3}-\frac{5}{3}+\frac{5}{6}x=0\)

\(\Leftrightarrow\frac{x}{2}-\frac{2}{3}x+\frac{5}{6}x=-2+1-\frac{4}{3}+\frac{5}{3}\)

\(\Leftrightarrow\frac{2}{3}x=-\frac{2}{3}\)

\(\Leftrightarrow x=-1\)