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$(x+45):27=12$
$x+45=12\times27$
$x+45=324$
$x=324-45$
$x=279$
Lời giải:
a.
$x-\frac{1}{2}=\frac{2}{3}$
$x=\frac{2}{3}+\frac{1}{2}=\frac{7}{6}$
b.
$x\times \frac{5}{6}=\frac{1}{2}$
$x=\frac{1}{2}: \frac{5}{6}=\frac{3}{5}$
c.
$x:\frac{2}{5}=10$
$x=10\times \frac{2}{5}=4$
d.
$\frac{7}{5}-x=\frac{12}{10}$
$x=\frac{7}{5}-\frac{12}{10}=\frac{1}{5}$
a, => x-12 = 0
=> x=12
b, => 27-x =1
=> x= 27-1 -26
c, => 2x = 69(4-2) =69.2
=> x=69
d, => x-12=0
=> x=12
a) (x - 12) . 105 = 0
=> x - 12 = 0
=> x = 12
b) 47 . (27 - x) = 47
=> 27 - x = 1
=> x = 27 - 1 = 26
c) 2x + 69 . 2 = 69 . 4
=> 2x = 69 . 4 - 69 . 2
=> 2x = 69 . (4 - 2) = 69 . 2
=> x = 69 . 2 : 2
=> x = 69
d) 2x - 12 - x = 0
=> x - 12 = 0
=> x = 12
\(\left\{\left[27\times11-\left(x+12\right)\times8\right]\times3-79\right\}\div5=100\)
\(\left[27\times11-\left(x+12\right)\times8\right]\times3-79=100\times5\)
\(\left[27\times11-\left(x+12\right)\times8\right]\times3-79=500\)
\(\left[27\times11-\left(x+12\right)\times8\right]\times3=500+79\)
\(\left[27\times11-\left(x+12\right)\times8\right]\times3=579\)
\(27\times11-\left(x+12\right)\times8=579:3\)
\(27\times11-\left(x+12\right)\times8=193\)
\(297-\left(x+12\right)\times8=193\)
\(\left(x+12\right)\times8=297-193\)
\(\left(x+12\right)\times8=104\)
\(x+12=104:8\)
\(x+12=13\)
\(x=13-12\)
\(x=1\)
\(k\)\(dung\)\(cho\)\(minh\)\(nhe!\)
\(\frac{3}{4}.\frac{12}{7}+x=\frac{5}{2}\)
\(\frac{3.3}{1.7}+x=\frac{5}{2}\)
\(\frac{9}{7}+x=\frac{5}{2}\)
\(x=\frac{5}{2}-\frac{9}{7}\)
\(x=\frac{35}{14}-\frac{18}{14}\)
\(x=\frac{17}{14}\)
a,12,5-x=4,27
x=12,5-4,27
x=8,23
vay x=8,23
b,18,2:x=5,6
x=18,2:5,6
x=3,25
vay x=3,25
Tìm y:
\(\frac{Y}{15}=\frac{2}{5}\) => y = 15 x 2/ 5 = 6
Vậy y = 6
tk ủng hộ giúp mk nha!!!!!!!!!
\(x:12=x:27\Rightarrow\dfrac{x}{12}=\dfrac{x}{27}\Rightarrow x\in\varnothing\)